Fluorescence in one hour

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  • เผยแพร่เมื่อ 2 ม.ค. 2025

ความคิดเห็น • 20

  • @danielmalaver1869
    @danielmalaver1869 11 หลายเดือนก่อน +2

    I wish you could also explain nmr and IR spectrometrics. Excelent for an instrumental analysis class. U r the best

    • @aarinnan
      @aarinnan 11 หลายเดือนก่อน

      Thank you very much for the nice comment.

  • @danielbastian5280
    @danielbastian5280 2 ปีที่แล้ว +3

    Thank you for this invaluable content!

  • @AlphaNumeric123
    @AlphaNumeric123 ปีที่แล้ว +1

    That was an extremely good presentation

  • @kaarmukhilnilavan9495
    @kaarmukhilnilavan9495 ปีที่แล้ว +1

    Very good lecture...... Thanks a lot

  • @AgronomyMadeEasy
    @AgronomyMadeEasy ปีที่แล้ว +1

    thank you

  • @fatimasheraz8235
    @fatimasheraz8235 2 ปีที่แล้ว +2

    Tusind tak :-)

  • @samgaita
    @samgaita 3 ปีที่แล้ว +2

    Thank you for the insightful lecture on fluorescence.
    Quick question. I have Em Ex plot of humic solution and the 2nd order Rayleigh line cuts through. How do you correct for the lost signal data in results evaluation?

    • @aarinnan
      @aarinnan 3 ปีที่แล้ว +1

      It is always problematic when you have one of the scattering lines on top of your fluorescence signal. The best approach to handle this is to model the Rayleigh scatter (and there are several options here). The other, more simple approach, would be to investigate your excitation and emission profile, and then (either visually or manually) remove the scattering signal by drawing a "reasonable" interpolation between your existing fluorescence signal.

  • @dongchris2996
    @dongchris2996 2 ปีที่แล้ว +2

    thank you sir

  • @السيدةرواءعبدالعليم
    @السيدةرواءعبدالعليم 2 ปีที่แล้ว +2

    Hi , can you help me please?
    How can I use the synchronous scan in Rayleigh scattering method.

    • @aarinnan
      @aarinnan 2 ปีที่แล้ว

      If you're running synchronous scan, you would normally just select a delta that is sufficiently high to get away from the Rayleigh Scatter line.

  • @SelinManojKumarS22PHD004
    @SelinManojKumarS22PHD004 9 หลายเดือนก่อน

    informative..

  • @jacobvandijk6525
    @jacobvandijk6525 11 หลายเดือนก่อน

    @ 15:21 A single wavelength? Really? In my opinion, a single wavelength can't be measured, because it isn't localized (according to Heisenberg).

    • @aarinnan
      @aarinnan 11 หลายเดือนก่อน

      Sorry, I don' understand your comment. I am mentioning that several researchers are measuring a single excitation and emission pair. NOT that they are measuring an exact, specific wavelength.

    • @jacobvandijk6525
      @jacobvandijk6525 11 หลายเดือนก่อน

      @@aarinnan "A very, very specific wave length", that's what you said. Just listen.

    • @danielmalaver1869
      @danielmalaver1869 11 หลายเดือนก่อน

      Lol UV spectrometric methods are based on the suposition that a single wavelength is being absorbed. It is part of the noise of the instrument working in the UV region. That is why we accept the fact that there will be absorbance on a single wavelength.
      Excellent video, love from Colombia.

    • @jacobvandijk6525
      @jacobvandijk6525 11 หลายเดือนก่อน

      @@danielmalaver1869 Haha, you can accept what you like, mate. But nobody has ever seen a spectrum in which exactly one frequency was absorbed. Learn your lesson on bandwidth again ;-)

  • @rocketman475
    @rocketman475 3 ปีที่แล้ว +1

    👍

  • @nareshbarik5384
    @nareshbarik5384 10 หลายเดือนก่อน +1

    Thank you