Chapter:6 Ex.6.2 (Q.3,4,5,6) Triangles | Ncert Maths Class 10 | Cbse.

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0:35

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8:01 surrender

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Guys Q)3 should be like this
In ∆ABC , LM// CB
BY BPT WE GET
AM/BM = AL/CL -i
AGAIN , IN ∆ACD or∆ADC ( YOUR WISH YOU CAN TAKE ANY ONE)
AL/CL = AN /ND -ii
Comparing i and ii we get
AM/BM= AN/ND
BM/AM = ND/AN(invertendo)
BM/AM+ 1= ND/AN+1 (adding 1 both sides )
BM/AM+AM/AM = ND/AN+AN+AN
AB/AM= AD/AN
AM/AB=AN/AD (invertendo )
Hence proved
.
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8:59

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