Hello, I am wondering why the dissolved O2 would reach saturation at steady state. The rate equation for the dynamic system is dC/dt=kLa(C*-C)-Q(consumption rate by organism), correct? So at steady state, with a non-zero consumption rate, the concentration "c" can never equal the C*, or it would be 0=0-Q. I cannot find a solution to this issue, and I also cannot derive the linearized equation you had provided in this video.
![โรงเรียนห้ามรัก โดนจับได้ตาย...!! [เอิร์นไดเม่]](http://i.ytimg.com/vi/4u02Sbr556Q/mqdefault.jpg)
![ตีสิบเดย์ [FULL] | เปิดใจ "อาจารย์ เบียร์ ฅนตื่นธรรม" นักสนทนาธรรมสายดุดัน!](http://i.ytimg.com/vi/vqaBI_mnoDk/mqdefault.jpg)
Happy to share!!
Hello, I am wondering why the dissolved O2 would reach saturation at steady state. The rate equation for the dynamic system is dC/dt=kLa(C*-C)-Q(consumption rate by organism), correct? So at steady state, with a non-zero consumption rate, the concentration "c" can never equal the C*, or it would be 0=0-Q. I cannot find a solution to this issue, and I also cannot derive the linearized equation you had provided in this video.
Very nice explanation...on point .. thanks for making it so easy..i have exam today for bioprocess 🥹
Thank u so much...
Awesome
Thank u so much
Thank you for a nice explanation. I assumed that this system DO control is at 78%. Is that correct?
Yes, Oxygen Saturation % is 78%
Superrr
Thank u so much
Nice 👍
Thank u so muchh
😇
everything is well executed except the background music. kindly don't use it thank you.
Please remove the music from video
Sure..