Maths 9, Ex.2.4 (Q.5) (i) (ii) Polynomials | Ncert Maths Class 9 | Cbse.

In this video I taught Q.5 (i) (ii) of exercise 2.4 from chapter:2 Polynomials | Ncert Maths Class 9 | Cbse board.
#mathsclass9chapter2
#ncertmaths9
#polynomials
#cbsemaths9

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@Breaker's Bomb because we have to change the sign of zero of polynomial and we have to add X so it was +1 so now it is -1 and after adding it become,x-1
I hope you understand

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Sir but my maths teacher is saying that Long Division method is now ban in C.B.S.E. Instead of this method take (x-1) as a common and solve the sum..

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(+ + + + ) x=-1
(-- -- -- --) x=-1
(+ + -- --) x=1
( + -- + --) x=1
Hum aise kar sakte hai easily 🙂

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1 is a factor
x-1 = 0
x = 1
So x - 1 is a factor

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because the factor was +1 and in the 4th exercise, we see that x-1=0, x=+1 so we reversed that process and got x-1

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You solved all my problems

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Sir we have to the long division method or we can do it on rough

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Thanks

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Thanku sir🥰 sir aap bahut aache se samjhte ho