+2 Maths Onam Exam | Chapter 5 | Continuity And Differentiability Part 1 | Oneshot | ExamWinner +2
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- เผยแพร่เมื่อ 26 ก.ย. 2024
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Gear up for your Plus Two Maths Onam Exam with our focused session on Chapter 5: Continuity and Differentiability (Part 1)! 📐 This comprehensive review will cover essential concepts such as limits, continuous functions, and the basics of differentiation. Perfect for quick revision, this session is designed to clarify key ideas and boost your confidence before the exam. Don’t miss out on mastering these fundamental topics for success! 🌟📚
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13:58 Allen sir rocked students shocked 👀
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Ans ; 2cos(tane^2x+3).sec²(e^2x+3).e^2x+3
Yes good class ❤
Class starts at 2:44
Cos(tan(e^2x+3)) . sec^2(e^2x+3) . e^2x+3 . 2
Thank you sir 💛👍🔥🔥🔥🙏🙏
Super class❤❤full clear ❤❤🔥🔥🔥🔥🔥🔥🔥
Sir always very thankful for your efforts ❤❤❤
By the way the ans is : 2*Cos(tan(e^2x+3))*Sec²(e^2x+3)*e^2x+3
An:2 cos (tan e^2x+3).sec^²(e^2x+3)e^2x+3
2cos(tan(e^2x+3))sec^2(e^2x+3)(e^2x+3)
Useful class ❤❤
dy/dx=cos[tan(e^(2x+3))]*sec²(e^(2x+3)*2[e^(2x+3)]
Thankyou Allen Sir🎉❤ for your great effort❤🎉
Thankyou Exam winner family🎉❤
5:22
Cos(tan(e^2x+3))sec²(e^2x+3)(e^2x+3)×2. Sirr cls valare help full aayirunnu.... Bakki topics nu katta waiting aqnuu❤️🥰
dy/dx=cos[tan(e^(2x+3))]*sec²(e^(2x+3)*2[e^(2x+3)]
Thankyou Allen sir.....🎉❤Super class🎉❤
Nice class ❤
Ans:cos(tan(e^(2x+3))×sec2(e^(2x+3))×e^(2x+3) ×2
THANKYOU SIR FOR YOU EFFORT❤️
22:14 😂
Cos(tan(e^2x+3).sec^2(e^2x+3).e^2x+3.2
Everything crystal clear ❤
13:58 😅 14:21 💀
Enik mathrano mnsilakanje🥲🥲 continuity
Ans) 2cos(tan^2x+3).sec²(e^2x+3).e^2x+3.
❤
One of the best class ❤
Cos(tan(e^2x+3).sec^2(e^2x+3).e^2x+3
Good class😍😍
Thankyou sir❤️❤️❤️❤️❤️👍🏻👍🏻🔥
Ans: 2cos(tan(e^2x+3))(sec^2+3))(e^2x+3)
ans; 2cos(tane^2x+3).sec²(e^2x+3).e^2x+3
thanks for this wonderful class sir
2Cos(tan(e^2x+3)).sec²(e^2x+3).e^2x+3
2cos(tan^2x+3).sec²(e^2x+3).e^2x+3 - ans.
