Meshing Tips: Hourglass, Zero Energy Modes, Shear Locking, Volumetric Locking - ABAQUS Tutorial
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- เผยแพร่เมื่อ 23 ส.ค. 2024
- This video will give you an overview of using different element formulations in ABAQUS CAE.
You will learn about:
abaqus meshing techniques
- Hourglassing / zero energy modes / parasitic shear strains
- Enhanced hourglassing control in abaqus
- ways of removing hourglassing
- shear locking and how to get rid of it
- volumetric locking and how to get rid of it
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Thank you for sharing! was encounter some issue due to hourglass E and about to preform similar study to find solution. now you did it for me~~thx~~~
Hi thank you, could you povide the values of the rection forces at the left side for each case?
I will check and get back. Thank for checking not too don’t forget 😇
This is a great channel, the person is clearly knowledgeable. Can you please Make a video on GTN model on a dissimilar weld CT specimen?
Thanks for liking. If you could please send me more details on the model. I will be more than happy to make a video. 3minutesengineeringconcepts@gmail.com
Hello 3MEC, thank you for all your great work !
I need to model delamination (that starts from teh pick of a transverse cracking) of a composite material on abaqus and I only have the 6 engineering constants, is there a way to do it without needing more properties? if yes then how ? I really need this, thank you.
Thanks for appreciating. If I understood you correctly for Delamination you will need delamination strength, etc. One way could be to use cohesive elements or interface crack propagation criteria
@@Professor3MEC here's a description from the article of the original model I'm trying to model on abaqus : This investigation has been implemented by
element analysis. Fig. 3 shows an example of the mesh-
ing used. The tensile load was applied via prescribed
longitudinal displacements of the extreme nodes (nodes
A to B and B to C). The conditions of symmetry lead to
suppress the transverse displacements of the nodes of
the middle plane CF and the longitudinal displacements
of the nodes D to E. To analyse the delamination
between the 0 and 90 layers, nodes were splitted into
pairs of nodes on the delaminated part GE: one node in
the 0 layer and one node with the same coordinates (in
the non-deformed state) in the 90 layer. The relative
slipping between the 0 and 90 layers was considered
by joining the transverse displacement of a pair of
nodes. The friction between the 0 and 90 layers was
introduced by prescribing a longitudinal stress on each
element of the delaminated part.
What I did : modeled the composite plate, applied the symmetry conditions and the load, did a cut between the 0 and the 90 layer to model delamination, couldn't undertand how to model the rest of the description (I'm not very familiar with abaqus), the result was obviously different, if you can advise me on what to do with the rest then I'd be very grateful, if you have time and would want to take a look on the model, please leave me an email I can contact you on.
Thank you !
@@nadj_b 3minutesengineeringconcepts@gmail.com
please me details on this
@@Professor3MEC Sent, thank you so much!
DEAR BROTHER
CAN U PLEASE TELL, HOW TO APPLY A HIGH STRAIN RATE ON THE UNIAXIAL TENSION TEST IN ABAQUS/EXPLICIT?
Hello, For any time dependent loading you will have to use amplitude function. There are a number of videos in my channel discussing about it. However below one might be more relevant on how to define time dependent loading, i.e. in your case high strain rate loading.
@@Professor3MEC YA I GOT UR POINT. HOWEVER, WHEN I GO TO PERFORM A TENSILE TEST AT A HIGH STRAIN RATE AND ITS TOTAL TIME IS COMING OUT TO BE AS 0.001 OR 0.0001 SECONDS THEN THE TEST RESULTS IN TERMS OF TENSILE STRESS-STRAIN CURVE IS COMING OUT IN CYCLIC MODE. DO U HAVE ANY SUGGESTIONS REGARDING THIS?
@@Professor3MEC BASICALLY I WANT TO PERFORM DIFFERENT CONSTANT HIGH STRAIN RATE TENSILE TESTS...
@@kamrankamran1071 well it will be difficult to speculate what is going wrong. First thing to check would be the definition of amplitude function?
lets see if strain rate is 1000 /sec and based on this the displacement that needs to be applied is 1mm per 0.001 second then displacement amplitude function should be like below.
0., 0.
0.001, 1
this means displacement will increase linearly, i.e. constant velocity/strainrate.
good luck
@@Professor3MEC but how much total time should I given? would it be the same as 0.001?
Dear sir, i have few quires related to modelling and simulation (SMA material) in Abaqus, can i get your Email so, that we can interact.
Thank you
Regards,
Saiyad
3minutesengineeringconcepts@gmail.com