Oooh we're almost to this in calc class, it's nice to see a preview. I love everything you're doing Prime, you're very charasmatic and excited about math
My calc 2 proffessor purposefully sped through his review lecture on FTC 1&2 but explained things in such mindnumbing detail It was hard to follow. This was short and to the point. Thanks so much!
Der sir you always do brife short and clear video ❤❤❤❤ all of them But just as an idea please make explanation about different therom with out question just explanation by using some constant it is helpful for many calculus students just an idea sir ❤❤❤❤❤ 🤔🤔
Why are we multiplying by the derivative of the upper bound though? I get it in terms of just getting f(x) but I just want to know the purpose behind it because. I do appreciate you actually showing this to us instead of just saying to plug in x. I just want to understand the concept though instead of just plugging and chugging.
I had my midterm 2 weeks ago it was very tough got 30 out of 100 :( although I am pretty good at it but there was 600 students who took the exam and most of them failed it last year. So the doctor was very nervous and angry about that and brought a "please fail" questions.. Ex: find y'' for ln(cossqrt(x/sqrtx)). Log rule + chain rule + quotient rule simultaneously for the first derivative test. The second derivative is absolutely unsolvable I swear to God man got a very tedious expression 😩.
Your video is rubbish. The fundamental theorem of calculus is given by my historic geometric identity: (f(x+h)-f(x))/h = f '(x) + Q(x,h) where (f(x+h)-f(x))/h is slope of secant line f'(x) is slope of tangent line Q(x,h) is the difference in slopes. f(x+h)-f(x) = h*[f'(x) + Q(x,h)] = \int_x^{x+h} f'(x) dx This and nothing else. I was the first human to solve the slope and area problem rigorously without BS concepts such as Limits, infinity, etc.
OMG I found my calculus guru u r 2 trillion times better at explaining things then my teacher I luv this channel W channel
Omg bro your the goat, nobody gave a better explanation on the internet better than you bro
best explanation I have seen of this concept anywhere on the internet.
Thanks for your generosity. You are actually my first ever super thanker!
I've never seen Super Thanking before! @@PrimeNewtons
Thanks!
Oooh we're almost to this in calc class, it's nice to see a preview. I love everything you're doing Prime, you're very charasmatic and excited about math
you the goat bro, literally made it so quick, easy, and short! thank you. just subscribed
My calc 2 proffessor purposefully sped through his review lecture on FTC 1&2 but explained things in such mindnumbing detail It was hard to follow. This was short and to the point. Thanks so much!
man amigo you are the man, really appreciate it... only you showed a straight forward easy to understand way on how to do it . thank you very much
😂😂 we don't know how to solve that's why we are watching this video 😂😂😂❤❤❤.
I wish I knew how simple this topic was before! Thank you so much for the super helpful explanation :)
Groovy! And I totally agree about the charisma and excitement. Also, hats!
You make it look so easy! Thanks a lot Sir!
The first 10 secs of the video was exactly what i did on my exam :D. I just left it as it was and wrote "???".
Excellent explanation ! This teacher is a godsend !
Well shorten and just straight to the point,well done sir keep it up 🤝🤝🤝🤝
Incredible and very clear explanation.
👏👏, pls more examples for calculus 2!!!!!! BEST VIDEO Ever
Ufff... Wow... Very nice shot
P.S.: I like your black cap❤
Please do more videos on other calculus topics...your videos are the only ones I understand ❤❤
You, sir, are an inspiration!
Nice teaching style, thanks
thank you very much , it is sooo easy with your explanations
YOU ARE SO AWESOME THANK YOU!!!!! this was very cool
You are so welcome!
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Well explained sir thank u so muchhh!!
Der sir you always do brife short and clear video ❤❤❤❤ all of them
But just as an idea please make explanation about different therom with out question just explanation by using some constant it is helpful for many calculus students just an idea sir ❤❤❤❤❤ 🤔🤔
Noted
you are a real legend
LOVE YOUR CONTENT SIR God bless
Keep up the good work!!!!!
Brilliant!
Why are we multiplying by the derivative of the upper bound though? I get it in terms of just getting f(x) but I just want to know the purpose behind it because. I do appreciate you actually showing this to us instead of just saying to plug in x. I just want to understand the concept though instead of just plugging and chugging.
Great, what happens if i also have a function at the lower limit?
thank you! helped me ace my test!
Thank you for all your help!
I had a question but I think I solved it. You don’t include the constant because when differentiated it just reverts to 0?
What happend to lower limit 7 ? What to do with it ?
Intergating sin(3t^2) is easy if we are allowed to use power series
Definitely!
why can't I have function down? eventually the function is goanna give me number,
great teacher thank you
I had my midterm 2 weeks ago it was very tough got 30 out of 100 :( although I am pretty good at it but there was 600 students who took the exam and most of them failed it last year. So the doctor was very nervous and angry about that and brought a "please fail" questions.. Ex: find y'' for ln(cossqrt(x/sqrtx)). Log rule + chain rule + quotient rule simultaneously for the first derivative test. The second derivative is absolutely unsolvable I swear to God man got a very tedious expression 😩.
Thanks Sir 🙏
Thanks a lot.😊
OMG Kanye West 😅 btw thanks a lot sir !
love this!!!!!!!!!!!!!!!!!
Thank you
NICE!!
Wow just wow
Thank you!
What a G!
We don't know x. Because of this is the result Intg. [sin 8x^9 -sin 343 •dt ] 2x^3-> 7
Proper
Not true . Hierarchy of solving should be followed
Your video is rubbish.
The fundamental theorem of calculus is given by my historic geometric identity:
(f(x+h)-f(x))/h = f '(x) + Q(x,h)
where
(f(x+h)-f(x))/h is slope of secant line
f'(x) is slope of tangent line
Q(x,h) is the difference in slopes.
f(x+h)-f(x) = h*[f'(x) + Q(x,h)] = \int_x^{x+h} f'(x) dx
This and nothing else. I was the first human to solve the slope and area problem rigorously without BS concepts such as Limits, infinity, etc.