because copper sulpghate is in excess, so it's the reactant you want to calculate, copper sulfate + iron is a product, you are trying to find a reactant
If the question was worded so that it said decrease in temperature would that mean it would be endothermic and so a +ve energy value is given? Also thank you so much!!
Hey great video but what would happen if the amount of moles you had for the metal was greater than the moles of acid if the acid was in excess if that makes sense (if the molar ratios werent 1:1) would u still use the higher mole value as it is if it is the limiting reactant? thanks a lot man
Thankyou for the video, really helpful! If you had the reactants in a 2:1 ratio, and you calculated the number of moles of each of them that reacted, which one would you use in the equation. E.g. if you had 2mol of A and 4mol of B reacting, would you use 2 or 4 mol? Thanks.
Wouldn't the mass of the iron need to be included because the energy is released when the iron is added. So wouldn't the energy then be seen to heat up the solution with the iron in it ?
Perfect video as usual. Just a quick question, if it doesn't matter if you have change in temperature in K or Celcius then why when converting Celcius into K by adding 273 it will give you a different value in the end, a different value for Change In Enthalpy? Also in the exam if we are given temperature change in Celcius should I not bother changing it right?
+KaBoom No because a temperature change in Celsius is the same as Kelvin. The conversion is not needed. However it is important to know that the change in temperature is Kelvin. Hope this helps!
you are actually brilliant at explaining
Why did you use the mass of the copper sulfate instead of the mass of coffer sulfate+ iron when you calculated q?
because copper sulpghate is in excess, so it's the reactant you want to calculate, copper sulfate + iron is a product, you are trying to find a reactant
This is amazing! I was wandering if the limiting reactant and excess agent applies to the neutralisation reactions as well?
+Shops xox Hi. Thanks very much! Yes it will apply to neutralisation reactions too. Happy calculating!
If in the equation we don't have the same ratio (1:1), then do we multiply and then select the moles to put in the formula?
Thanks! Waiting for Part 4. :)
+Saadz RS No problem. Part 4 is here - th-cam.com/video/T-ev2YIMWR8/w-d-xo.html
another good video allery could you send me a link to your calorimeter questions
+Mirwis Nasseri Thanks very much! Here is the link - th-cam.com/video/GBtVuztQDMQ/w-d-xo.html
Thank you so much 💖😫 This was very very helpful to me 😫💖💖💖
Glad it was helpful!
If the question was worded so that it said decrease in temperature would that mean it would be endothermic and so a +ve energy value is given? Also thank you so much!!
+Mo Tayee Yeh you would change the q value to a positive sign.
Hey great video but what would happen if the amount of moles you had for the metal was greater than the moles of acid if the acid was in excess if that makes sense (if the molar ratios werent 1:1) would u still use the higher mole value as it is if it is the limiting reactant? thanks a lot man
Yes that's right.
any videos on redox, oxidation and reduction?
Thankyou for the video, really helpful! If you had the reactants in a 2:1 ratio, and you calculated the number of moles of each of them that reacted, which one would you use in the equation. E.g. if you had 2mol of A and 4mol of B reacting, would you use 2 or 4 mol? Thanks.
Finally, some good videos! Does this follow the AQA spec?
+James P Thanks very much! It certainly does.
+A Level Chemistry Revision Videos by Allery Tutors ah right, apparently I study OCR Chemistry, are the specifications broadly the same?
+James P Yes, the majority is the same. The videos also cover content specific for OCR too.
Wouldn't the mass of the iron need to be included because the energy is released when the iron is added. So wouldn't the energy then be seen to heat up the solution with the iron in it ?
Perfect video as usual. Just a quick question, if it doesn't matter if you have change in temperature in K or Celcius then why when converting Celcius into K by adding 273 it will give you a different value in the end, a different value for Change In Enthalpy? Also in the exam if we are given temperature change in Celcius should I not bother changing it right?
+KaBoom No because a temperature change in Celsius is the same as Kelvin. The conversion is not needed. However it is important to know that the change in temperature is Kelvin. Hope this helps!
why we used c=4.184 which is for water in the calculations...... I am confused?
btw i still watch ur videos :p
Why are we not interested in the iron bit? 3 mins 10 secs?
👌🏻👌🏻💯