At 8:48, I always look to the pressure tables as first, so ı looked for 1200kpa to Table 12 and the sat. temp. is 46.29 celcius but we are on 36 celcius. So ı assume it as sat. liq. when I draw the t v diagram, the enthalpy value for that 117.77 kj/kg but you use the temperature table and got another value, do ı made something wrong ?
So whether you look at a temperature table or a pressure table first doesn't make a difference. Here, the given temperature is lower than the table temperature for pressure, so it's a compressed liquid. Even if you look at the pressure table first, you will see that at the given pressure, the temperature is higher than what's given to us. So when it's a compressed liquid, we treat it as a saturated liquid at the given temperature, so you have to use a temperature of 36 degrees Celsius.
@@QuestionSolutions thx for replying, for example in 11:29 you are using he=cp((t1+t2)/2), as an example at 500 K air has cp=1.029 so h=1.029*500=514.5 but if we look it from table at 500 K h=503.02 so maybe it is negligible idk , im confused
I don;t get why you get the average of enthalypy on the 1st question. Is it because the h2 is the "end enthalpy" of the system inside so h_exit should be between h1 and h2?
I explain this at 2:20. So in simple terms, we need to make assumptions, one such assumption is that things "won't change." So to get that, we need to average out values, otherwise, solving these problems would require a lot more work, with time rate differences.
It's on my to-do list, but I probably won't get to it for some time. There are a lot of videos on mechanics of materials on TH-cam. Have you looked through them as well?
I have been waiting for your thermo videos for more than 5 months.
It's been really busy with my personal life so I wasn't able to get more videos out. 😔
your teaching skill is just awesome.
Thank you very much, I appreciate it :)
Continue doing what you're doing 🤞🏽📸❤️
You're the best🔥🔥
Kindly do videos on mechanics of materials
Thank you! I am happy to hear these videos are helpful. :)
At 8:48, I always look to the pressure tables as first, so ı looked for 1200kpa to Table 12 and the sat. temp. is 46.29 celcius but we are on 36 celcius. So ı assume it as sat. liq. when I draw the t v diagram, the enthalpy value for that 117.77 kj/kg but you use the temperature table and got another value, do ı made something wrong ?
So whether you look at a temperature table or a pressure table first doesn't make a difference. Here, the given temperature is lower than the table temperature for pressure, so it's a compressed liquid. Even if you look at the pressure table first, you will see that at the given pressure, the temperature is higher than what's given to us. So when it's a compressed liquid, we treat it as a saturated liquid at the given temperature, so you have to use a temperature of 36 degrees Celsius.
Thank you !
Very good I have midterm on Monday !
Best wishes on your midterm :)
After thermodynamics 1, start lecture series for thermo 2.
It's my humble request please.
I'll add it to my list but I am hoping to cover all the basic subjects first before going into deeper topics 👍
Do you have plans to do videos on Fluid and Solid Mechanics?
Yes, eventually, but probably not for sometime. It's on my to-do list. 👍
Love your videos but I got one question-
why are we taking the average of the Enthalpy instead of : Hf-Hi ?
Thank you very much! To help you out better, please provide me with a timestamp so I can take a look.
hey love your vids, i wanted to ask that integral cp*dT gives ht so when we take integral should not it be equal h=cp*dT + C
Thank you very much!
Could you please provide me with a timestamp? I can take a look and let you know. Thanks!
@@QuestionSolutions thx for replying, for example in 11:29 you are using he=cp((t1+t2)/2), as an example at 500 K air has cp=1.029 so h=1.029*500=514.5 but if we look it from table at 500 K h=503.02 so maybe it is negligible idk , im confused
I don;t get why you get the average of enthalypy on the 1st question. Is it because the h2 is the "end enthalpy" of the system inside so h_exit should be between h1 and h2?
I explain this at 2:20. So in simple terms, we need to make assumptions, one such assumption is that things "won't change." So to get that, we need to average out values, otherwise, solving these problems would require a lot more work, with time rate differences.
do you have videos on carnot cycles?
That's the next video coming up. Haven't been able to finish it yet :(
@@QuestionSolutions my final is in 2 weeks will you be able to finish it? 😅 excellent videos btw
@@christopherelkhoury7294 I'll try my best :)
I am really struggling with Mechanical of material class, will you ever be uploading topics about it ?
It's on my to-do list, but I probably won't get to it for some time. There are a lot of videos on mechanics of materials on TH-cam. Have you looked through them as well?
@@QuestionSolutions I did but your explanation are clear as daylight .
hi
can you make a video about friction
It's on my to-do list but I probably won't be able to get it done for some time, still working on thermodynamics videos 😅
i didnt understand last example
I am sorry to hear that. Which part did you have a hard time understanding?