Find the Amount of Excess Reactant (+ Example)

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  • เผยแพร่เมื่อ 23 ส.ค. 2024
  • How much of the EXCESS reactant is left over?
    * Find the limiting reactant. The OTHER reactants are in excess.
    * Use mole ratio to see how much of the excess reactant is used up
    * Subtract that from the original amount of excess reactant

ความคิดเห็น • 30

  • @normalhumanbeing6066
    @normalhumanbeing6066 4 หลายเดือนก่อน +17

    This video has changed my life. My whole outlook on everything that exists in this world, in fact even in the entire universe. I can never look at anything I know the same way ever again. This video represents emotions most humans could never comprehend. But I can. Thanks to this video I have been awakened to many things previously thought unimaginable. Thank you.

    • @chemistNATE
      @chemistNATE  4 หลายเดือนก่อน +4

      Your comment changed my life.

    • @idkdikdidkd
      @idkdikdidkd 3 หลายเดือนก่อน

      bot or what

  • @particleex6428
    @particleex6428 5 หลายเดือนก่อน +4

    Your video changed my life. I'm so glad that you make videos like these, I would not be alive otherwise. I hope your channel flourishes and you never need to work another day in your life
    (from @Orion)

  • @cucumberboi945
    @cucumberboi945 2 หลายเดือนก่อน

    OMG thank you so much watched three vids so far, with at least an hour of work, and this 5 min vid helped more than anything.

  • @neeuqollav2224
    @neeuqollav2224 20 วันที่ผ่านมา

    Bro...... What the heck! You made the formula looks so easier!
    Calculating moles was a heck of a ride, not until I found different video giving the simplest formula.
    Why can't we have this simple formulas instead of making a long and complicated one?

  • @ArnavThakur-dq8jl
    @ArnavThakur-dq8jl หลายเดือนก่อน +1

    This was really helpful bro
    Hats off

  • @thingsb4sleep
    @thingsb4sleep 5 หลายเดือนก่อน +3

    you saved my life, thank you so much

  • @GodSahil
    @GodSahil ปีที่แล้ว +5

    Great video!

  • @southafricannewsroom
    @southafricannewsroom ปีที่แล้ว +4

    Please make another video about this 5opic

  • @nolansebring6786
    @nolansebring6786 3 หลายเดือนก่อน +1

    Does this work for problems other than finding just grams? Such as finding the amount of moles?

  • @atomicshards
    @atomicshards 5 หลายเดือนก่อน

    Very grateful for this clear explanation, thank you

  • @birbhadrajha3988
    @birbhadrajha3988 9 หลายเดือนก่อน +2

    Can you share where to find your print out of periodic table please

  • @g3jusfly497
    @g3jusfly497 6 หลายเดือนก่อน +34

    this still makes no sense

    • @aishahvora
      @aishahvora 5 หลายเดือนก่อน +5

      ur so real

    • @wh1681
      @wh1681 3 หลายเดือนก่อน

      I’d pack you in a fight

    • @arpitapanchal6129
      @arpitapanchal6129 3 หลายเดือนก่อน

      Are u dumb bruh?!

    • @M.i192
      @M.i192 3 หลายเดือนก่อน

      😂😂

    • @notdaycrucial5179
      @notdaycrucial5179 3 หลายเดือนก่อน +3

      Just because this more of something doesn't mean it is in excess.
      For example lets say you are making a cheese sandwich which needs 2 slices of bread and 1 slice of cheese. If you had something like 8 slices of bread and 5 slices of cheese you would only be able to make 4 sandwiches before running out of bread.
      Even though we had more slices of bread it was the ingredient that caused us unable to make sandwiches.
      Now apply the same idea to chemistry.
      If for example you had 3 grams of hydrogen gas and 16 grams of oxygen gas let's see how much water we can make.
      The balanced equation for water is 2H2 + O2 --> 2H2O
      So if you convert that into moles
      3g/2.0M = 1.5 mol of hydrogen
      16g/32M = 0.5 mol of oxygen
      Then divide by 1.5 by 2 because there are 2 moles of hydrogen reacting per mole of oxygen. This nets you 0.75 moles
      Compared 0.75 to 0.5 the oxygen is lower which means it is the limiting reactant.
      Even though we had much more grams of oxygen than hydrogen it was still the thing that limited the reaction!
      I hope this comment helped you understand this concept more!

  • @cilar7002
    @cilar7002 3 หลายเดือนก่อน +1

    Thankkkk youuu mister

  • @AtharvNatu18
    @AtharvNatu18 หลายเดือนก่อน

    thank you sir🙏🙏🙏

  • @user-qq2bx3mk5i
    @user-qq2bx3mk5i 4 หลายเดือนก่อน +1

    Shoudnot we take hydrigen molarmass 4 because we have 2 moles of 2h

    • @omarora9516
      @omarora9516 4 หลายเดือนก่อน

      Nope its a mistake lots of students make you need to ignrore any number b4 the reaction

  • @jaskaran8339
    @jaskaran8339 6 หลายเดือนก่อน

    Thank you so much sir.

  • @user-tg8yv2ox9f
    @user-tg8yv2ox9f 3 หลายเดือนก่อน

    Thanks mate

  • @user-sr3iy5rk7m
    @user-sr3iy5rk7m หลายเดือนก่อน

  • @viperdio69420
    @viperdio69420 2 หลายเดือนก่อน

    i have no brain
    im traumatised
    AAAAAAAAA

  • @user-tp8dg9qv6w
    @user-tp8dg9qv6w 2 หลายเดือนก่อน

    Guys how is h2 is limiting reactant
    Its 1.5 its higher than 0.95 huh???

    • @rekham2083
      @rekham2083 หลายเดือนก่อน +1

      After dividing by stoichiometry coefficients,it's 0.75, which is less than 0.90