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Python Program to Check Armstrong Number
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- เผยแพร่เมื่อ 11 ส.ค. 2020
- Armstrong number in Python: In this video, we will write a Python program to find Armstrong number
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Armstrong to theek hai lekin ye Binod kon hai?
Binod is Binod 🤣😎
Are apko nhi pta 🤣🤣 ya likes ke liy likha hai
Binod ka toh pta nhi pr Nitish toh apun ha
Sir Binod CORANA KA BADA BHAI hai 😅
mere pados m rehta h
I m 14yrs old and we r not taught programming in school, I started learning programming in 6th, and am an intermediate python coder, all just bcoz of you, hope you read and if yes, plz reply or give a ❤️👍😊☺️
Please
@@technoguide1462 ?
@@siddheshphadke3719 same here
@@siddheshphadke3719 please give me feedback please
@@DivyanshuLohani what happened
I took a different approach!
n = input('Enter the number: ')
length = len(n)
value = 0
for i in n:
a = int(i)**length
value = value + a
print(value)
if value == int(n):
print('The number is an Armstrong number!')
else:
print('The number is not an Armstrong number.')
@Malik Abdullah Nasir it's is nice coincidence
so why are u learning to code
Harry bhai, you are a wonderful teacher and programmer
If you like please support
Apki waja se mai apne sapne pure kr pa rahahun Mai apni kud ki websites banali h ab mai bahut jald payse Arun kr pauga
Lekin yh bat Jan kr bahut khushi ho ki mai ek electrical engineering karne wala student apki waja se ek Web developer bn paya.
9:09 We've changed the value of n in loop.
there should be temp = n, as n keeps changing and becomes 0 at last. SO we have to store the input value to a temp variable
Yes
Aisa lgta h aap pura mere college k sath chl rhe ho same...topic there same topic here even in same lang
So nice of u
Plot Twist: Harry and you are in same college, but he didn't revel his identity yet 😂😂😂
@@yashbansal1414 😂😂😂kash
Harry bhai theak haa code
number = input("Number Enter:
")
lennumber = len(number)
sum=0
for i in number:
square= int(i)**lennumber
sum+=square
if int(number) == sum:
print("Number is Armstrong")
else:
print("Number is not Armstrong")
Great way to make us acually realise HOW TO CODE !!!!!!!!!!!!
Harry bhai this would also work:
from math import pow
z = (input("Enter a number: "))
p = list(z)
c = 0
for i in range(0, len(p)):
t = pow(int(p[i]), len(p))
c = c+t
if int(z) == c:
print(f'{z} is an armstrong number')
else:
print("Not an armstrong number")
🔥🔥🔥
another possible solution is this
num=input('please enter the number in question')
n=len(num)
sum=0
for digit in num:
sum+=int(digit)**int(n)
if int(sum)==int(num):
print('it is an armstrong number')
else:
print('it is not an armstrong number')
Thank you very much!
excellent bhai this question was asked to me in one of the interviews i faced recently !
You are great genius coder.
def isArmstrong(number):
numList = list(str(number))
sum = 0
for numbers in range(len(numList)):
sum = sum + int(numList[numbers]) ** len(numList)
if sum == int(number):
print(f"Yes {number} is a Armstrong number")
Number ki digits ke liye calculation ki kya need hai? Number ko string me convert karke uski index ke liye bhi loop chla sakte hai.
Sir you have made learn linux in one video tutorial and it helped me a lot. Can you make a full tutorial on linux. Please..🙏🏻🙏🏻🙏🏻
And if it is already there then can anyone provide me the link.
Harry bhai.... debugging pe bhi video bana do plzzz
Harry bhai apke channel per java ke tutorial nahi hai. So please upload full java course begineer to advanced. Apse achha koi nahi samjata hai pure youtube per.
Perfect explanation sir... I wish i had a teacher like you🙄🙄🙄
Harry bhai ur best programming teacher
Perfect teaching skills 👌
Very well explained!
