FEA 27: Isoparametric Element Example

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  • เผยแพร่เมื่อ 21 พ.ย. 2024
  • Video showing the derivation of the [B] matrix for a non-rectangular isoparametric bilinear quadrilateral element.

ความคิดเห็น • 8

  • @brainblader2
    @brainblader2 3 ปีที่แล้ว +1

    Great video, it actually helped me out tons.
    But beware that there is an error in dN3/dx @10:48 and is further complicated @11:11 when dN3/dx is plugged inside [B]. If you take both equations and evaluate them, you will see they yield different results.
    To clarify, dN3/dx itself is wrong @10:48 and when plugged in [B] is a whole different equation altogether.
    Overall, excellent video. Liked

    • @peterelliotpeter
      @peterelliotpeter ปีที่แล้ว

      Thanks for pointing this out. For anyone wondering, the numerator should be 2t-s+1.

  • @MrsHeoU
    @MrsHeoU 4 ปีที่แล้ว

    nicely done! FEM is quite hard to grab, but u did well in explanation!

  • @lazer2405
    @lazer2405 5 ปีที่แล้ว

    This was fantastic! I'm doing a class project and this was the portion I really needed help with. I'm going to use this method, but I did have one question related to an example in my text: Nam Ho Kim et al. 2009, example 6.10 b. They refers to the B matrix as [B(si,tj)] in their stiffness matrix calculation and don't appear to convert it to x, y coordinates. Are they somehow not converting the B to x,y coordinates and leaving it in s,t coordinates to find the stiffness matrix? Is that something you can do and then convert in the final stiffness matrix?

  • @carbon273
    @carbon273 3 ปีที่แล้ว

    Why is there a 2 in the numerator of the coeeficent of jacobian determinant? There should be an 8 there no?

  • @EddieVBlueIsland
    @EddieVBlueIsland 5 ปีที่แล้ว +1

    @ 7:10 Second line, second term should be dy/dt = 1/4* (5+s) not dx/dt? - BTW nicely done.

  • @minh-tienle2672
    @minh-tienle2672 5 ปีที่แล้ว +1

    Why N1=(1/4)*(1-s)(1-t)? can you explain?

    • @longyang5598
      @longyang5598 4 ปีที่แล้ว

      It is a property of shape function, where the value of N1 when the coordinate of point 1 is (s,t)=(-1,-1) is N1=(1/4)*(1-s)(1-t)=N1=(1/4)*(1-(-1))(1-(-1))=1.
      And N1 is zero at ALL other three points.