2cos(tan e^2x+3))sec^2(e^2x+3)(e^2x+3)
14:22 💀 😂
Allen sireeyy thnkuuh so much.....class nannayi manassilaay💗💗💗🤩
Ans:2cos(tan e^2x+3)•sec²(e^2x+3)•e^2x+3👩🏻🦯
2cos(tane^2x+3).sec²(e^2x+3).e^2x+3
Thanks allen sir💥
2cos( tane^2x+3.sec^2(e^2x+3).e^2x+3
Thankyou allen sir❤❤
Thankyou sir ❤
Ans:2cos(tan(e^(2x+3)))sec^2(e^(2x+3))2e^(2x+3)
Alen sir power❤🔥
Answer:-
2cos(tan e^2x+3).sec²(e^2x+3).e^2x+3
Sir poly ❤
2cos(tan e^2x+3)sec^2(e^2x-3)(e^2x+3)
Answer:2Cos(tane^2x+3) * sec^2(e^ 2x+3)*e^2x+3❤❤❤🎉🎉🎉 Adipoli class 💪💪❤️❤️❤️💪
Ans:2cos(tan^2x+3).sec^2(e^2x+3).e^2x+3
Thankuu sirr
Cos(tane^2x+3) sec^2
(e^2x+3) e^2x+3
Ans is 2cos (tan e^2x+3).sec^2 (e^ 2x+3).e^2x+3
Cos(tan(e^2x+3).sec^x(e^2x+3).2e
Answer: 2 cos (tan e^2x+3) sec²(e^2x+3) × e^2x+3
Thank u Allen sir ❤🙌
2cos(tane^2x+3)*sec²(e^2x+3)*e^2x+3 ❤❤❤❤❤❤❤
Ans=cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3
❤️Thanku exam winner❤️
Ans: 2Cos(tan e^2x+3).sec² (e^2x+3).e^2x+3
2cos(tan(e^2x+3)*sec^2(e^2x+3*e^2x+3 is the answer
Thank you soo much for your effort sirr 🎉
Very useful class❤🎉
Answer =2.Cos[tan (e^2x+3)].Sec^ (e ^ 2 x+3).e ^2x+3
Ans)2cos(tane^2x+3).sec²(e^2x+3).e^2x+3
2 cos(tan( e^2x+3))(sec^2(e^2x+3)) (e^2x+3)
Crystal clear tnk u Allen sir ❤
Yes class is super ❤
Ans) dy/dx = 2cos (tan (e^2x+3)) sec² (e^ 2x+3) e^ 2x+3
Thank you so much Sir🔥❤
Baakki portions nale mrning eppozhelm live il edkamo Sir? 💖
Ans: 2cos(tane^2x+3).sec²(e^2x+3).e^2x+3🖤
Thank you sir ❤
2Cos(tan e^2x+3) Sec²(e^2x+3) e^2x+3
Thank you sir💖for such a nice class
2cos (tan e^2x+3).sec²(e^2x+3).e^2x+3 is the answer. Thankuu examwinner for the double dhamakka seriess🎉❤❤
Ans:cos ( tan(e ^ (2x + 3)) * sec(2) * (e ^ (2x + 3)) * e ^ (2x + 3) * 2❤
Differentiability 🧠
Onam exam n continuity vare ollu 🫠
Ans:2Cos(tan(e^2x+3)).sec²(e^2x+3).e^2x+3
Tnquu sir 🤍
Ans:cos ( tan(e ^ (2x + 3)) * sec(2) * (e ^ (2x + 3)) * e ^ (2x + 3) * 2 Thanks
dy/dx =
2cos(tan(e^2x+3))×sec^2(e^2x+3)×e^2x+3
Thank youh Allen sireeh
2cos(tan(e^2x+3).sec^2(e^2x+3).e^2x+3 ❤ class full on power sir powli😊😊😊😊😊😊❤❤❤❤❤❤❤❤
Exam Winner family 💪💪💪💪
Cos(tan(e^2x+3))*sec²(e^2x+3)*e^2x+3*2+0 thank you so much sir 🥹
Thankyou sir ❤❤😊
Ans =2cos(tan^2x+3).sec²(e^2x+3).e^2x+3
Thankyou Allen sir... For this amazing class❤
Ans:-Cos(tan(e^2x+3))*sec²(e^2x+3)*e^2x+3*2+0 thank you so much sir for this great class !!😊
