Thermodynamics - 3-5 Pure substances - saturated liquid vapor mixture example 2
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- เผยแพร่เมื่อ 29 ม.ค. 2025
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Super Helpful, thank you very much! Will be checking out your other playlists as well
My teacher doesn’t teach this lesson so I’m browsing your lecture sir to understand it
total enthalpy = specific enthalpy x mass
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Hey, i have a question in my mind; why didn't we use our calculated spesific volume value while calculating the quality (at 07:53)? BTW great course, thx for everything Sir!
I think that’s what I did? I used the specific volume that we calculated = vf + (x)vfg to solve for x
@@engineeringdeciphered i mean why did we use value from table rather then 0.02m3/kg? Why didn’t our vf value become 0.02?
The vf value is the specific volume of a saturated liquid, and ours is not a sat liq, ours is a mixture. So we plug in our v value as “v” and the sat liq value as “vf” and then vfg is vg - vf.
Does that make sense?
you are genious
H = mh 12:00
when i clicked the video i didnt expect to fully understand the solutions but wow i was wrong
hi dr, if the temperature and pressure of liquid-vapor mixture are provided together, which table A4 or A5 is more preferable for us to refer?
You can do either! I like to go to A5 and the if my temperature is higher than the tsat for that pressure- then I know it’s superheated. Your other option is going to A4 and if your given pressure is lower than the psat for that temp- then you know it’s superheated. Either table should point you in the right direction!
thank you soo much
thank you
2:09
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Quality ratio of masses, not ratio of volume
The v=0.02m3/kg is larger than vf. How is it between?
vf=0.0007435 m3/kg and vg=0.1229. The specific volume of the mixture is v=0.02m3/kg. So the specific volume of our liquid falls between the specific volume of a sat liquid (vf) and a sat vapor (vg). So in simpler terms vf< v