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500k subscriber complete hone ki khoshi me sir ki trf se ek aur demanded video deliver....MANY MANY CONGRATULATIONS SIR JII FOR THIS MILESTONE ...(from the heart of whole batch student)
What I couldn't recall: 1. Acceleration would have to be taken out through Electrostatic force and not gravity. 2. mg to kg x×10^-6 . 3. Find angle at which charge enters magnetic field. 4. Don't assume that it makes semicircle . Find angle subtended by motion of charge (arc) at centre of circle and basic geometry. 5. Then find time period through T= 2pi m/qb.
These questions helps a lot, I was assuming that my motion in 2d is good enough, But after trying this question I got the reality check. Thank you sir I will now revise it again
Sir Congratulations for 500k ! Sir main NEET ka aspirant hu and aapke videos dekhke short notes banata hu and Revision karta hu ❤❤ but Sir Mechanics me bohot dikkat aaa raha hain please Sir JEE Mains khatam hone ke baad NEET ke Mechanics ke kuch practice sessions lijiye please 😢 aap 7-8 hrs bhi de doge hume to Mechanics thik ho jaayega 🙏🙏🙏
2022 , Electrostatics . Question level was crazy , cleared up so many concepts 🔥🔥 Did it correctly 😅 ; Used the exact same method which you did + a small trick . step 1 : Noted down every formula which can be used in this question step 2 : found acceleration ( qe/m) , Electric field and time b/w the plates ( t = d / v cos x ) step 3 : time taken for particle to perform full circular rotation ( T = 2*pi*m/qB ) if we observer carefullly ; agar final angle 30 hai ( not given but can be assumed ki arc mei right angle triangle ban raha as , 90( right angle ) - 30 = 60 ) ; then all angles will be 60 automatically and arc formed ka angle is 120 , which is 1/3rd of angle of circle , so timeperiod is 1/3 of full circle rotation . Its the same method you have done but by observation its much faster .
sir aapke jaise teachers ko dekh ke samajh aata ki pehle ke yugon mein shishya apne guru ke liye itna samman aur aatm-samarpan kaise laate the! 🙏 dil se thankyou sir 💝 #teachlikeneverbefore
I always found this concept of finding time spent in magnetic field confusing.. but understood it today Learnings First find horizontal and vertical velocity to find angle just before entering magnetic field Use geometry and symmetry to determine angle subtended at centre Find time spend
MY Learning The magnetic field thing, the behaviour of charge when it enters in magnetic field , it will perform circular motion , i got distracted i thought i need to find the velocity in order to get the time but the finest approach to this qsn was to focus on how we can get the angle before starting the motion in magnetic field, great qsn !
7 out of 7 are correct sir 😁 itni Khushi Toh mujhe mains Ke result se Bhi Nhi mil Sakti jitna isko Karne se mil . A confidence booster lecture for those who did studies very well .
I paused and tried by my own and my answer was 3 too. Thanks for the confidence sir. All revision videos and experiment videos done. (Done in approx 4 mins.) ❤
angle subtended wala nhi dhyaan aarha tha .... ek baar pehle bhi mere saamne time nikalne wala ques aaya tha usme bhi ham smjh nhi paaye the angle subtended nikal ke kr skte the ... ab smjh aagya ... THANK YOU sir
@@gamerxrusher8270 Rotate your head anticlockwise by 30° and you can clearly see that v is perpendicular to B. Otherwise, you can do a dot product of v and B and it will turn out to be zero which means that v is perpendicular to B. v = v cos 30° (i cap) + v sin 30° (j cap) B = B(- k cap) Clearly, v dot B is zero.
Sir ek doubt hai... Aap vo plates conducting yaa non conducting nahi bathaye... Tho answer tho ussi according se differ hotha hein na sir... Agar conducting plates tho E=sigma/afselen aur non conducting tho E=sigma/2afselen hoga na sir
Sir i found v' and then using it i found radius of that circular path and by geometry i found therta And by radius×therta i found arc lendth and the v'/arc length i got t=3 (IS THIS APPROCH RIGHT)
Yes sir my answer was correct in first try These single multiconceptual sessions are very good way to revise Please bring more videos because like this ❤❤
Congratulations sir for 500k subscribers, you are the reason for my strong physics in jee , will give my best in the exam with your guidance and then advanced, hope to meet you someday, thank you so much sir for your efforts for us ❤❤.
sir i will hit back harder in physics in the next attempt at the moment i know my weakness and strengths and it is next to impossible for me to score 20+ in physics right now i promise to cover remaining syllabus of physics from your channel after this attempt and i will make sure to score decent marks in physics my reflections : in the early months i was theory oriented and so basically it messed it up all and lastly in december i discovered this heavenly channel increasing cutoff and competition for free
wonderful session sir! my approach was almost correct but i got confused and stuck in between. concept learned: to take angle while entering field and calculating further with the help of it.
