Network Engineer REVEALS easiest method to Subnet without a Calculator

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  • เผยแพร่เมื่อ 24 ม.ค. 2025

ความคิดเห็น • 13

  • @LarryTravels80
    @LarryTravels80 12 วันที่ผ่านมา

    🔥

  • @wfw_kylle22
    @wfw_kylle22 19 วันที่ผ่านมา +1

    happy new year
    and thank you bro🫡💯🔥 really enjoyed the video

    • @jongreenit
      @jongreenit  19 วันที่ผ่านมา +1

      Thanks, glad to hear you enjoyed the vid! More to come.

  • @FabianEdouard
    @FabianEdouard 19 วันที่ผ่านมา

    Hey Jon - I've been looking into getting a mini-pc/server to start up my eve-ng lab journey - how's your mini-pic (Minisforum UM773 Lite) been? Any issues?

    • @jongreenit
      @jongreenit  19 วันที่ผ่านมา

      Hi Fabian, that's awesome to here. I enjoyed it for the time that I had it. The UM773 will last most folks starting out a long time if you sole purpose it for labbing. However in full transparency I did end up returning it for a more beefier travel server for my work needs. Though I do miss the size of the UM773 as it incredibly small in comparison.

    • @FabianEdouard
      @FabianEdouard 19 วันที่ผ่านมา

      Thanks for the reply and transparency! I know you’re in a Sales position now, but are there any plans on expanding into videos about protocol redistribution, MPLS, NAT etc? I find your content extremely helpful w/ the way you explain & showcase different technologies!

    • @jongreenit
      @jongreenit  18 วันที่ผ่านมา

      @@FabianEdouard No problem, and glad to hear you've been enjoying the content. As I've begun re-studying for another JNCIE certification my goal is to begin posting more network lab tutorials this year, so stay tuned!

    • @FabianEdouard
      @FabianEdouard 18 วันที่ผ่านมา

      @@jongreenit This is great news! Good luck with studying and Happy News Years!

    • @jongreenit
      @jongreenit  18 วันที่ผ่านมา +1

      Much appreciated and happy new years to you as well!

  • @walterbortone6410
    @walterbortone6410 19 วันที่ผ่านมา

    The answer would be:
    1. 172.16.31.254 last host
    2. 172.16.31.255 Broadcast
    3. The next network as you show would be 172.16.32.0/20
    Let me know if its correct.

    • @jongreenit
      @jongreenit  19 วันที่ผ่านมา

      You crushed it! How'd you find the process?

    • @walterbortone6410
      @walterbortone6410 19 วันที่ผ่านมา

      I took the 32 value as you showed. Each 32 value would be a new subnet.
      Let me know if that analysis is correct.

    • @jongreenit
      @jongreenit  19 วันที่ผ่านมา

      @@walterbortone6410Your answer was correct but the logic is not quite there. Double check the Block size value used for the /20 and your logic will match. Once you've had a chance to confirm the block size value, see which subnet comes after 172.16.32.0/20.