Position vs. Time and Velocity vs. Time Graphing, PT and VT graphing

แชร์
ฝัง
  • เผยแพร่เมื่อ 2 ม.ค. 2025

ความคิดเห็น • 50

  • @sonaliparmar98
    @sonaliparmar98 12 ปีที่แล้ว +30

    You explained it way better than my Physics teacher. Thank you so much!

  • @iriskoh4868
    @iriskoh4868 4 ปีที่แล้ว +13

    I’m still a little confused, but so much less confused than when my teacher explained. Thank You!!!!

  • @MissFrankieJean
    @MissFrankieJean 10 ปีที่แล้ว +9

    I was seriously struggling with these concepts in how these graphs/terms related. I talked to my TAs, watched videos, read the textbook... this was the first video that helped me!! Thank you so much! Do you have a video of an acceleration-time graph now?! I need to know how to relate all three concepts/graphs. You're the best!

  • @haha123pancake
    @haha123pancake 12 ปีที่แล้ว +3

    I totally fist-bumped my iPhone screen. Thank you so much for this!!! Helped a bunch

  • @ander15154
    @ander15154 10 ปีที่แล้ว +84

    *Punches screen*

  • @leetramp
    @leetramp 7 ปีที่แล้ว +2

    I'm out sick tomorrow, and this video is just what my students need to complete their work for the day :-)

  • @jadamarie4711
    @jadamarie4711 8 ปีที่แล้ว

    Every time I think I won't get the concept I see your video and I finally get it. Wish you were my teacher to be honest

  • @hardxrain
    @hardxrain 8 ปีที่แล้ว +1

    Very educational and well made video! I am incredibly thankful for your help, keep up the good work!

  • @MsSunnyMuffins
    @MsSunnyMuffins 9 ปีที่แล้ว +9

    thank you so much. wish you were my physics teacher after that quiz i just failed from not knowing this.

  • @sohaibfarrukh5844
    @sohaibfarrukh5844 9 ปีที่แล้ว +10

    I wish you were my physics teacher!! :(

  • @pukamon1681
    @pukamon1681 10 ปีที่แล้ว +2

    Thank you so much! Great explanation, I actually understand this now.

  • @LixupVideos
    @LixupVideos 12 ปีที่แล้ว

    this is a really helpful video for revising for test. it explained everything in detail.

  • @radiotete1e2
    @radiotete1e2 12 ปีที่แล้ว +2

    This was incredibly helpful. Thank you!

  • @MelvinAdekanye
    @MelvinAdekanye 4 ปีที่แล้ว +2

    *This guy has a bomb in the back*

  • @aaronbeckman2801
    @aaronbeckman2801 11 ปีที่แล้ว

    Great videos. I'm just starting to make my own using Doceri. It's alright but kind of clunky. What types of programs are you using for your vids?

  • @coloradowilderness3139
    @coloradowilderness3139 8 ปีที่แล้ว

    Would you tell me Which software are using to draw the Graphs ?
    Thanks

  • @jackzhang5595
    @jackzhang5595 3 ปีที่แล้ว

    This is such a helpful video

  • @Rgober239
    @Rgober239 11 ปีที่แล้ว

    Hmm if the velocity is constant at the beginning of the video then it means its moving not standing at 0 because it starts at 2m so it object moved from 0 to 2.

  • @janets5370
    @janets5370 4 ปีที่แล้ว +1

    Like literally everybody hates their physics teachers same tho

  • @lulablu55
    @lulablu55 10 ปีที่แล้ว

    thanks for this very helpful video !

  • @nicholasy04
    @nicholasy04 9 ปีที่แล้ว

    So at 1 second the squirrel has a velocity of 0m/s and .5m/s?

  • @krithikaparemeswaran9264
    @krithikaparemeswaran9264 8 ปีที่แล้ว

    would the total displacement of 22 secs be 8m?

  • @ppmp9937
    @ppmp9937 4 ปีที่แล้ว +1

    thank you. everyone, “as the slope goes, so does velocity!”

  • @robertmadeo7672
    @robertmadeo7672 7 ปีที่แล้ว

    Good Explanation.

