16:23 bin1 after bounder replacement will be (13,16,16) because middle value is near to 16 boundry not 13. as 15-13=2 and 16-15=1 so it will be (13,16,16)
For Bin 1: 13,15,16 in bin boundary technique bin 1; 13 16 16 as 15 bin value is closest to boundary value 16 . (your answer is 13,13,16) Also for Bin 2: 16, 19, 20 in bin boundary technique bin 2: 16 , 20, 20 as 19 bin value is closest to boundary value 20.(your answer is 16,16,20) Similarly, for bin 3 answer may be 20,20,22 or 20, 22 , 22 because 21 is closest to 20 also and 22 also. Remaining answers are correct.
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i added to python code that kind of array, it to nearest integer value eg: 19 / 3 = 6.3333 to 6. so that code divided elements by 6 and ignored last one.
16:23 bin1 after bounder replacement will be (13,16,16) because middle value is near to 16 boundry not 13. as 15-13=2 and 16-15=1 so it will be (13,16,16)
YES AAMIR
For Bin 1: 13,15,16 in bin boundary technique bin 1; 13 16 16 as 15 bin value is closest to boundary value 16 . (your answer is 13,13,16)
Also for Bin 2: 16, 19, 20 in bin boundary technique bin 2: 16 , 20, 20 as 19 bin value is closest to boundary value 20.(your answer is 16,16,20)
Similarly,
for bin 3 answer may be 20,20,22 or 20, 22 , 22 because 21 is closest to 20 also and 22 also.
Remaining answers are correct.
In text book(HAN page number 63) it is given that each bin value is replaced by the closest boundary value. that's why i am thing like this
HAN second edition
what if bin has 13 14 15?
thankss buddy... for the wondeful explanation..
In case of smoothing by median:
if bin depth is 4 then (50/100)(4+1)=2.5. Then which will be middle value among 4 items in the bin ?
It means for any value greater than for example 2.1 also we have to select 3rd item. Thank u very much
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U hv taken 3bin values.....what if we hav 4 value in each bin.....how to calculate boundaries
Did you know the answer now?
Then it's not equal frequency binning, maybe equal width binning can work instead.
i added to python code that kind of array, it to nearest integer value eg: 19 / 3 = 6.3333 to 6. so that code divided elements by 6 and ignored last one.
Thanks for clear explanation bro
The mean should be calculated with the original values...
thanks for the video
Thanks bro keep uploading
how to make bin for depth 4..sir
after calculating we get 27/4=6.75...how many bin possible...plz tell sir
did you know the answer now?? I'm also have same question...
Boundary answers are wrong
TAKE SMALLER LENGTH EXAMPLES.....
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