Explanation and approach to the question was correct but at 13:24 you plugged in the wrong numbers. it should be 147(4) + 638(2) = FN1(8) and FN1 would be equal to 233 N and not 356 N
Didnt you switch the radius at the end. You said the painter has a force of 638N, And a radius of 2 meters. But you put 638(4) , which is the radius of the board.
i think the last equation should be " (638)(2) + 147(4) = Fn1(8) shouldn't it? Since you are looking for the Torque force for the board (147N), the middle point/radius should be 4
omg thank you i have been looking for ages for an explanation with beam weight its been a bloody month! thank you so much my assignment is due next week
Right answer for the second torque problem should be Fn(1) = 233N & Fn(2) = 552 N. The calculations were correct, but he mixed up the distance from the pivot point to the different forces.
make sure for the applying the given in the solution it be 147(4) - (because the force of the board is 147 not 638, then 638(2) - (because the force of the painter is 638 not 147)
Very late reply, but here's how I understand it: the normal force is larger because it opposes the weight of the board *and* the weight of the painters. Remember that there is no normal force on each painter because the painters are part of the painters-beam system (which means normal forces from the beam on the painters are not shown).
I didn't get the same answer, I used a the other support as the pivot… and i got 522 for Fn2 and 233 for Fn1, I think you may have the wrong r for the weights of the painter and board?
May I assume that the beam will be in the same position, for instance, at a certain inclination of some degrees, if I put two equal masses at the same distance of the pivot ? Or it will rotate to the horizontal position ? In this case, why it turns to zero inclination, if I put two equal forces? Shouldn't it keep at the same position, considering the fact that the beam are subject to the same torque?? Thanks.
no cuz u use the direction that the force is pointing at...when u use f1 as a pivot u can see that f2 is acting in the opposite direction..trace the force with your finger and go in th direction of the arrow...u eventually find that the direction is opposite to ur pivot
Good video, you made a little mistake though. At 9:53 The torque caused by weight of painter is counter clockwise, and the second normal force will cause a clockwise torque. It was a tiny booboo. Good work!
Right hand rule. Point your pointer finger from the pivot to the point the force is applied, and point your middle finger in the direction of the force. The thumb points in the direction of torque. By convention, torque is assigned to be in the direction that a threaded fastener would translate along the axis of the bolt, while subject to that torque. This is because torque is r cross F, and the right hand rule yields the direction of the torque. Torque will point out of the page if it would cause a CCW rotation, and in to the page if it will cause a CW rotation.
Conor Murray It was stated in the question that the see-saw was 50N. If it was grams or a similar unit then you would multiply it by gravity to find N.
while watching the video i fell asleep, . he talks too much! ! i was waiting for the equations, why not directly go to the point? the slide was good but you talk too much -.- .
Kim JongIn I believe that one of the primary key points in understanding Torque is to conceptualize it in a visual way. He did a great job in helping me understand it so much better than my text book. He had to explain how and why you are putting a certain pivot point in a certain place. That's really the whole point of physics. You can just memorize the equations, you will not survive... Lol. (:
Explanation and approach to the question was correct but at 13:24 you plugged in the wrong numbers. it should be 147(4) + 638(2) = FN1(8) and FN1 would be equal to 233 N and not 356 N
like the way u taught
this is true
same answer I've got
Yes
Excellent teaching. Now I can feel confident in solving more torque problems. Thanking you for your help. Michael.
You, sir, are an incredible teacher. This is so easy now!
Didnt you switch the radius at the end. You said the painter has a force of 638N, And a radius of 2 meters. But you put 638(4) , which is the radius of the board.
Why isn’t there a normal force for the painter
Great tutorial on Torque. Struggling to understand it with my book. But you explained it in such a simpler way than the book!! THANK YOU!
seems like youve interchanged the force of the painter to the force of the board in 13:25.
Magnificent explanation, thank you sir!!!
sir, in the second question where you multiplied 147 by 2, it should be 147 by 4 and eventually the value of F1 comes 233N and F2 comes 552N
Indu Das yup
i think the last equation should be " (638)(2) + 147(4) = Fn1(8) shouldn't it? Since you are looking for the Torque force for the board (147N), the middle point/radius should be 4
Yeah, I kept rewinding questioning my intelligence when I saw that mistake too
Why isn’t there a normal force for the painter
Great tutorial!! I reading and re-reading instructions, but this made it very understandable! Thank You!!!
omg you saved my life
my teacher taught this for 2 weeks and i still didnt understand but you taught this in 15 minutes and now i understand
Great explanation for solving torque. Regardless of the little math mistakes, the explanation was clear and straightforward!!!
omg thank you i have been looking for ages for an explanation with beam weight its been a bloody month! thank you so much my assignment is due next week
Right answer for the second torque problem should be Fn(1) = 233N & Fn(2) = 552 N. The calculations were correct, but he mixed up the distance from the pivot point to the different forces.
Why isn’t there a normal force for the painter
Holy fuck I love you. Saved me for my exam tomorrow.
Great video! I especially liked the step-by-step slide.
AP Physics exam in an hour lolol, this helped a lot!!
Great video, but you made an error @13:24. it should be (147)(4)+(638)(2)=Fn1(8) Which Fn1 = 233.
make sure for the applying the given in the solution
it be 147(4) - (because the force of the board is 147 not 638, then 638(2) - (because the force of the painter is 638 not 147)
Why isn’t there a normal force for the painter
Brilliantly explained!
we want more!
