51:16 the mark scheme hydrolyses the nitrile then forms the amine, surely that would be wrong cause u use dilute hcl so the br will be substituted by an oh during the hydrolysis. The allow column uses the method you've done
I think because its ethanol and not NaOH it wont get substituded, not sure though. Also if you added the HCL second you would most likely get a NH3+ salt, which isnt what we need
The 2.3 peak thing is a singlet, therefore the carbon atom its bonded too isn't bonded to any hydrogen atoms. So that kinda serves as a clue because when u have an alkyl group bonded to an aromatic ring, the aromatic carbon the alkyl group is bonded too will not be bonded to any other hydrogen atoms. Im sorry its quite difficult to explain without diagrams tbh.
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51:16 the mark scheme hydrolyses the nitrile then forms the amine, surely that would be wrong cause u use dilute hcl so the br will be substituted by an oh during the hydrolysis. The allow column uses the method you've done
I think because its ethanol and not NaOH it wont get substituded, not sure though. Also if you added the HCL second you would most likely get a NH3+ salt, which isnt what we need
I have been waiting for this tysm!!!
1:02:14 I don't really get the explanation here, why you chose to use the benzene version of the 2.3 peak and the C=O version of the 2.6 peak
The 2.3 peak thing is a singlet, therefore the carbon atom its bonded too isn't bonded to any hydrogen atoms. So that kinda serves as a clue because when u have an alkyl group bonded to an aromatic ring, the aromatic carbon the alkyl group is bonded too will not be bonded to any other hydrogen atoms. Im sorry its quite difficult to explain without diagrams tbh.
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