  • @bennettjacobs9453
    @bennettjacobs9453 10 ปีที่แล้ว

    what about a more complex slope in the position vs. time graph? how would i translate that into velocity vs. time? The slope i have in mind is a curve, in the shape of a fancy italic f without the strike through. How would i make a velocity chart if the acceleration is not constant? would the velocity be at a slope, or curved? please answer, somebody! i need help!

    • @phunphyz
      @phunphyz 10 ปีที่แล้ว

      If the position-time graph is a curve (and you are taking physics in high school or maybe an algebra/trig physics course in college) it's likely a uniform acceleration situation. The velocity will be changing (increasing or decreasing) by the same amount each time interval and will be a straight line with some slope that is equal to the acceleration. Use the shape of the position-time graph to determine the velocity -- if the slope is positive, the velocity is positive; if the slope is increasing, the velocity is increasing. Hope that helps.

  • @sallydhe1
    @sallydhe1 9 ปีที่แล้ว

    thanks this was really clear

  • @aaronbeckman2801
    @aaronbeckman2801 11 ปีที่แล้ว

    Thanks, I'll check out Camtasia.

  • @cliojensen2512
    @cliojensen2512 11 ปีที่แล้ว

    So helpful thank you!

  • @AnonymousAnonymous-yp6io
    @AnonymousAnonymous-yp6io 7 ปีที่แล้ว +1

    From 14-16 the slope is 2.5 , not really sure why you put 1.7

    • @abdullahirfan2280
      @abdullahirfan2280 7 ปีที่แล้ว

      Anonymous Anonymous yeah I was confused on those points. How did u find that?

  • @mirandab.2873
    @mirandab.2873 7 ปีที่แล้ว

    My teacher doesnt teach thank you for your videos !!!!

  • @PickUps4You
    @PickUps4You 8 ปีที่แล้ว

    THANK YOU SO MUCH!!!

  • @CortezEspartaco2
    @CortezEspartaco2 7 ปีที่แล้ว

    This was helpful but so quiet that I had to hold my laptop up to my ear on full volume. Eventually I just used subtitles which was annoying to try to read while also looking at the graphs.

  • @s2dorisyeung
    @s2dorisyeung 12 ปีที่แล้ว

    thaaaanks so so so much !

  • @Good4Smiles
    @Good4Smiles 12 ปีที่แล้ว

    thank you!

  • @kipi_4034
    @kipi_4034 2 ปีที่แล้ว

    Hello ma boy appreciate it

  • @noosha4150
    @noosha4150 5 ปีที่แล้ว

    oh my god thank you

  • @melissabbyyy1589
    @melissabbyyy1589 3 ปีที่แล้ว

    5:50

  • @animal_lover1009
    @animal_lover1009 6 ปีที่แล้ว

    Great, but can u cut out the freaking beeping in the background it’s making me go insane

  • @noerutajiri8859
    @noerutajiri8859 10 ปีที่แล้ว +4

    Louder please. :D

  • @s_naeemnaqvi8725
    @s_naeemnaqvi8725 5 ปีที่แล้ว

    Yeet

  • @milkman5180
    @milkman5180 2 ปีที่แล้ว

    jshulz

  • @terrencekarson
    @terrencekarson 12 ปีที่แล้ว

    A beautiful woman doing math? yah I think the world IS gonna end

  • @Iberedmas
    @Iberedmas 11 ปีที่แล้ว

    Totally wrong.

  • @bennettjacobs9453
    @bennettjacobs9453 10 ปีที่แล้ว

    what about a more complex slope in the position vs. time graph? how would i translate that into velocity vs. time? The slope i have in mind is a curve, in the shape of a fancy italic f without the strike through. How would i make a velocity chart if the acceleration is not constant? would the velocity be at a slope, or curved? please answer, somebody! i need help!

    • @Fwnh
      @Fwnh 4 หลายเดือนก่อน

      To do this, you would need to be able to differentiate the curve to find the velocity, or integrate to find the area under the velocity-time curve. Not all graphs are just straight lines. 😊

  • @kundanrao4844
    @kundanrao4844 6 ปีที่แล้ว

    Thanks a ton