sir i think you forgot to write cos theta ??? my ans is 3cos30degree ????? any ways nice question and creativity sir ji apse jyada mehnati caring and dedicated teacher maine aaj tak nhi deka many many congratulations for 500k ❣❣❣♥♥ sir aap ka ashirwaad chahiye jan attempt ke liye ❣
Sir, congratulation for 500K , please keep supporting us in same way sir And solved the Question by own , then seen your soln , it was exact same ...You have made our concept so clear that no multi concept Q can stop us , Thank U sir❤❤
congratulations sir for 500K🎉🎉🎉🎉 ... may this channel shine more and more❤❤❤❤.... and thanks for this series sir.. this ques was really good...and i have done it 50% correct.. last m thodi mistake kr di thi..😅😅
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Sir yeh wala question cengage me bhi h maine 1 saal pehle kiya tha
PLEASE SIR PROVIDE GOLD MINE SHEET LINK
IN COMMENT NOT GETTING IN ANY OF YOUR VIDEOS DESCRIPTION
SIR PLEASE MAKE A VIDEO ON CHARGE IN A MAGNETIC FIELD AND PULLEY PROBLEMS🙏🙏🙏PLESE REPLY⚠️🙏⚠️🙏
500k subscriber complete hone ki khoshi me sir ki trf se ek aur demanded video deliver....MANY MANY CONGRATULATIONS SIR JII FOR THIS MILESTONE ...(from the heart of whole batch student)
thank you for your wishes, keep learning and solving
Ider saans leta hu or waha eduniti ke new video aa jati hai❤
Ider overthinking start hoti h aur uder sir motivate kr dete h kbhi teli pr to kbhi u tube shorts se❤
Bhai saans lena band mat karna please
@TusarJha-d8r great so thoughtful 😂
@@RashiKumari-z3i You are very cute💓
@TusarJha-d8r acha joke hai 😂😂
I did it almost correct I just didn’t think the angle could be different and took it as a semi circle, learning done!
Same mistake😅
Congrats on hitting 500k subs!
stay blessed sirji…a fellow jee aspirant as well as an edunitian💙
2:35- Must See Variety
6:56 - KTP - Charge Trajectory
8:48 - Procedure to find Centre of the Circular Traj.
What I couldn't recall:
1. Acceleration would have to be taken out through Electrostatic force and not gravity.
2. mg to kg x×10^-6 .
3. Find angle at which charge enters magnetic field.
4. Don't assume that it makes semicircle . Find angle subtended by motion of charge (arc) at centre of circle and basic geometry.
5. Then find time period through T= 2pi m/qb.
Same, just exclude point 5 for me
Also 5:44 mei +10 use kar diya, instead of - 10
I missed 2nd nd 3rd pnt
Ye toh tune pura sawaal hi likh diya mtlb kuch nhi recall kr paye ?? 😢
Congratulations mohit sir for 500k family we will grow and 1 million soon.... #eduniti
These questions helps a lot, I was assuming that my motion in 2d is good enough, But after trying this question I got the reality check. Thank you sir I will now revise it again
well done on completing it
keep learning and solving
Sir congratulations for 5 lakhs subscribers. Now we are a half million family
Congrats 🎉
Watched it in learning mode and solved it later ☑️
Sir Congratulations for 500k ! Sir main NEET ka aspirant hu and aapke videos dekhke short notes banata hu and Revision karta hu ❤❤ but Sir Mechanics me bohot dikkat aaa raha hain please Sir JEE Mains khatam hone ke baad NEET ke Mechanics ke kuch practice sessions lijiye please 😢 aap 7-8 hrs bhi de doge hume to Mechanics thik ho jaayega 🙏🙏🙏
Very nice question sir, connect all the loops ❤
2022 , Electrostatics . Question level was crazy , cleared up so many concepts 🔥🔥
Did it correctly 😅 ; Used the exact same method which you did + a small trick .
step 1 : Noted down every formula which can be used in this question
step 2 : found acceleration ( qe/m) , Electric field and time b/w the plates ( t = d / v cos x )
step 3 : time taken for particle to perform full circular rotation ( T = 2*pi*m/qB )
if we observer carefullly ; agar final angle 30 hai ( not given but can be assumed ki arc mei right angle triangle ban raha as , 90( right angle ) - 30 = 60 ) ; then all angles will be 60 automatically and arc formed ka angle is 120 , which is 1/3rd of angle of circle , so timeperiod is 1/3 of full circle rotation .
