Normal Derivative

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  • เผยแพร่เมื่อ 25 ก.ค. 2024
  • Normal Derivative
    In this video, I define a really cool and useful concept called the normal derivative, which allows us to talk about the behavior of a function on the boundary of a region. This is very useful especially for PDEs, and the next couple of videos illustrate the power of that. Enjoy!
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ความคิดเห็น • 35

  • @blackpenredpen
    @blackpenredpen 3 ปีที่แล้ว +37

    No “thanks for watching”?

    • @Visputescooking
      @Visputescooking 3 ปีที่แล้ว +2

      True feelings are indescribable!💖
      Actually I love your videos!

    • @drpeyam
      @drpeyam  3 ปีที่แล้ว +6

      Hahaha

    • @lakshya3199
      @lakshya3199 3 ปีที่แล้ว +1

      @@drpeyam Keep uploading such videos for someone who wants to explore the depth of mathematics. Thanks, Dr.Peyam ☺️

  • @aliyarc.a150
    @aliyarc.a150 3 ปีที่แล้ว +13

    Love from an Indian Math enthusiast.♥️

  • @sophiasabelja8241
    @sophiasabelja8241 ปีที่แล้ว

    Thank you so much! This video was really helpful!

  • @gareebmanus2387
    @gareebmanus2387 2 ปีที่แล้ว +1

    Dr Peyam, Thank you for explaining very clearly (and enthusiastically as always) the normal derivative. Ideas like this one are often either assumed to be too easy to be discussed in detail or just mentioned during some elaborate calculation. I do not know if you have a video on Lipschitz domain which is also about the boundary of a domain.

  • @matrixstuff3512
    @matrixstuff3512 3 ปีที่แล้ว

    I really appreciate the notation using nu for the normal

  • @yinvara9876
    @yinvara9876 3 ปีที่แล้ว

    I like your enthusiasm, I also like the math

  • @EmissaryOfSmeagol
    @EmissaryOfSmeagol 3 ปีที่แล้ว

    Does the good Doc. have a video on multi-dim. IBP yet? If not I await in earnest!

  • @HDQuote
    @HDQuote 3 ปีที่แล้ว

    Thank you a lot. I follow your channel for a long time.
    What software & hardware did you use for this video?

    • @drpeyam
      @drpeyam  3 ปีที่แล้ว

      Microsoft Whiteboard

    • @HDQuote
      @HDQuote 3 ปีที่แล้ว

      Thanks a lot! And what hardware if I may ask?

  • @StreuB1
    @StreuB1 3 ปีที่แล้ว

    Hi Dr. Peyam!!! I haven't stopped in for quite some time but wanted to for this video. In Calc3; partials, gradient, and the TNB space was one of the biggest "Ah HA!!!!" moments in my maths career. It was also one of the most exciting because of all the immense power you now wielded. TNB was very hard for me to understand initially but once I realized it was another Cartesian coordinate plane "flying" around in the primary coordinate plane, anchored to the curve in question. I envisioned it as a roller coaster track and I am in the coaster car riding along, and me sitting in the car is one frame of reference, the TNB frame. Riding through the primary space of x,y,z. Once I realized that, it was like an avalanche of realizations all happening in short order. It was amazing TBH. So yeah, these topics are really awesome.
    I am in diffeq now and due to being "taught" remotely, I am failing horribly. Its not even failing, its like I understand absolutely zero. I will be retaking it in the spring, assuming we are back to REAL school and not this remote learning "socio-political experiment" or whatever you want to call it.

    • @knivesoutcatchdamouse2137
      @knivesoutcatchdamouse2137 3 ปีที่แล้ว

      What is TNB? Tangent, Normal, and Binormal vectors, I am guessing? Just never heard it referred to like that before. Makes sense though, their being orthogonal and all!

  • @iabervon
    @iabervon 3 ปีที่แล้ว

    If u is a function of |x|, the normal derivative of u on a surface of constant |x| is obviously going to be u' of |x|, according to the explanation of the normal derivative. The example is really checking that the definition gives the right result for a case where we know what the answer should be, so it's good that we aren't surprised.

    • @drpeyam
      @drpeyam  3 ปีที่แล้ว

      That’s interesting and makes total sense, thank you!

  • @TheMauror22
    @TheMauror22 3 ปีที่แล้ว

    What a cliffhanger :( I'm really looking forward to see that video.

  • @toaj868
    @toaj868 3 ปีที่แล้ว

    What kind of function is v in the integral you showed at the end?

    • @drpeyam
      @drpeyam  3 ปีที่แล้ว

      Any function

  • @Czeckie
    @Czeckie 2 ปีที่แล้ว

    what does W has to satisfy to have the normal defined at least almost everywhere?

    • @drpeyam
      @drpeyam  2 ปีที่แล้ว

      Smooth boundary

  • @dominicellis1867
    @dominicellis1867 3 ปีที่แล้ว +1

    Is their any difference between the divergence and the normal derivative they seem to measure the same thing

    • @drpeyam
      @drpeyam  3 ปีที่แล้ว +2

      Two different things, the divergence measures how something expands and the normal derivative measures how much something flows out of a surface.

    • @dominicellis1867
      @dominicellis1867 3 ปีที่แล้ว

      Dr Peyam I don’t really understand the difference is there an equation that relates the two functions using the gradient or does curl have anything to do with it?

    • @drpeyam
      @drpeyam  3 ปีที่แล้ว

      There’s no equation relating them since they’re two different things. The only relationship maybe is that if you integrate the divergence of the gradient, by the divergence theorem you get the gradient dotted with the normal vector which is the normal derivative

    • @dominicellis1867
      @dominicellis1867 3 ปีที่แล้ว

      @@drpeyam so the derivative of the normal derivative is the divergence of the gradient or the laplacian

  • @toaj868
    @toaj868 3 ปีที่แล้ว

    Is the normal derivative tied to flux? If so, how exactly are they related?

    • @drpeyam
      @drpeyam  3 ปีที่แล้ว

      By the divergence theorem

    • @toaj868
      @toaj868 3 ปีที่แล้ว

      @@drpeyam Thank you :)

  • @hugohugo37
    @hugohugo37 3 ปีที่แล้ว

    Hi Blackpenredpen!

  • @user-iv9sz8dx1g
    @user-iv9sz8dx1g 2 ปีที่แล้ว

    Why you take (1,f') as a tangent vector? shouldn't be (x,f'(x))?

    • @drpeyam
      @drpeyam  2 ปีที่แล้ว +1

      No, (1,f’) is correct. If you go 1 unit to the right, you go up f’(x) units

    • @user-iv9sz8dx1g
      @user-iv9sz8dx1g 2 ปีที่แล้ว

      @@drpeyam The curve have the representation (x,f(x)) at each points in it, so can we think about (1,f'(x)) as the gradient w.r.t x of the u where u= (x,f(x))?

  • @uwiennr4686
    @uwiennr4686 3 ปีที่แล้ว

    thnks for watching, hey i just watch ur video until 10 second 🤣🤣