PROBLEM ON CONTINUOUS RANDOM VARIABLE | PQT | PRP| PAS| UNIT-1 | VIDEO-15

UNIT I PROBABILITY AND RANDOM VARIABLES
Probability - Axioms of probability - Conditional probability - Baye‘s theorem - Discrete and continuous random variables - Moments - Moment generating functions - Binomial, Poisson, Geometric, Uniform, Exponential and Normal distributions.

[@animeluvr0107]

my toxic brain thinks that they can solve the problem in exam just by watching this watching this video without any practice😅

[@NavelsUrith]

IN 5:51 mam i can understand everything but how x (cube) by x^3/3 i got cube by intergrating but how by /3 appears

[@engineeringmathematics9006]

If you integrate x^2 you get x^/3, out side 2/6=1/3

[@kaviarasu8648]

E(x)=0 how mam
Right ans:1.5 தான் mam

[@engineeringmathematics9006]

X^2/2)-3 to 3= 9/2-9/2=0

[@kaviarasu8648]

Mam
1/6 integer x dx -3to3
Ithai integrated pannum pothu
Ans 1 varum
Eppadi mam 0 varum

[@engineeringmathematics9006]

@@kaviarasu8648 what do u get when u integrate x

[@kaviarasu8648]

9/2+9/2 varum mam

[@engineeringmathematics9006]

@@kaviarasu8648 (-3)^2=9

[@cookingco-ci1js]

Mam in 5.55 .if we procced the sum by normal integrating method .we are getting 9/2 but there its 3 .how?

[@engineeringmathematics9006]

1/6(27/3+27/3)=3
If u do Normal integration then also you get the same

[@cookingco-ci1js]

Yes mam .got it .thanks for explaining

[@Sasikala21AI050]

For variance -3 to +3 limit pota 0 thana mam varum in direct integration

[@engineeringmathematics9006]

It's 0 only for odd functions, not for all

[@mohammedmuzammil3124]

Mam make a video on unit wise important questions

[@jeyakumaruma2892]

Tq for clear explanation

[@bijilistatus4705]

Clear explaining mam thank you so much