How to use ci.95 with quantile to figure out the 95% confidence interval in R from a data set of 100 samples ( I am storing the median value initially). So ci.95= quantile (store_median, probs = c (.025, .975)). But this throws a syntax error “object ci.95 not found. Missing values and NaNs not allowed if na.RM is false). I am defining na.RM only in the obstat value later
I'm not exactly sure what is causing that error. In the video I assign s to be the variable as opposed to sd, so that may be it. it should be: qnorm(0.975) * s/sqrt(n) - If you named your variable s.
You would use the t-score if you do not know the true population standard deviation. In this case we do, so we would use the z-score. Sometimes the equation will just look like ave +- z * std. dev / sqrt(n). Not necessarily calling the std. dev / sqrt(n) the standard error, so some people may not have heard "standard error" before. Hopefully that makes sense!
![Confidence Interval [Simply explained]](http://i.ytimg.com/vi/ENnlSlvQHO0/mqdefault.jpg)
![Confidence Interval [Simply explained]](/img/tr.png)
helpful and straight to the point. thanks so much
Thank you!!! very concise and helpful
That mic quality though
How to use ci.95 with quantile to figure out the 95% confidence interval in R from a data set of 100 samples ( I am storing the median value initially). So ci.95= quantile (store_median, probs = c (.025, .975)). But this throws a syntax error “object ci.95 not found. Missing values and NaNs not allowed if na.RM is false). I am defining na.RM only in the obstat value later
Thank you for not using a data set and showing this -
Hello,
Could you tell me about the CI for poisson Distribution.
video on plotting a confidence ellipse is needed
life saver
Very helpful, many thanks.
if 98% CI ,what is the qnorm
HI. How can I change this 95 for 99 %? Because I want to do ANOVA
I know this is late and I dunno what I'm talking about, but probably change the 0.975 to 0.995?
i tried to use this formula but i got:
> e = qnorm(0.975) * sd/sqrt(n)
Error in qnorm(0.975) * sd : non-numeric argument to binary operator
I'm not exactly sure what is causing that error. In the video I assign s to be the variable as opposed to sd, so that may be it. it should be:
qnorm(0.975) * s/sqrt(n) - If you named your variable s.
sd is the standard deviation function, you are trying to multiply a function by a number
If you are using standard error instead of standard deviation, shouldnt you use the t-score instead of the z-score?
You would use the t-score if you do not know the true population standard deviation. In this case we do, so we would use the z-score.
Sometimes the equation will just look like ave +- z * std. dev / sqrt(n). Not necessarily calling the std. dev / sqrt(n) the standard error, so some people may not have heard "standard error" before.
Hopefully that makes sense!
@@thatrnerd4265 No, this is silly. If you know the population standard deviation then you wouldn't calculate a confidence interval for it LOL
appreciate it m8
Enlarge your data
not z-score but t-score