THANK YOU SO MUCH!! My teacher doesn't teach at all, and as a sophomore in high school it's super hard to keep up. Your videos are LIFE CHANGING!!!!!!! :)
I have to admit, the way you explained all of Chp. 12 was beautiful thank you for helping me understand through the content of calculus 3, I'm assuming you are covering using the book Thomas Calculus early transcendentals 14th edition right?
Since she found the center point, and you are given two points that reference the sides of the sphere, all you need to do is find the distance from the center point to one of the given points. Distance formula (note you can use the other point): sqrt((0-1/2)^2+(2-2)^2+(3-2)^2) = sqrt(5/4) = sqrt(5)/2
I calculated the distance between the center and one of the endpoints of the diameter. For example: r = sqrt[(-1 - -1/2)^2 + (2 - 2)^2 + (1 - 2)^2] = sqrt[(-1/2)^2 + (-1)^2] = sqrt(5/4). Either endpoint will work.
Hello ! I just stumbled apon your courses and I adore the way you explain this subject ! I'm a French student n struggle with the way my teachers explains stuff and I found that by learning from teachers that speaks in English helps a lot having another pov on the said subject. Now my question is what age student is this taught? I'm a bit lost trying to find the chapters we do in France at my age with all the algebra / calculus 1234 it's really confusing for me ... Is there a sweet soul that could help me out / explain it to me ? Thanks a lot !
i think The lecturer assumed the center point to be (-1/2, 2, 1), which is incorrect. They simply changed the x-coordinate of one endpoint, but the y and z coordinates remained the same. This does not represent the midpoint of the diameter.
That wasn't me talking, which is why the sound was so quiet. At 25:15, a student in my class was answering. The main point is that the inequality shown is a sphere with the inside filled in.
I’m confused on why for example six, R2 has a horizontal line. The y axis isn’t up and down, its on the left and right. Wouldn’t you graph the line vertically?
Since she found the center point, and you are given two points that reference the sides of the sphere, all you need to do is find the distance from the center point to one of the given points. Distance formula (note you can use the other point): sqrt((0-1/2)^2+(2-2)^2+(3-2)^2) = sqrt(5/4) = sqrt(5)/2
THANK YOU SO MUCH!! My teacher doesn't teach at all, and as a sophomore in high school it's super hard to keep up. Your videos are LIFE CHANGING!!!!!!! :)
Jesus, these videos are saving my calc 3 class. You are greatly appreciated.
Bro imagine i'm studying this at highschool
Thank you so much. I literally breezed through this video and didn’t pause once to scream or contemplate life lol
ma'am this lecture help me a lot I was struggling with this topic for 1 week and now it's clear, love from India
I have to admit, the way you explained all of Chp. 12 was beautiful thank you for helping me understand through the content of calculus 3, I'm assuming you are covering using the book Thomas Calculus early transcendentals 14th edition right?
I follow Stewart's Multivariable Calculus 8th edition.
I am following 7e Is their any problem?
4 sessions of lessons, in one video. Thank youu!!
Great videos.! It would also be amazing if you scanned all of them as completed notes so that it would be easy to study from it again. Thank you
I guess I am quite off topic but does anyone know a good place to watch new movies online ?
@Leland Jermaine Flixportal
@@lelandjermaine8378 netflix
wish i have this awesome lady as my calc 3 professor
Can someone please explain why the X and Y are switched ( X was labeled vertically and Y labeled horizontally) in 2 - space @ 0:18 mins?
I labeled them incorrectly - whoops. Sorry for the confusion!
@@alexandraniedden5337 thank you for reponding!
so how is radius computed in 13:45?
She used the distance formula then divided it by 2. but before you bring a number into a square root you have to sqaure it hence, sqrt(5/4).
Since she found the center point, and you are given two points that reference the sides of the sphere, all you need to do is find the distance from the center point to one of the given points.
Distance formula (note you can use the other point):
sqrt((0-1/2)^2+(2-2)^2+(3-2)^2)
= sqrt(5/4)
= sqrt(5)/2
❤ thank you so much
My teacher
Great work ...where is the rest of the video ?
Ma'am in example 3 it should be centre of sphere not the centre of circle
Do not completely understand problem 4 would you be able to explain that one on how you arrived at 5/4 ?
I calculated the distance between the center and one of the endpoints of the diameter. For example: r = sqrt[(-1 - -1/2)^2 + (2 - 2)^2 + (1 - 2)^2] = sqrt[(-1/2)^2 + (-1)^2] = sqrt(5/4). Either endpoint will work.
@@alexandraniedden5337 thank you so much
Hello ! I just stumbled apon your courses and I adore the way you explain this subject !
I'm a French student n struggle with the way my teachers explains stuff and I found that by learning from teachers that speaks in English helps a lot having another pov on the said subject. Now my question is what age student is this taught? I'm a bit lost trying to find the chapters we do in France at my age with all the algebra / calculus 1234 it's really confusing for me ...
Is there a sweet soul that could help me out / explain it to me ?
Thanks a lot !
In north america this (Multivariable calc) would be typically taught in First year or Second year of university (18-19 years old)
what age is this taught in france
am i crazy or is the radius supposed to be sqrt(5)/2 and then r^2 = 5/4 ??????
i think it should be 5/2
i think The lecturer assumed the center point to be (-1/2, 2, 1), which is incorrect. They simply changed the x-coordinate of one endpoint, but the y and z coordinates remained the same. This does not represent the midpoint of the diameter.
I couldnt make out what you said at 25:15, you are cutting out the .? Great videos btw very concise.
That wasn't me talking, which is why the sound was so quiet. At 25:15, a student in my class was answering. The main point is that the inequality shown is a sphere with the inside filled in.
WELL EXPLAINED AND YOU ARE THE BEST
I’m confused on why for example six, R2 has a horizontal line. The y axis isn’t up and down, its on the left and right. Wouldn’t you graph the line vertically?
She said she made a mistake in the comments
In example 5 why does the radius come out as 2 I assume you root the 4 but i don't see a reason to
Yes, you are correct. In the equation of a circle or sphere the equation has r^2.
@@alexandraniedden5337 ooooh I don't know how I missed that, thank you so much!
thank you Ma'am you teach really well ma'am.
Thank you from Turkey
I'm glad I found you.
Can someone explain in 11:07 how she got the value of d= √ 126?
calculator possibly but you gotta use the distance formula. it doesn't require the calculator.
Can anyone explain radius in 13:55
do u have it now
Since she found the center point, and you are given two points that reference the sides of the sphere, all you need to do is find the distance from the center point to one of the given points.
Distance formula (note you can use the other point):
sqrt((0-1/2)^2+(2-2)^2+(3-2)^2)
= sqrt(5/4)
= sqrt(5)/2
@@yojacq well im past the class but idek if i figured it out at the time
@@vibingwithchill676 its all Good thank God thank God
Wonderful
Thank you sooooo much ❤
V.good explination mam t.q
you are great thnx
you are amazing
i think you have a mistake in 20:11 you must replace x and y with each other
thank youuu very much
THANK YOU
VERY HELPFUL
Thx, in help to revise all of it
I'm using this video to prepare for a calc 3 test. If I fail, I'm blaming you.
did u blame her ?
@@NAYEF.. yes
@@generalforsythe3944😮
what
You didn't completed question 8
good
goat
Thanka for the lect.