Harry Bhai ....love u....i was very obssessed with code when i first learn from another TH-cam channel....but when i started watching your vdo.....swear to god.....siddha dimaag me gushta hai......maja aa gaia....Love u bro....Maja aa gaia
Harry bhia aapka internet really superfast hai.. Bilkul aapki tarah 🔥🔥🔥🔥
a=int(input())
b=[]
for i in str(a):
c=int(i)
b.append(c**len(str(a)))
if sum(b)==a:
print(f"{a} is an Armstrong number")
else:
print("No it is not")
Space tech sikhao please jo whitehat jr me sikhate hai faaltu me 1 lakh rupees charge karte hai jabki aap ye sab chize free me dete hai you are great human being par please ek baar whitehat jr ka course dekho or uspe ek playlist banao
I love the way when he told - samjha kar hi manunga.😂😂😂
Bro video dekhne se pahele..main try Kiya...🤗🙈 aur Success bhi Mila..😎🙈✌. You are ossm bro..✌
Thank you soooooo much!!
Yeh raha armstrong number ko check karne ka code.
num = input("Enter the number:
")
lst = []
for c in num:
lst.append(int(c)**int(len(num)))
if sum(lst) == int(num):
print("This number is a armstrong number")
else:
print("This number is not a armstrong number")
Bohot achhe harry bhai.Please aise aur practice programs banaye
Bhai ek problem hai kyoki mathematically 0 ki power 0 is equal to 1 hota hai fir ye Armstrong number kaise ho sakta hai.
Bhai ek dil dedo agar aap future mein ek AI game banaoge just like chess.
Please make a series on data structures and algorithms in python please. 🔥💯
Yes please Harry bhai
perfect 👌👌
thanks brother its help me a lot
num, sum = input("Enter a number: "), 0
for i in num:sum += (int(i) ** len(num))
if (sum == int(num)):print(f"{num} is an Armstrong number.")
else:print(f"{num} is not an Armstrong number")
sir this is the shortest code i can write for this problem please verify
Thank you harry for this great vedio... Lots of love your way... ❣️❣️ keep making us more perfect in python.
lambda n: n == reduce(lambda x, y: x + y, [int(str(n)[i]) ** len(str(n)) for i in range (len(str(n)))])
Bhai mast video banai hai.. aise hi aur banao yrr
Shukriya bhai ❤
thank you
number shd be assinged in another temporray variable the equate in if block
def armstrongnumber(n):
arm = 0
for i in range(0,len(str)):
arm = arm + int(str[i])**len(str)
print(arm)
if arm == int(str) :
print("The Entered number is Armstrong number")
else:
print(f"The Entered number is not an Armstrong number as {arm} not equal to {int(str)}")
if __name__ == '__main__':
str = input("Enter a number:")
armstrongnumber(str)
# print(arm)
harry bhai.. aap ka web development course bohot hi accha tha. please start a course on angular or reactJS.
Sir we are facing the errors in browser like "Failed to load resource: the server responded with a status of 404 (Not Found)"
While doing the java script programs in VSCODE..!
And our programs are not run bcz of this error.
Plz let us tell how to fix it🙏🙏🙏🙏
See Uncle this error comes when the address of the website is not found. You can fix this by verifying the address of the server
Sirji apke tutorial BHOT badiya hote hai....kya aapp Java programming language ke tutorial leke aa skteho
Thank you Harry bhai👌🏻
Harry bhai Main final year student abhi start hua hai mujhse data Structure kuch khass nhi aata main ye jaanna chahta hu ki aapki data structure ki series kitni time pr khatam hogi ek guzaris smjho yaa apne bhai ki request try to upload videos regarding Data Structures and Algorithm only not other stuff. This will help me out. Aapke DS and algo series mujhe pasand aayi aur main use continue krna chahta hu.
If u read my comment kindly reply.......
Write now I am taking ur Complete C tutorial that is awesome itna aache se toh hamare professor ne bhi nhi smjhaya.
So, think About it please......................
Awesome program harry bhai.......
And last main ji tune bajate ho uska naam kya hai??
Thanks so much sir
Please also make video in machine learning project and also data structure and algorithms in python.....
good explanation harry
Sir make videos on star patterns in C programming language
thanks bhai
harry bhaiya thnx mai 13ka hu aur coding sikh rh hu thnx
Thank you sir.