I am from 2021...btw ..Nice Explanation sir
You are boss!!! Thank you, Thank you.......... Thank you.
umm sir you mistakenly switch the force of the board with the force of the painter
great video .. can you explain to me why the normal force is larger on the center of the board than Mg is thanks
Very late reply, but here's how I understand it: the normal force is larger because it opposes the weight of the board *and* the weight of the painters.
Remember that there is no normal force on each painter because the painters are part of the painters-beam system (which means normal forces from the beam on the painters are not shown).
I didn't get the same answer, I used a the other support as the pivot… and i got 522 for Fn2 and 233 for Fn1, I think you may have the wrong r for the weights of the painter and board?
You are dead right. He screwed up at the final stage
Good practice problems, but ya fucked up bad with the last problem
This make very easier to study..... I I can give for all teacher I heartily thankx.......
thank you so much !
uhh did u got the person and the board weight mix up at 13:26?
this was so helpful! so much more helpful than my prof!
13:24 you did not stay consistent to the you variables FgB & FgP. You accidentally switched the values.
For FN1, the equation should be 638(2) + 147(4) = FN1.. The radius is just backwards
May I assume that the beam will be in the same position, for instance, at a certain inclination of some degrees, if I put two equal masses at the same distance of the pivot ? Or it will rotate to the horizontal position ? In this case, why it turns to zero inclination, if I put two equal forces? Shouldn't it keep at the same position, considering the fact that the beam are subject to the same torque?? Thanks.
Great Video! this truly helps me a lot with my concepts about torque :) Thank you for making such an informational video!
isn't the Fgp supposed to be 637 not 638?
Thanks for the great explanation :)
this was really helpful. thanks!
thank you. That has answered some questions
this was really helpful! thank you so much!
He explained very nice at the end it was a honest mistake so stop commenting about that
There is something wrong! at 13:25 ,, you mixed between the two forces i mean Fgb and Fgp
At 13:26 i believe you mixed up the forces between the painter and the board. Or maybe i am wrong?
Explanation was correct, but you plugged in the wrong numbers at 13:20.
When you conjugate a verb like "estar", does it become estará or estaría in the conditional?
for the last one, aren't they all torque'ing in the clock-wise direction?
no cuz u use the direction that the force is pointing at...when u use f1 as a pivot u can see that f2 is acting in the opposite direction..trace the force with your finger and go in th direction of the arrow...u eventually find that the direction is opposite to ur pivot
is Fgb*rb (147)*(4)
i got for Fn1=233 and for Fn2=552
r for painter and board have been switched in the actual calculation. it should be 638 (2) + 147 (4) = 8 F_N1
this was really helpful. thank you:)
Oh now I see why longer pens are easier to spin now.
so basically you separate the torques that are clockwise from the ones that are counter clockwise using the equal sign ---> (=) ?????? yes?!?!
Good video, you made a little mistake though. At 9:53 The torque caused by weight of painter is counter clockwise, and the second normal force will cause a clockwise torque. It was a tiny booboo. Good work!
great stuff. thnky!!!
The difficulty I have is that the 5 horsepower motor can run the shaft of how many kilograms
TH-cam and other online teaching services are increasingly showing how inadequate typical higher ed is.
Thank YOU!
thank you!!
THANK YOU
At 12:06,how do you know which forces will move the board clockwise and which will move it counterclockwise ?
Right hand rule. Point your pointer finger from the pivot to the point the force is applied, and point your middle finger in the direction of the force. The thumb points in the direction of torque. By convention, torque is assigned to be in the direction that a threaded fastener would translate along the axis of the bolt, while subject to that torque. This is because torque is r cross F, and the right hand rule yields the direction of the torque. Torque will point out of the page if it would cause a CCW rotation, and in to the page if it will cause a CW rotation.
Force of N1= 233N as others have pointed out
Awesome,thanks!
Chill... why does it seem like your rushing
Thanks very helpful
Thank you
great video :D
Amazing thanks :)
Where are you rushing my guy
Thank you :)
THank you
Doesn't the painter have a normal force, too?
dont consider force by system
yea you plugged it in the wrong order
638N should be multiplied to 2m
he switched the radius of the board and the painter
at 6;58 ,why the solution is wrong
no i s not clear
I just want to say astrology is real.
I love you!
gd video!!!thnks
Merci
"Their"
How does Fgboard = 50N?
Conor Murray It was stated in the question that the see-saw was 50N. If it was grams or a similar unit then you would multiply it by gravity to find N.
VIK96T reply 2 months after my exam but thanks anyway! I passed the exam btw ;)
Don't get it
helpful stuff
Wow i am still soo lost sighhhhh
jeez..slow down will yah??
yes...u r wrong
too fast. need to slow down a bit.
their* center of mass
wrong torque spelling
10:40
Why isn’t there a normal force for the painter
oof
Bahahahaha. Even these egg heads make mistakes.
slap dash
while watching the video i fell asleep, . he talks too much! ! i was waiting for the equations, why not directly go to the point? the slide was good but you talk too much -.- .
Kim JongIn I believe that one of the primary key points in understanding Torque is to conceptualize it in a visual way. He did a great job in helping me understand it so much better than my text book. He had to explain how and why you are putting a certain pivot point in a certain place. That's really the whole point of physics. You can just memorize the equations, you will not survive... Lol. (:
+shawawong Great comment about learning Physics, I agree
Thank you!