Its the same method you have done but by observation its much faster .
very good dear
I found this channel last month now I wish I knew it before
But the qoute learn like never before perfectly suits the channel content
sir aapke jaise teachers ko dekh ke samajh aata ki pehle ke yugon mein shishya apne guru ke liye itna samman aur aatm-samarpan kaise laate the! 🙏 dil se thankyou sir 💝
#teachlikeneverbefore
Congratulations for 500K subs 🎉🎉🎉
And many more to come🎉🎉🎉
I always found this concept of finding time spent in magnetic field confusing.. but understood it today
Learnings
First find horizontal and vertical velocity to find angle just before entering magnetic field
Use geometry and symmetry to determine angle subtended at centre
Find time spend
well done on completing it
keep learning and solving
MY Learning
The magnetic field thing, the behaviour of charge when it enters in magnetic field , it will perform circular motion , i got distracted i thought i need to find the velocity in order to get the time but the finest approach to this qsn was to focus on how we can get the angle before starting the motion in magnetic field, great qsn !
Learn like never before 💯
7 out of 7 are correct sir 😁 itni Khushi Toh mujhe mains Ke result se Bhi Nhi mil Sakti jitna isko Karne se mil . A confidence booster lecture for those who did studies very well .
Mohit goenka for a reason❤
Learning :- find the angle subtended by the centre of the trajectory to get time
Congratulations sir for 5 Lakh.
Need your blessing for jee🥰
Congratulations sir for 5 lakh followers 🎉🎉🎉
Done...sir aap aise aur question lao .... confidence aur concept dono badhta h 🔥
More helpful thanks alot❤
I paused and tried by my own and my answer was 3 too. Thanks for the confidence sir. All revision videos and experiment videos done. (Done in approx 4 mins.) ❤
Well done
@@mohitgoenka99 sir ab aage kya karu 😅
Congratulations sir 🎉🎉 now we are a family of 500k
3:17 converted mg to m..... mg is converted to kg
Solved in one go. Thank you sir for boosting confidence. #LearnLikeNeverBefore
excellent dear
Got answer 3....bring such more questions for boosting confidence sir
yes sir,done the q right with the same approach
Sir , solved till the last with the same approach just got some calc error.❤❤❤
Congratulations Sir on 500K😊
Following since some 1 lakh+ and now we are here at 500k. Congratulations sir ❤
Congrats for 500k sir 🙏🏻
500K congrats
angle subtended wala nhi dhyaan aarha tha .... ek baar pehle bhi mere saamne time nikalne wala ques aaya tha usme bhi ham smjh nhi paaye the angle subtended nikal ke kr skte the ... ab smjh aagya ... THANK YOU sir
well done on completing it
keep learning and solving
I almost touched the correct concept and approach for the question 😊
Got it correct for the most part Sir
sir thank you did it on my own in 5 min
thanks for teaching us : )
bring more such sessions
excellent dear
Really man sir is giving his 110%
Thanks sir
Sir congratulation on 500k❤❤❤❤
Same approach lagaya tha sir thank you 😊
almost did it bas last time ka formula galat kar diya tha
learning done! thnks sir
thank u sir aisa best content provide karne ke liye😊
well done on completing it
keep learning and solving
congratulations sir for 500k sub. complete 🙏🙏,
sir if v is at some angle with B then it should follow helical path rather circular path ?
But here v is perpendicular to B look carefully the 30° angle is with x-axis
@@pog4501if B is in -z direction and x is perpendicular to z axis but if v is in some angles from x axis how can it be perpendicular to z axis?
@@gamerxrusher8270 Rotate your head anticlockwise by 30° and you can clearly see that v is perpendicular to B.
Otherwise, you can do a dot product of v and B and it will turn out to be zero which means that v is perpendicular to B.
v = v cos 30° (i cap) + v sin 30° (j cap)
B = B(- k cap)
Clearly, v dot B is zero.
Sir ek doubt hai... Aap vo plates conducting yaa non conducting nahi bathaye... Tho answer tho ussi according se differ hotha hein na sir... Agar conducting plates tho E=sigma/afselen aur non conducting tho E=sigma/2afselen hoga na sir
inside the capacitor yhi hota h n bro Electric field sigma/epsilon .....and
sigma/2 epsilon toh single plane k karan hota
Sir i found v' and then using it i found radius of that circular path and by geometry i found therta
And by radius×therta i found arc lendth and the v'/arc length i got t=3
(IS THIS APPROCH RIGHT)
Sir ko mera 🫡 for the hard work he is putting in .
