Eddie Woo helped me understand a CS problem from one of his videos back in 2012. Ever since I've been subscribed to this channel. I am no math guy who watches his every video but I am happy he pops up on my TH-cam timeline every now and then 😂
5:45 Multiplying by purely imaginary numbers is *not* a pure rotation (except for i and -i). Multiplying by numbers with modulus |z| = 1 is a pure rotation.
and here I thought a rotation had to do with a change in argument (even if the resultant argument is the same as the initial) and nothing about the modulus or magnitude regarding initial and terminal ... purely, but I'm not a mathematician, so what do I know, really? (Nor and English major with that run-on sentence with no initial capital ... and to start with 'and' ...)
@@seanclough7810 True, rotation is when the argument changes. The "pure rotation" is when also the modulus stays the same. In term of the w → z·w map (multiplication by z), it's a pure scaling (without rotation component) when z is positive real (i.e. arg(z) = 0) , and a pure rotation (without scaling component) when |z| = 1. (When we have both, it's z = 1 (a trivial scaling and trivial rotation).)
@@PauxloE Obviously I know not the word set used for this stuff. Going to try and spell vernacular now. But you wom't catch me calling an eigenvector with the same magnitude by that name. That is true enough.
Awesome thank you so much sir I have studied the complex numbers the years before in my secondary school but i didn't understand it, but now after watching your lessons and explications i can solve hard exercises Thanks a lot sir you're the best 👏😁
"Good morning Aaron, thanks for joining us"
Classic! :) :)
Eddie is the best maths teacher ever , convince me otherwise
Hi from France, your prononciation of "De Moivre" was kinda fun, you were almost at the right pronunciation haha ; thanks for the lesson
Eddie Woo helped me understand a CS problem from one of his videos back in 2012. Ever since I've been subscribed to this channel. I am no math guy who watches his every video but I am happy he pops up on my TH-cam timeline every now and then 😂
i have absolutely no reason to be learning this stuff but it's fun
Same
Sir love from India
I love maths
Im from india 🇮🇳 sir thank you so much 🙏
India yay
5:45 Multiplying by purely imaginary numbers is *not* a pure rotation (except for i and -i). Multiplying by numbers with modulus |z| = 1 is a pure rotation.
and here I thought a rotation had to do with a change in argument (even if the resultant argument is the same as the initial) and nothing about the modulus or magnitude regarding initial and terminal ... purely, but I'm not a mathematician, so what do I know, really? (Nor and English major with that run-on sentence with no initial capital ... and to start with 'and' ...)
@@seanclough7810 True, rotation is when the argument changes. The "pure rotation" is when also the modulus stays the same. In term of the w → z·w map (multiplication by z), it's a pure scaling (without rotation component) when z is positive real (i.e. arg(z) = 0) , and a pure rotation (without scaling component) when |z| = 1. (When we have both, it's z = 1 (a trivial scaling and trivial rotation).)
@@PauxloE Obviously I know not the word set used for this stuff. Going to try and spell vernacular now. But you wom't catch me calling an eigenvector with the same magnitude by that name. That is true enough.
I need more!!! Thxxxxx
Lovely presentation thanks.
I am from india
You are the best
Literally gonna pass maths because of you
Awesome thank you so much sir
I have studied the complex numbers the years before in my secondary school but i didn't understand it, but now after watching your lessons and explications i can solve hard exercises
Thanks a lot sir you're the best 👏😁
Sir, Can you tell which writing software or app are you using here ?
I'm happy
Love u sir
DHAMALASTICB👍🏻❤️
To the Quik: Great Teacher! A [Real Number] attached by an [Imaginary Number] = a [Complex Number]! (i)!
Amen.
This is an excellent lesson to fall asleep
Dam that looks super hard