Sum = 0 , pehle mention krna kyon jaroori hai...Please reply
thank you harry bhai for giving a wonderful course of python
# Bhai maine bhi ek solution banaya hai wo bhi sahi answer de raha he ye mujhe zyada easy lag rha he
def armstrong_detector(num):
lst = []
n = len(num)
for i in num:
try:
lst.append(int(i)**n)
except ValueError:
print("Please provide a number.
")
exit()
if sum(lst)==int(num):
return f"
{num} is an armstrong number."
else:
return f"
{num} is not an armstrong number."
if __name__ == "__main__":
number = input("Enter a number.
")
print(armstrong_detector(number))
Sir,
Please please please make a video on Pyside2 Qt5 please please make video
thanku
Harry bhai you are op 🤣🤣 Binod Number wali baat pr hasi aa gai😄😂
bro you are awesome
Sir please make a video on which desktop is best for for programming
please post more python programs like this
are you using any external device for writing?
n ki value while loop ke endgame ke baad 0 hogi kyuki floor division of last 8//10=0 dega
n ki value intact toh nhi thi badal gayi aur agar ap uss n ki value se program krte ho toh not an Armstrong aayega
Great
1:41 was awesome 😅😅😅😂😂🤣🤣
Awesome bro
nice sir
Bhai ek question hai important ,do you know how can we read the data which is in ram ?
You're amazing Harry sir💖
Amazing sir thank you
Bro make this series in python too please🙏🙏🙏🙏🙏🙏
Sir how are you able to write? I mean what stylus and pad are you using?
Bhai Aapke har din 5000 subscribers badh rahe hai
Congo
You deserve a lot more
Problem is the variable n is not the original one as we have modified it in while loop
def armstrong_checker(number:int):
ls = []
ls2 = []
for item in str(number):
ls.append(int(item))
for item2 in ls:
ls2.append(item2 ** len(ls))
if sum(ls2) == number:
print("It is an Armstrong Number!")
else:
print("It is not an Armstrong number")
if __name__ == '__main__':
inp = int(input("Enter your Number: "))
armstrong_checker(inp)
1:42 Harry Bhai mic ko kya hua tha
Thank you brother 🙏👍
Thank you.
Please Upload a video for installing visual studio.
It will really be helpful for me.
There is already a video on visual studio code.....
I am big fan of you..
Name: Rajveer singh
Make video on anagram of strings
Please give us your discord server link sir. It a request. If you dont have discord server so i am very helpful to make a discord server for you.
harry bhai aap toh padha kar nikal jate ho,
kabhi live session bhi kra kro
QnA type
How to convert answer to list in an interval
Like 1 to 100
1
2
3...
I want in [1,2,3..] ??
I have a question
How to find angles between two lines with numpy. Please tell me
6:52 Bhaiya agar digit ko append kare toh nhi chalega??
Can this be done with for loop???
Please make tutorial for java...mostly needed.
Sir you are great but please tell me about how to make games and app by python
Find a maximum armstrong number in a given number.
Example: 1211531634121
Possible armstrong numbers: [153, 1634]
Output: 1634
Any one know
Yes variable kisi or value me save karna padega
Harry bhai Apne python biggener tutorial mein #59 mein abstraction and encapsulation ko switch kar diya hai . main vo playlist dekhra hun abhi main beginner hun..
c# ke upar bhi ak complete tutarial banado . bohathi acccha hoga
# this is programmer to calalate the armstrong number
# author = kartik☻
import math
number = (input("Enter the number"))
len_of_number = len(str(number))
# print(len_of_number)
total = 0
for i in (number):
i = int(i)
power = i ** int(len_of_number)
# or
# power = math.pow(i,int(len_of_number))
total = total + power
number = int(number)
total = int(total)
if number == total:
print(f"This is armstorng number {number}")
else:
print("this is not armstrong number ")
please make playlist on reactjs please you have created playlist of website development but reactjs is included in that so without reactjs its incomlete its necessary for web developer to learn reactjs also so please make reactjs playlist in hindi. i am searching for it so long but can't able to find a good teacher like you to make things easier to understand please please .
from your fan and student.