At 06:49, While evaluating the impulse momentum, U considered the velocity of system is "V" & change as V - 0, since the compressible fluid under consideration is getting compressed between the wave front & the displaced piston. So the velocity of total mass will not be equal to "V" as portion of mass in contact with piston is moving at "V" & the velocity of portion of mass behind wave front is "0". It will be absolutely ridiculous to think that entire mass is moving at "V" , in which case there will be no compression & no change in density. Even the first step of your derivation of law of conservation of mass would not be applicable as the system has exited wave front at velocity "V". The velocity should be an average taken over the entire mass.
The pressure change of the system under consideration will happen to "p+dp" after completion "of time interval dt" at point x. Do consider that the wave front , the disturbance generated by the moving piston, has started to travel at time t=0 travel at speed of sound & will traverse length L after dt time ( hence u could use the equn L=c x dt ). so what change has actually been communicated at t=0 when p = p only. Since this is dynamic change which has not attained its full value until the end of dt. so the pressure "p+dp" will reach the value after completion of dt, so the pr at point L will be at "p+dp" after a time = not "dt" but " L/c +dt " .
the velocities of sound in air and water are 336 m/s and 1470m/s. two sources producing waves of wavelength 6m and 7m sounded together will produce beats
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Thank you so much. I had hard time understanding Thermodynamics textbooks and now it is clear!
At 06:49, While evaluating the impulse momentum, U considered the velocity of system is "V" & change as V - 0, since the compressible fluid under consideration is getting compressed between the wave front & the displaced piston. So the velocity of total mass will not be equal to "V" as portion of mass in contact with piston is moving at "V" & the velocity of portion of mass behind wave front is "0".
It will be absolutely ridiculous to think that entire mass is moving at "V" , in which case there will be no compression & no change in density. Even the first step of your derivation of law of conservation of mass would not be applicable as the system has exited wave front at velocity "V".
The velocity should be an average taken over the entire mass.
The pressure change of the system under consideration will happen to "p+dp" after completion "of time interval dt" at point x. Do consider that the wave front , the disturbance generated by the moving piston, has started to travel at time t=0 travel at speed of sound & will traverse length L after dt time ( hence u could use the equn L=c x dt ). so what change has actually been communicated at t=0 when p = p only. Since this is dynamic change which has not attained its full value until the end of dt. so the pressure "p+dp" will reach the value after completion of dt, so the pr at point L will be at "p+dp" after a time = not "dt" but " L/c +dt " .
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TQ so much sir
the velocities of sound in air and water are 336 m/s and 1470m/s. two sources producing waves of wavelength 6m and 7m sounded together will produce beats
Really nice sir
nice video....quite helpfull in clearing my concepts
you are good in lecture sir thank you alot
Thank you so much sir , you are great 👍
Thank you sir
I am very happy by learning your concept on this topic.
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why pressure wave gets greater in fluid ? is there any limits? is that limit called as sound speed?
The molecules are closer together so transmit waves faster. Has a higher density of material..
F = m * a , m = D/v higher D makes higher m makes higher F with the same acceleration applied to the different material
Thank u sir
Thanks bhai.
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