How to Sketch Acceleration Time Graph From Velocity Time Graph

[@syedfazlihanan9759]

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[@MathematicsTutor]

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My textbook didnt explain this very well, so I went to youtube, watched 5 videos about this, and this one if definitely the best.

[@MathematicsTutor]

Thanks a lot for appreciation. It inspires me to do the needful for the students like you. Share and Subscribe, if you like. Thanks and All the Best!

[@ramniwasgupta8688]

MegaRingla I

[@kwispee5169]

This was so helpful. These graphs are pretty hard to grasp the concept of, especially since we are so used to our graphs being continuous or remotely continuous, and then these acceleration graphs come out of nowhere.

[@MathematicsTutor]

Thanks

[@lilohandaru5552]

yes, discontinuous graph is unintuitive

[@Schmidty96]

Random Indian genius saving me from the depths of failure once again

[@MathematicsTutor]

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[@MathematicsTutor]

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[@MathematicsTutor]

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All the Best

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Thumbs up Sir.! You explained it way better than how my proffesor did. Hats off.

[@MathematicsTutor]

Thanks for appreciation. Feel free to post question. Thanks

[@ajibolaekunola]

Very informative❤

[@MathematicsTutor]

Thanks

[@rohityadavjhansi]

Thank u so Mach is this topic is very difficult for me and I am facing problem to understand this topic clearly but now I understand this topic clearly😊

[@MathematicsTutor]

Thanks and All the Best

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Best video ever made for graphs! Awesome explanation.. Keep up the good work!

[@MathematicsTutor]

Thanks a lot for appreciation

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Very easy to understand and I'm in 2019
Thanks alot

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Very nice explanation, very clear, props to you sir!

[@MathematicsTutor]

Thanks for appreciation.

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Thanks sir very very much.. it helped me a lot. Presently I'm in class 11 and studying kinematics..

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[@veronicaanderson1307]

Great video. Helps a lot for my exam tomorrow. Thanks!

[@MathematicsTutor]

Thanks for appreciation. All the Best!

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[@MathematicsTutor]

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Thank you so much!!! I’m taking AP physics 1 (I want to major in physics) I was so confused lol

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Wish me luck!!!

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[@lostperson23]

Sir I actually have a question, is it a way I can reach out to you?

[@MathematicsTutor]

email: [e-mail]
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ahh this video was so helpful! thank you :)

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what pen are you using ?

[@MathematicsTutor]

This is the most popular question. Here is the solution: th-cam.com/video/ck-MU8Pmwzs/w-d-xo.html
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[@yousufali4567]

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[@jabsba]

Thank you very helpful! But at the beginning on the acceleration graph shouldn't you start at 0 and then go to 2?

[@MathematicsTutor]

Acceleration is constant and eqaul to 2 m/s^2 in the first leg.from 0 s to 5 s. Horizontal line as shown in the graph correctly shows it. Hope it is clear. Thanks

[@sivakumarsg1153]

👌🙏 Good explanation

[@aerdis3814]

I have a question. when velocity goes from 0 to -20 so in the negative direction the acceleration will be negative too. isn't it

[@bemneth.tefera7682]

Yes, Because its decelerating or the speed is decreasing which only happens when the position is negative. The acceleration is negative too.

[@aerdis3814]

@@bemneth.tefera7682 thanks professor!😇

[@killerman6336]

This Clear my doubts

[@shafkatalam7373]

Don't we have to join the lines in Acceleration vs. Time graph?

[@dianaf8507]

Thank you for helping me!

[@joseguevara9143]

Thanks so much!

[@harshitarai9297]

Can anyone tell me from which book this question has been taken?

[@judekmashi9227]

Thank you. ❤️

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Nice 🎉🎉

[@verniego6189]

Thank you sir!

[@swetasweta9540]

Why is deceleration always taken as negative ?

[@SadiqunhnabiChoudhury]

Why didnt you add the seperate lines in the acceleration time graph together???

[@MathematicsTutor]

Good question. Transition at an instance is not really defined. Example at 5 we are not sure if the value is 2 or 4. Corners result into undefined rate of change.
Hope that is clear. Thanks

[@Babsmeme]

Does that mean that if velocity was a curve, then acceleration would be a straight but diagonal line?

[@bijoyetribhowmik9905]

Absolutely

[@lenamitrov9861]

Wonderful!

[@lonevoyager6026]

but why don't you look at like the point like at 1,2,3,4 or 6,7,8,9/? ik these dont have accurate numbers on the y but on a test I did, i could find one for each x number but idk why u have to use only the 5,10,15,and 20 plz epxlain

[@jdrukman]

they're not needed. you only need two points to create a line, and acceleration is just the slope of each line.

[@TheMath2700]

very helpful

[@shashiranjan8596]

Thnq sir

[@mthulisi]

So u don't connect the points just leave the dashes

[@canyalman8794]

OMG THANK YOU SO MUCH

[@vondrez]

Really good vid

[@MathematicsTutor]

Thanks for appreciation. All the Best!

[@valsalak4957]

Thank you sir

[@hemu5036]

Thank you

[@nshu8935]

Btw nice explanation

[@vestafarhan7580]

Best out the best

[@maleighapeterson3987]

i hate physics but i love you bro

[@rvs263]

Can I join the lines of a-t graph

[@rvs263]

Any of the reader of my doubt can reply

[@lazycatt287]

So acceleration is just tangent lines and irs not connected

[@MathematicsTutor]

There is jump discontinuity at t = 5, 10, 15, in between we have constant acceleration as shown by the horizontal line.

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Good shit

[@MathematicsTutor]

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[@MathematicsTutor]

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helped :) so much

[@MathematicsTutor]

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