Nice video. unfortunately when t = logx, dt/dx = 1/(xln10) and not 1/x I got an answer more along the lines of: 1/y = x*logx*10^(-logx) + (x*10^-logx )/ (ln10) + C
There is one mistake here, at last your answer should be 1/y=log(x)-1+xc 1. You wrote plus instead of minus between logx and q 2. Correct me if I am wrong(because on 2nd time integrating according to u.v formula , again minus sign should come, please lemme know if I am wrong
Brother, there is no mistake, you are making a mistake in understanding . we let 1/x=e^-logx . And put the value of e^-logx in tha end Ok There is no mistake in the U.V formula
i'm from Cambo Sharing Tech . good video sharing
Well explained
Aap ne bahut acha samjaya sir thank you very much
Very good explanation
Nice video 👍
Upload more questions like this ❤
Ok
Thank you so much 😊
Sukriya sir
nice 🤗
good
Nice video. unfortunately when t = logx, dt/dx = 1/(xln10) and not 1/x
I got an answer more along the lines of:
1/y = x*logx*10^(-logx) + (x*10^-logx )/ (ln10) + C
Very good sir
Nice work
Nice video
Good info
Bhaiya m❤❤❤❤❤❤
Thank you
Tq sir ❤
Welcome
Good job
Nice
nice
Smjhane ka trika thoda thik kr lijiye sir😊
Ab phele se better hai
Nice work 👍👍👍
There is one mistake here, at last your answer should be 1/y=log(x)-1+xc
1. You wrote plus instead of minus between logx and q
2. Correct me if I am wrong(because on 2nd time integrating according to u.v formula , again minus sign should come, please lemme know if I am wrong
Brother, there is no mistake, you are making a mistake in understanding . we let 1/x=e^-logx . And put the value of e^-logx in tha end
Ok
There is no mistake in the U.V formula
watch the video carefully again
My bad bruh, that's absolutely correct, my bad, and thanks for rectifying❤
Hello Ants😉
Clear nh dikhayi de ra sir😢
Ye kafi purani video h latest video esi nhi h ok unme clear dikhega or gar koi dikkat h to quality badha lo
Good night
Sir makkhi ko mar do video disturb ho raha hai 😂
Makkhi nhi marni chahiye
Very good explanation