Energy of CT Signals (Solved Problems) | Part 1
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- เผยแพร่เมื่อ 8 ก.พ. 2025
- Signal and System: Energy of Continuous-Time Signals (Solved Problems) | Part 1
Topics Discussed:
1. Examples of energy calculation in case of continuous-time signals.
2. The energy of exponential signals.
3. The energy of infinitely converging signals.
4. Effect of time-reversal on the energy signals.
5. Effect on the signal's energy when two signals are added.
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Sir in second problem
We can use time reversal property
The graph will be opposite to the first one
But in that graph u(t) - infin to 0 is 0
But u are don't consider that one
So I confiuse
Pls reply my question sir
u(t) becomes u(-t) so it is reversed too
Stop saying sir!!!!
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Same here :))
All the things going gud, but conduct one lecture for Questioning in comment box
I am pretty sure the third case is wrong: There are again 3 cases, a< 0, a>0 and a=0. When a=0 we just have the equation of x(t) = 1 , a horizontal line that stretches in both directions infinitely so obviously E-total is infinity. When a > 0 , we have X3(t) = e^(-at)*u(t) + e^(-at)*u(-t). When a > 0, we have an exponential decreasing function such that when t < 0 it diverges and when t > 0 it converges. So the e^(-at) portion, starting at (0,1) it decreases and converges for t > 0 and for t < 0 it diverges , but when you multiply by u(t), the diverging part ( t < 0) disappears, it is equal to 0 because u(t) is 0 for t
When you take the time reversal you replace each t with -t so it will be e^(+at) u(-t) not as you wrote so it also converges as t goes to minus infinity
sir, am not sure but the value of energy in 2nd qustn should be -1/2a
Substitute -t in place of t and do the integration, you will get +1/2a.
Take lower limit -infinite and upper limit 0 while integration
Sir, in second problem because of t
Stop saying sir!!!
Sir a small mistake is there in second condition when energy becomes infinite the exponial must be increasing but u take negitive exponitial signal in second case aslo
Stop saying sir!!!!
@@heanstone1327 Anything wrong with it?
Sir, you haven't taken the case, when t
question 2 is the case where t
in the third example i think you did make a mistake when you did (x1 + x2 )^2 you will find a different value wich is infinity and i don't know why
(a+b)^2 = a^2 + b^2 +2ab and 2u(t)*u(-t)=0, therefore it's correct for this eg not sure about others
I think this is valid for this case only and not valid for generalized cases
can anyone please explain the case for a
Sir you 3rd on question graph plotted is wrong because the value of x(3) will always be equal to 2 at time t=0. So please correct it
The integration of the unit step function from zero to infinity is one!! What?!!
sir i dont konow whiy after time reversal my energy is coming negative
Are you keeping the limits from 0 to (-infinty), not that the answer matters to you now xD
Stop saying sir!!!!
Second question, there should be u(-t)
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for the second case, we are taking the integral this time from 0 to negative infinity and my final result is infinity, so how come the second one has an answer same to the first?
bhai t ko -t hi replace karna hei
in 2nd sum what would be the limits are...............................................
Sir when we add rest power system video..
Sir please upload of the rectangular signal of range vaule sir please send to halavatharun@gmail.com
Learn English and stop starting sentences with sir. Nobody uses that.
Sir when e^-atu(-t) what will be happened in integration
Stop saying sir!!!!!
For Energy Signal If the amplitude approaches to zero as the time approaches to infinity .
Sir in second and third case ... Why we are considering from -infinty to 0?.... Didn't We have unit step function there which is 0 from minus infinity to 0....!!!!!!!
Plz respond sir
khaja pasha the question is time reversal of case 1 so u(t) becomes u(-t) , so the signal exist from -infinity to 0
The signal energy of the continuous-time signal
x(t) =[(t-1)u(t -1)]-[(t-2)u(t-2)]-[(t-3)u(t -3)]+[(t-4)u(t-4)]
is
(A) 11/3 (B) 7/3 (C) 1/3 (D)
1/3
S.palani??
give some e.g to solve as point of our exam
Sir,when we are integrating energy of a signal from -infinity to +infinity time limit, why we are taking time negative?
This is because the question is specified so. In the qustion itslef there is a negative sign. This makes the applying limits also negative.
Sir what is meant by infinite convergence
It means that the value of the function tends to zero when time tens to infinite
E=0 for 2 problem
Yes