At 28:18,You considered section frm pt B at dist x. But for moment purpose,if u had considered section from pt A at distance x,it would yield same result with only one force P. Just like u took section on BC at distance of x from C. Anyways,gr8 learning
Sir, Considering B as fixed support the slope and deflection are zero both in the vertical and horizontal member. But how does a value of Ml/ 3EI come to B?
It's not actually fixed ...but it's a frame.. so it's resisting rotation of point c i.e BC independently so considered fixed here...but as seen from ab pov its simply moment acting at one hinged end and other is roller so direct formulas are there for theta
1) If we select AB as system 2) section. Where AB and BC connected shear force V, Axial Force and resistive moment M will be there (i)V= P from (FBD of BC ) (ii)M= PL CLOCKWISE (FROM FBD OF AB AND BC ) (iii)AXIAL FORCE AT SECTION=0 (FBD OF BC ) (3) Bx=Ax =P.....these two forces cause COUPLE This couple and Moment at section (where AB and BC are separated ) Will bend so where I am thinking wrong ?
Sir in daily quiz question on natural frequency of multiple loads on simply support beams - it become multiple dof question.only single dof are solvable
This lecture is from Video Course Shivam. But this question was discussed in Exergic ONE Live class as well. Please check Students Centre for all the latest updates in course content.
Absolutely loved the analysis by Chandresh Sir. It opened up many little things like reaction , moment. Thank you Chandresh sir. Do more videos like these sir. Keep inspiring us. Love you sir❤
At B. There should be a vertical reaction P .. if we consider whole frame at a time. At A. Reaction is Rax. At B Rbx Rby Apply summation of Fx=0. We get Rax=Rbx. And Summtion fy=0 Rby =p. And net moment about B. To balanced the frame. RaxL=PL. So Rax=Rbx=p. Hoga..
GATE Course discounts, Ending SOON !!
For details, Visit 👉 www.exergic.in
I was searching for the complete explanation of this question from many days and finally it's fulfilled after watching this video. Thanks
Thank God you picked up this question, this one needed a complete separate explanation. Thankyou
f
Really awesome explanation sir..thank you so much sir..lots of confusion are removed this question..
Thank you Sir for discussing this question... This was confusing one😊👍❤🙏
At 28:18,You considered section frm pt B at dist x.
But for moment purpose,if u had considered section from pt A at distance x,it would yield same result with only one force P.
Just like u took section on BC at distance of x from C.
Anyways,gr8 learning
Due to support A even though it's a roller, as per the sir point of view,not disturbed the result value know
why you weren't consider the force p for axial force of AB while transfering P of BC member.RB1=P
Sir now i regret not taking exergic coaching but sir thanks for such anlysis videos they hav enhanced my ability to luk prpblems in the correct way
Sir, excellent teaching
Thank you very much sir..clear cut concept
Sir, Considering B as fixed support the slope and deflection are zero both in the vertical and horizontal member. But how does a value of Ml/ 3EI come to B?
Please watch previous lectures for more clarity. It has been discussed earlier.
According to me P(L^3)/3EI will come as answer. The deflection and slope shape at the end B will not affect the deflection value at C.
Sir, Can you please draw shear force diagram, bending moment diagram, slope and deflection diagram for that vertical member alone?
It's not actually fixed ...but it's a frame.. so it's resisting rotation of point c i.e BC independently so considered fixed here...but as seen from ab pov its simply moment acting at one hinged end and other is roller so direct formulas are there for theta
1) If we select AB as system
2) section. Where AB and BC connected shear force V, Axial Force and resistive moment M will be there
(i)V= P from (FBD of BC )
(ii)M= PL CLOCKWISE (FROM FBD OF AB AND BC )
(iii)AXIAL FORCE AT SECTION=0 (FBD OF BC )
(3) Bx=Ax =P.....these two forces cause COUPLE
This couple and Moment at section (where AB and BC are separated ) Will bend
so where I am thinking wrong ?
Sir, is joint B a fixed joint or hinged joint?
Sir in daily quiz question on natural frequency of multiple loads on simply support beams - it become multiple dof question.only single dof are solvable
Shi bol rha bhai sir bhul gye shayad
Sir , when you calculated the slope you considered the moment at B only not the reaction force ?
That reactive force becomes axial load for vertical member not transverse load
Reactive force if horizontal which is transverse for vertical section
Supbb explanation sir👌👌👌👌
Thank you sir 🙏
Sir is it possible that the effect of AB in final deflection at C, if that B is fixed support (not hinged)?
Exergic now using digital board, superb
Is it better?
@@ninadsbhatt100 yeah, better diagrams, animations and gifs can be played, saves a lot of time la di da
Sir RB2 =P as sumFy=0
But it does affect the answer as it does not produce the moment
u r the best
Thank you sir :)
Is this video from Exergic ONE live classes???
This lecture is from Video Course Shivam. But this question was discussed in Exergic ONE Live class as well.
Please check Students Centre for all the latest updates in course content.
Please upload more videos on numericals
Sir, You had a beautiful rank, then why not you pursued M.Tech or Ph.D at IITs ??
4PL³/3EI will be answer if point A will be fixed.
Absolutely loved the analysis by Chandresh Sir. It opened up many little things like reaction , moment. Thank you Chandresh sir. Do more videos like these sir. Keep inspiring us. Love you sir❤
At B. There should be a vertical reaction P .. if we consider whole frame at a time. At A. Reaction is Rax. At B Rbx Rby Apply summation of Fx=0. We get Rax=Rbx. And Summtion fy=0 Rby =p. And net moment about B. To balanced the frame. RaxL=PL. So Rax=Rbx=p. Hoga..
@11:55 😂😅