15:27 doesnt inverse sine mean that the only acceptable values are from the right half of the unit circle? therefore, wouldn't 2pi/3 not be a solution?
yes but this isnt an inverse sine problem. arcsin will only take values from [-pi/2, pi/2] but if it is something like sin(x) = √3/2, then this includes both pi/3 and 2pi/3 since sin(x) itself doesnt have those restrictions.
In the last problem, could you explain why x = - (root(15))/(5pi) isn't an answer? I got this by using 5pi/3 instead of pi/3 so when I got to the tangent section the sin value was negative resulting in a negative answer.
You can't use 5pi/3 because even though that would be a solution, I was taught for inverse cosine graphs you only look for solutions in the top 2 quadrants (quad I & II) so you only get one answer
I hope that makes sense and helps, I am not the best explainer. For inverse tan and inverse sin, however, you use Quad I and Quad IV to find that singular answer
For the last problem part c would that one have an infinite number of possible answers as well so you would need to add the 2pi*n as well or does this one only have the one solution?
Even when you change an inverse trig into trig try to think abt the graph. It still has its limitations of -pi/2 to pi/2 so the answer will be limited as well
Hi sir! Can you explain why you did not add 2pi*n to the last problem? I understand that it is an inverse trig function, but what is the rule for inverse trig functions and multiple values of x?
X is not an angle. That’s why. Try to think of another value for x that makes original equation true. Or add 2pi and see if that new answer works. It won’t
Hi sir! I wanted to ask if writing the domain limitations for the log rewriting questions or anything where the answer ends up being a fraction is a mandatory thing? Like if I don’t do it will I get no points? Thank you!
this frq cooked me, the frqs especially the 4th were so hard 😭
@@realleochang fr
@@realleochang yep
8:40 is the (x+1) supposed to be (x+1)^4
you are right! I Missed that. I will fix and adjust! Thanks!
that’s what i was thinking lol
Was about to mention that lol
The exam is 1hr away… Either we’re cooked or we cook 👨🍳
I’m with u bruh, it’s over for us 😭
we might be cooked
godspeed soldiers
HELPPPOP
Understood.
Exams in 30 min think I’m cooked
Same
Thank you so much for all your videos! They’ve been really helpful to me.
15:27 doesnt inverse sine mean that the only acceptable values are from the right half of the unit circle? therefore, wouldn't 2pi/3 not be a solution?
Did u end up figuring it out, Im wondering the same thing lol.
yes but this isnt an inverse sine problem. arcsin will only take values from [-pi/2, pi/2] but if it is something like sin(x) = √3/2, then this includes both pi/3 and 2pi/3 since sin(x) itself doesnt have those restrictions.
@@Noah-ko9cm just answered the question lmk if it helps
@@christian-vt2yo Appreciate it, unforunately I forgot to check youtube after I woke up lol
In the last problem, could you explain why x = - (root(15))/(5pi) isn't an answer? I got this by using 5pi/3 instead of pi/3 so when I got to the tangent section the sin value was negative resulting in a negative answer.
I thought the same thing
You can't use 5pi/3 because even though that would be a solution, I was taught for inverse cosine graphs you only look for solutions in the top 2 quadrants (quad I & II) so you only get one answer
I hope that makes sense and helps, I am not the best explainer. For inverse tan and inverse sin, however, you use Quad I and Quad IV to find that singular answer
Cosine inverse of 1/2 can only have one solution pi/3 based on the restrictions put on inverse cosine
This video explains it
Inverse Sine EXPLAINED!!! AP Precalculus Topic 3.9
th-cam.com/video/rfKM1eRXUmo/w-d-xo.html
For question 3 we can use fractions for the period or coordinates as well right
Yes fractions will be fine
In part B, when you were simplifying the logarithm into a single log, why did you not put the coefficient of 4 as an exponent?
I totally forgot. I’m the video description I corrected myself. Sorry!!
For the last problem part c would that one have an infinite number of possible answers as well so you would need to add the 2pi*n as well or does this one only have the one solution?
just the only solution since it is an inverse trig function
Even when you change an inverse trig into trig try to think abt the graph. It still has its limitations of -pi/2 to pi/2 so the answer will be limited as well
Hi sir! Can you explain why you did not add 2pi*n to the last problem? I understand that it is an inverse trig function, but what is the rule for inverse trig functions and multiple values of x?
X is not an angle. That’s why. Try to think of another value for x that makes original equation true. Or add 2pi and see if that new answer works. It won’t
bro fucked up his math at like 8:30 haha
For the first problem I simplified 79/3 to 26.333, do you think that still counts? might be a stupid question.
Should be fine. But it’s a no calculator section so fractions are fine
For part C do I need to provide both answers you circled? Or just one of those solutions showing the domain? Thanks
at 17:19 being the first example of a part C question
Hi sir! I wanted to ask if writing the domain limitations for the log rewriting questions or anything where the answer ends up being a fraction is a mandatory thing? Like if I don’t do it will I get no points? Thank you!
For what I have read and seen they will not be asking for the domains in these problems. Just asking to simply and rewrite
Thanks a much for clearing it up..my teacher has been giving me 0s because I didn’t put the domain limitation, only the right answer
exam in 2 hours chat
I think you forgot to add, "+ 2pi k" for the last question involving tangent
No there is only one answer since it is an inverse tangent function.
this eats