Sir in the electronic configuration series we were taught to write 5s after 4p sir but for this CoF6 why are we taking 4d after 4p sir.pls clarify this doubt sir Thank u
Because fluoride is a weak legend it will not make any pair so electrons remain para magnetic..now we want total 6 orbital so we introduce 4p also ...so hybridization will be sp3d2..means total 6
Sir You Are My Inspiration........😇
Keep Growing Sir......
Sir i have studied somewhere when co is in +3 oxidation state all ligand behave as strong field ligand . Plz reply 🙏
Can you find something tell me bro
Yes bro iam also searching for the answer why F is WFL while Co is in +3 oxidation state, bro if you know the answer then please explain to me
@@ArunKumarVandrasi mera bhi ye hua ki mene iss question ko exam mai dimagmetic likh diya
In case of co+3 and those ligand having oxygen as donor only thoda act as strong ligand
Ab koi tension nhi hai result acha agya
Thank you very much sir it helped a lot🙏🙏😇
Amazing explanation sir❤
Sir in the electronic configuration series we were taught to write 5s after 4p sir but for this CoF6 why are we taking 4d after 4p sir.pls clarify this doubt sir Thank u
Because fluoride is a weak legend it will not make any pair so electrons remain para magnetic..now we want total 6 orbital so we introduce 4p also ...so hybridization will be sp3d2..means total 6
Sorry we will introduce 4d after 4p
Thank you very very much sir 😊
How do we determine the low field from the high field? I am a bit confused.
Amazing sir 😊🎉
Thank you very much sir 🙏 😊
Thanks sir 😊😊
sir after 4p we have 5s orbital available and it should be filled first according to aufbao rule so why we didn't used 5s orbital?
Same question
Thank you sir❤❤❤
Please share to your friends and classmates
ty
Thank you sir
Please share to your friends
I understood very well
Please share to your friends and classmates
Thank you sir