Camronmathz !! Nice strategy and good explanation Another way I found is by plugging in each discontinuity into the numerator If the numerator = 0, its a hole; otherwise its a vertical asymptote Example - x²-5x+6 / x²-3x+2 We set denominator = 0, and get x = 1,2 as discontinuities Plug x=1 into the numerator and we get 2, so its a vertical asymptote Plug x=2 into the numerator and we get 0, so its a hole It also works for silly fractions as long as both the numerator and the denominator are continuous I think Example - sin(x)/x We set denominator = 0, and get x = 0 as discontinuity Plug that into the numerator and we get 0, so its a hole Btw at 4:09 - strictly speaking when the denominator cancels out, we get 1 on the denominator
For my sister
thank you bro clutched my next test 🙏(ive never heard of this in my life)
Great to hear!
Camronmathz !!
Nice strategy and good explanation
Another way I found is by plugging in each discontinuity into the numerator
If the numerator = 0, its a hole; otherwise its a vertical asymptote
Example - x²-5x+6 / x²-3x+2
We set denominator = 0, and get x = 1,2 as discontinuities
Plug x=1 into the numerator and we get 2, so its a vertical asymptote
Plug x=2 into the numerator and we get 0, so its a hole
It also works for silly fractions as long as both the numerator and the denominator are continuous I think
Example - sin(x)/x
We set denominator = 0, and get x = 0 as discontinuity
Plug that into the numerator and we get 0, so its a hole
Btw at 4:09 - strictly speaking when the denominator cancels out, we get 1 on the denominator
this guy is the goat
Lmk if you need anything else
Duuuude I had a test on this like a week ago WTH!
You know now for next time ! If u need me to do any concepts lmk I'll gladly do it