Yes sir my answer was correct in first try
These single multiconceptual sessions are very good way to revise
Please bring more videos because like this ❤❤
really good question sir
quickly revised 4 chapters
hats off to your efforts 🤠❤❤
Beautiful Question
Question was too good sir...please keep giving multiconceptual questions like this❤
Congratulations on 500k subs sir! You're a true hero helping most of us overcome our hurdles in physics!!!
Great questions ❤
correct 🔥 thankss sirr and congratulations on 500k!!!!❤
Easy sir. Did it in 5 minutes only.
Sir please one video on all different formules of mean free path.
I took the same approach!😊
very good dear
Sir did the kinematics part by myself and it was correct but i couldn't thought of t/3 thanks sir ❤
Congratulations, MOHIT sir Your dedication and hard work truly inspire us all and love you sir 🎉🎊👏🎉🎊👏🎉🎊👏❤❤❤
With this type of quality content this channel deserves more than 1M subscribers ❤❤❤
Sir Is more consistent that us ❤
Many many congratulations sir for 500k🫡🫡❤️❤️
Congratulation 🎊 for 500k subscriber sir 👏
Solved the question exactly the same way u solved .
Thank you so much sir
All the best
Solved in one go but took 4-5 minutes😊😊 thank you sir for your efforts
excellent dear
Really sir mind blowing question ## 500 k special question
yes
500K special fresh question by Mohit Sir
Congratulations sir for 500k subscribers, you are the reason for my strong physics in jee , will give my best in the exam with your guidance and then advanced, hope to meet you someday, thank you so much sir for your efforts for us ❤❤.
sir i will hit back harder in physics in the next attempt at the moment i know my weakness and strengths
and it is next to impossible for me to score 20+ in physics right now
i promise to cover remaining syllabus of physics from your channel after this attempt and i will make sure to score decent marks in physics
my reflections : in the early months i was theory oriented and so basically it messed it up all
and lastly in december i discovered this heavenly channel increasing cutoff and competition for free
wonderful session sir!
my approach was almost correct but i got confused and stuck in between.
concept learned: to take angle while entering field and calculating further with the help of it.
Thankyou sir.. Understood the concept crystal clear
(Congratulations Sir on 5 LAKH SUBSCRIBERS)🔥🔥🔥
Ho gya tha. Thank you 👍🏼
Congratulations sir!!❤❤❤ we all wish that the channel keeps growing.. you are the best⭐️🫶
7:17 why is the motion of the charge not helical
either from our revision sessions or your short notes once check the condition for helical path
sir i think you forgot to write cos theta ??? my ans is 3cos30degree ?????
any ways nice question and creativity sir ji apse jyada mehnati caring and dedicated teacher maine aaj tak nhi deka
many many congratulations for 500k ❣❣❣♥♥
sir aap ka ashirwaad chahiye jan attempt ke liye
❣
sir please jaldi jaldi video dala karoo ❣❣
Was able to do it 🎉
Congratulations sir for 500k Subscribers .Aap sach me deserve krte ho bhot sare subscribers...truly happy for you ❤❤❤❤❤
Sir thank you so much for this series it help us a lot.....😊😊
4:36 apki aawaz meri atama chugai
Theeta ko 180 assume kar liya,balki wohi find karna tha by geometry and motion of charged particle in magnetic field
same sval salim sir pw ne prayas batch me bhi kraya tha. Isiliye easily bngya🙏. thankyou sir for your efforts too
Lakshya me bhi ye sab hamare class notes me dekh ke bohut kushi hota hai!
Sir, congratulation for 500K , please keep supporting us in same way sir
And solved the Question by own , then seen your soln , it was exact same ...You have made our concept so clear that no multi concept Q can stop us , Thank U sir❤❤
Loved the session sir very good question. Got the answer right at first try . Sir more such questions pls....❤
THANK YOU SO MUCH SIR JI 🙏🙏
Confidence level highly boosted as always after Sir's efforts
Almost right approach sir
Sirji, thank you very much...
0:31 2023 and one old path equation, angle of deviation
0:32 2023...2 questions
Thankyou so much sir❤. Bhagwan aapko lambi umra de.
Sir at 4:17 did you pitch then for that need to multiply with time peroid
Thanks sir for this wonderful session
Learn some quick concepts of magnetic field
congratulations sir for 500K🎉🎉🎉🎉 ... may this channel shine more and more❤❤❤❤.... and thanks for this series sir.. this ques was really good...and i have done it 50% correct.. last m thodi mistake kr di thi..😅😅
Got the correct answer. Thank you sir
Lost it at the angle subtended by the circular path inside the magnetic field. Rest did correctly
Sir a small doubt, can we say that a particle won't complete a semicircle if it enters the field at an angle?
Thank you sir for this amazing session...it is really helpful