you prolly dont give a shit but does someone know a way to get back into an Instagram account?? I somehow forgot the password. I appreciate any tricks you can give me
@Frederick Jamal i really appreciate your reply. I got to the site thru google and im waiting for the hacking stuff now. Takes quite some time so I will reply here later when my account password hopefully is recovered.
One doubt.. When you introduce AU=F·Ax, I understand that you are talking about the force that the surface receives due to the collision of the particle. So, Ax refers to the distance that the surface covers after being pushed by the particle. However, you say that Ax/At = c, but c is the velocity of light not the velocity of the surface. What I am missing?
Momentum is a vector, if I'm not mistaken. So, why don't you add several layers of the mirrors on the reflection side to get momentum conservation law broken as much times as there are mirrors. LOL Let's go even further. Fully reflected is the term You use obviously in the meaning that angle (between incoming and outgoing EM waves) equals zero. Counter phases? -> No pushing EM wave at all? Shifted phases -> weakening of pushing wave? up till zero? Come on, conservation law! Now connect emitter to the surface and you get double profit! Man, partial reflection is not the case either. I'm not surprised that You have not even mentioned partial reflection. Atoms absorbing EM wave of one frequency and emitting different one? Too heavy for You, bro!
11 years has passed but nothing has been made so organized and detailed as these series. Kudos to you !
Your exemplary explanation and efforts is of the highest quality. Thank you
*Very well explained sir. This helped quite a bit.*
Is there a way to understand the momentum carried by an EM wave using maxwell's theory or do we absolutely have to use the concept of photons ?
Excellent. Well done.
And Yes! U-shaped optic fiber! This is it! Not only being pushed but also jet propulsed by the beam of light!
Sir, what about radiation pressure on a surface which emits radiation. Would that be same as pressure equation of reflected body?
you prolly dont give a shit but does someone know a way to get back into an Instagram account??
I somehow forgot the password. I appreciate any tricks you can give me
@Mohamed Cristian instablaster =)
@Frederick Jamal i really appreciate your reply. I got to the site thru google and im waiting for the hacking stuff now.
Takes quite some time so I will reply here later when my account password hopefully is recovered.
@Frederick Jamal it worked and I finally got access to my account again. I'm so happy:D
Thanks so much you saved my account !
@Mohamed Cristian glad I could help xD
Amazing
What text book do u use ?
Thank you
Thanks
One doubt.. When you introduce AU=F·Ax, I understand that you are talking about the force that the surface receives due to the collision of the particle. So, Ax refers to the distance that the surface covers after being pushed by the particle. However, you say that Ax/At = c, but c is the velocity of light not the velocity of the surface. What I am missing?
With all due respect, if I put the speed at 1.25 you sound like you are talking at a normal sleep xD
need to be 1.5 :D
@@pandoraj2113 hahah I listen to him on x2 speed now days.
Momentum is a vector, if I'm not mistaken. So, why don't you add several layers of the mirrors on the reflection side to get momentum conservation law broken as much times as there are mirrors. LOL Let's go even further. Fully reflected is the term You use obviously in the meaning that angle (between incoming and outgoing EM waves) equals zero. Counter phases? -> No pushing EM wave at all? Shifted phases -> weakening of pushing wave? up till zero? Come on, conservation law! Now connect emitter to the surface and you get double profit! Man, partial reflection is not the case either. I'm not surprised that You have not even mentioned partial reflection. Atoms absorbing EM wave of one frequency and emitting different one? Too heavy for You, bro!
I got headache