Greetings to you your highness, am an amateur in php and am trying to build a site where one can select an option from a dropdown-list, I have managed to load from MYSQL data-table onto the selection list, every option on the list has additional information in the data-table so when the user choose an option the other info should display in the text filled and label before submission. My problem is, the details are not displaying on text input nor the label. I used Ajax to send to html, I have tried every possible way that I could. The confusing part is, when i was loading from the database onto the select dropdown-list sometimes the language is difficult to understand when some codes work at some pages and same code won't work at some. I have watch tutorials that did the same thing but when I try mine give error, " Notice: Undefined variable: rows in"----"Notice: Trying to access array offset on value of type null in".
How are you using echo when nothing is getting diisplayed on your brwoser?? it worked for me but the json file is getting displayed in the browser. Can you help me man?
Thanks for this Raj, but what if the records are so much up to 2000 records, I can't search one after the other...I hope you get me.
Its just amazing
Help me A Lot
Thanks sir it’s very useful video
Please would like to know how you were able to use Mysql instead of xampp in step by step
Gracias
ty so much bro
this is what i want
Thank you man
The code will be much helpful
Greetings to you your highness, am an amateur in php and am trying to build a site where one can select an option from a dropdown-list, I have managed to load from MYSQL data-table onto the selection list, every option on the list has additional information in the data-table so when the user choose an option the other info should display in the text filled and label before submission.
My problem is, the details are not displaying on text input nor the label. I used Ajax to send to html, I have tried every possible way that I could. The confusing part is, when i was loading from the database onto the select dropdown-list sometimes the language is difficult to understand when some codes work at some pages and same code won't work at some. I have watch tutorials that did the same thing but when I try mine give error, " Notice: Undefined variable: rows in"----"Notice: Trying to access array offset on value of type null in".
How are you using echo when nothing is getting diisplayed on your brwoser?? it worked for me but the json file is getting displayed in the browser. Can you help me man?
Thankyou so much!
thanks
hi sir, i followed same steps but i didnot get result, data is coming in the text field as undefined, please help me very urgent
hi good can you do it on a drop down menu
helo good day what if search by employee name not to ID
Olá tem o código e o banco de dados para baixar
Sir source code if you add in the description it will be much more effective
The code is not working for me, can someone please help
can i have your source code
The source code pls
code pls
Codes pls
Please share source code?
bro need source code
Source code please 🙏