2 Cos (tan(e^2x+3)).Sec²(e^2x+3).(e^2x+3)
Thank u Allen Sireyyy .... ✨🫶💗
y' = cos(tan(e^(2x) + 3)) * (sec^2(e^(2x) + 3)) * (2e^(2x))
Thanku Allen sir❤️✨
dy/dx=
Cos(tan(e^2x+3))•sec²(e^2x+3)•(e^2x+3)•2
Answer-2cos(tane^2X+3). Sec²(e^2X+3) . (e^2X+3)
Thank you sir🎉🎉❤❤
Ans:2Cos (tan e^2x+3)* sec^2(e^2x+3)*e^2x+3
Adipowoli class , thankyou for valuable class❤❤
2cos (tan e^2x+3) * sec² (e^2x+3) * e^2x+3
Thankyou❤
Thankyou sir❤
Answer:dy/dx =2 cos(tan e^2x+3).sec²(e^2x+3).e^2x+3❤
Its 2cos(tan e^2x+3).sec²(e^2x+3).e^2x+3
dy/dx=2cos(tan(e^x+3)).sec^2(e^2x+3).e^2x+3
2cos(tane^2x+3).sec²(e^2x+3).e^2x+3
Thankyuuh sirrr for yourr valuable classess🥺🖤🖤
Ans=2cos(tan^2x+3).sec^2(e^2x+3).e^2x+3
Seen class thanne❤❤
dy/dx=cos(tan( e^2x+3)).sec^2(e^2x+3).e^2x+3
Adipoli class ❤❤
2cos(tane^2x+3).sec²(e^2x+3).e^2x+3 is the ans
Nice class♥️♥️♥️
Ans:2cos(Tan^2x+3).sec²(e^2x+3).e^2x+3
Ans; 2cos(tan(e^(2x+3))).sec²(e^(2x+3).e^(2x+3)
Thanks for giving your best sir❤❤❤
2cos(tane^2x+3).sec^2(e^2x+3).e^2x+3
❤❤❤ Adipoli siree
ANSWER Cos(tan(e^2x-3))×sec2(e^2x+3)×e^2x+3
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Don't fear Exam Winner is hear🔥🔥🔥🔥
Ans:dy/dx=cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3×2 , thankyou sirrr❤
Ans: dy/dx= 2 cos (tan (e^2x+3)).sec^2(e^2x+3).e^2x+3
Super class.... Thank you sir..,..❤❤❤
Examwinner ❤❤❤
ans - 2cos(tan(e^2x+3)).sec²(e^2x+3).e^2x+3
Ans : 2 cos (tan(e^2x+3)).sec^2(e^2x+3).e^(2x+3)
Thank you sir ❤
Ans:2cos(tan(e^2x+3)).sec^2(e^2x+3).e^2x+3
Bigg salute for your effort sir💗🫂
Ans: cos(tan(e^(2x+3))).sec²(e^(2x+3).e^(2x+3).2
Allen sir aura🔥🧨🎇🎆🔥
Class starts at 13:59 Thank me later 😍😍
😂
Ans:2 cos(tan e^2x+3)*sec^2(e^2x+3)*e^2x+3 ✨✨✨✨❤️nice class❤️
ADIPWOLI CLASS😁❤️ ANSWER = 2Cos ( tan e^2x+3) * sec² (e^ 2x+3) * e^ 2x+3 💀❤️❤️
Yes super class 😊
Allen sireeyy thnkuuh so much.....class nannayi manassilaay💗💗💗🤩
Ans:2cos(tan e^2x+3)•sec²(e^2x+3)•e^2x+3👩🏻🦯
Allen sireeyy thnkuuh so much.....class nannayi manassilaay💗💗💗🤩
Ans:2cos(tan e^2x+3)•sec²(e^2x+3)•e^2x+3👩🏻🦯
2Cos( tan e^2x+3)*sec^2(e^2x+3)*e^2x+3😊
ANS =COS[TAN(e^2x+3)].sec^2(e^2x+3).(e^2x+3).2
thanks for super class
samaya parimithi manasilakkunu sir
2cos(tan(e^(2x++3)))sec²(e^(2x+3))e^(2x+3)
52 comments in less than 6 minute Allen sir influence 😂🔥🔥
2cos(tane^2x+3.sec2(e^2x+3).e^2x+3