You dropped the sig figs and rounded to 1920, then used 1918.7 to further interpolate anyway, does this method of "nested" interpolation cause significant or measurable error?
Great question. When doing calculations, you do not want to round your answer until the very end, as there could be a difference in the outcome. But when reporting the answer, you need to use significant figures because in reality, you do not know the answer with more detail than that.
Here, we have interpolated first with respect to temperature and then with respect to pressure. Why can't we first interpolate with respect to pressure and then with respect to temperature?
Thanks for your question! It would equally valid to interpolate first with respect to pressure, followed by temperature. It was more convenient in this case to start with temperature since we had already found the enthalpy at 220 C, 0.01 MPa from the first part of the problem.
The following questions are based on the example taken from Borgnakke and Sonntag "Fundamentals of Thermodynamics" (pgs 181 - 182; eg. 4.9; 8th edition) - link: www.slideshare.net/AnglicaRivera1/fundamentals-of-thermodynamics-8th-edition-sonntag-borgnakke-van-wylen-1 1. For saturated steam at 300 kPa, the enthalpy (h_g) is 2725.30 kJ/ kg and NOT 2967.59 kJ/kg as noted in the example - please confirm.
@@LearnChemE sorry, you're right. I just misread a value. BTW, Why did you give out a significant figure 2920 instead of just leaving the value 2918. 3 there?
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thankyou😁helping a lot
This was very helpful...Thank you
Thank you
You made my day....Thanks!
hello, so if i have a super heated steam at a pressure that doesn't exist in the tables what do i do?
Did you found out yet?
Thanks ,😊😊,nice video ,it helps me a lot .Im expecting for more informative thermodynamics videos soon 🙏
But what does one do when the temperature is not given and neither is the pressure?
You dropped the sig figs and rounded to 1920, then used 1918.7 to further interpolate anyway, does this method of "nested" interpolation cause significant or measurable error?
Great question. When doing calculations, you do not want to round your answer until the very end, as there could be a difference in the outcome. But when reporting the answer, you need to use significant figures because in reality, you do not know the answer with more detail than that.
@@LearnChemE nice
this was perfect thank you
That’s perfect 👌 thank you 🙏
thank you so much, really helped meeee
Thankyou for this video ! You help me a lot :>
thank you, saved my exam. Watched this 3 hours before the paper, lol
am watching it now before a paper in the next two hours
thankyou so much :) you helped us a lot
excellent. works in even more applications too
What if you are given pressure and temperature that are not there in the table?
very helpful thank you so much
Thanks my guy!
appreciated . that"s very help in perfect time
Here, we have interpolated first with respect to temperature and then with respect to pressure. Why can't we first interpolate with respect to pressure and then with respect to temperature?
Thanks for your question! It would equally valid to interpolate first with respect to pressure, followed by temperature. It was more convenient in this case to start with temperature since we had already found the enthalpy at 220 C, 0.01 MPa from the first part of the problem.
Cool :) thanks - this helps a lot.
The following questions are based on the example taken from Borgnakke and Sonntag "Fundamentals of Thermodynamics" (pgs 181 - 182; eg. 4.9; 8th edition) - link: www.slideshare.net/AnglicaRivera1/fundamentals-of-thermodynamics-8th-edition-sonntag-borgnakke-van-wylen-1
1. For saturated steam at 300 kPa, the enthalpy (h_g) is 2725.30 kJ/ kg and NOT 2967.59 kJ/kg as noted in the example - please confirm.
How to use interpolation to find H and V, given P and S?
Where could we find the steam table in perry's?
This seems to be wrong. What you do first the first interpolation is 2879.6+((2977.4-2879.6)/(250-200))*(220-200)= 2918.72
thanks , crystal clear
it is useful for me thank you.
Excellent.Thanks
Thank you so much!
What if the given is only Temperature and Enthalpy, but is a Superheated since the given enthalpy is higher than saturated enthalpy of vapor?
Thanks, fantastic help
Amazing
This is super!
goated video
thank you so much
4 hours berfore the exam I just hope that I pass it
mine 45 mins 😂
@kblackgg Hope you pass it too, btw I passed the subject with BC grade 😂
Thanks sir
Thank u sir
thanks
Anyone think there's an error in calculation for the last value?
Can you please be more specific? It looks correct to me, but I'd love to know why you think there is a problem.
@@LearnChemE sorry, you're right. I just misread a value. BTW, Why did you give out a significant figure 2920 instead of just leaving the value 2918. 3 there?
Thmku bhai jaan
thanx for the help...appreciated