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TheLastPost
เข้าร่วมเมื่อ 22 ธ.ค. 2013
Welcome to my Channel, it’s just me, playing with things that interest me at the time. Hope some of it will be interesting to you.
Thanks for taking the time to watch :)
Thanks for taking the time to watch :)
CB Radio Grab Bag - Utility Pouch & Solar Powered Generator feat.
Inspired by Gary from 104's Outdoors to show your CB Radio Grab Bag, here is mine. A RadioShack TRC-1014 handheld CB, a T2LT homemade aerial, Midland 26-L speaker mic, swr meter and leads residing in a cheap ebay medical utility cordura pouch.
Also shown is my solar power generator. Made with a plastic Plano ammo box, 12v-12Ah sealed lead-acid battery, solar charge controller and various usb and 12v outputs. Red and white led lights added for night time operation.
Also shown is my solar power generator. Made with a plastic Plano ammo box, 12v-12Ah sealed lead-acid battery, solar charge controller and various usb and 12v outputs. Red and white led lights added for night time operation.
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Saving my 12v batteries with a DC-DC Boost Buck Converter!!
มุมมอง 8K7 ปีที่แล้ว
I found out that my 12v battery charger was putting out nearly 16v while charging my batteries!! They were literally sizzling inside! Here I use a DC-DC Boost Buck Converter to lower the output to a much more sensible and safe 13.80v. Here are some specs on the converter I purchased: Input voltage: DC 3-15v Output voltage: DC 0.5-30v Input current: 3A (max) Power: 25W (max) Conversion Efficienc...
12v Battery Internal Resistance Test
มุมมอง 82K7 ปีที่แล้ว
Here I'm testing a bank of used 12v batteries to find out the internal resistance and if any are worth keeping or taking to the recycle centre. Generally the lower the internal resistance a battery has the healthier it is, although that didn't seem the case with one particular battery I tested..
RadioShack TRC-1014 Handheld CB upgrade to 12v power
มุมมอง 1.2K7 ปีที่แล้ว
Here I upgrade my RadioShack TRC 1014 handheld CB to use a 12volt car lighter socket. This will boost its output from the original 2watts to the legal UK maximum of 4watts, while also allowing the battery pack to be returned simply to its original state.
Maglite LED Upgrade, 3 Watt 180 Lumen Cree Bulb
มุมมอง 105K10 ปีที่แล้ว
Here I show you how to upgrade and convert your Maglite to LED for superior performance and efficiency. This is a must "How To" if you own a Maglite! I'm upgrading using a 3 Watt 180 Lumen Cree bulb and the difference in output at the end is outstanding!
Awesome! Thanks for sharing
I use V1 - V2 = V3 V2 / R = I V3 / I = Ohms IR Ohms * 1000 = milliOhms . 12.66V1 - 12.36V2 = 0.30V3 voltage drop 12.36 v2 divided by 120ohms resistance or load = 0.10 I amp draw. 0.30V3 voltage drop divided by 0.10 I amp draw = 2.8691 Ohms internal resistance or 2869.13milliohms. I couldn't find the internal resistance of your exact battery but similar models like the UB1222 have an IR rating of 80milliOhms. Those batteries are showing there age.
Great video
Hi sorry for replying late🥰 what's your email address?
Wow never seen a better demonstration. Awesome
Interesting. Interchanging current, watts and voltage all in one video...glad I know the difference or it might've really confused me🤣
Voltage should be measured at the battery terminals, The resistance for the load should factor in the leads that were used. The resistance of the load will change slightly due to heating. Outside of that close enough to get reference measurements compared to the others.
Hindi me bolo bhai
Thank You so much
Hi Is a hi ressist is bad ? How mucu sold be a resistens of a 12 v battery ? Thenks.
I’ve also done this upgrade about five years ago, and still impressed with it now in 2023
nice video. What if we connect some batteries in series like two in series? Can you calculate the internal resistance of each cell for the series combination?
You made changing a flash light bulb last 6 min long. Lame.
its too high IR for a SLA batt.. i think something is wrong...
Another great upgrade is to use a Cady that will hold regular AA batteries....say like energizer lithium....guaranteed not to leak.....are lighter and are easier to find.....or just use regular eneloops that you can recharge.....
Good
Assuming you don't have one shorted cell in that battery, the reason your good battery limits to 12.03V when charging is probably because it is trying to draw a high initial charge current and your converter/regulator has gone into current limit. Typically a good lead acid / SLA, battery with the low internal resistance will pass a high initial charge current and then increase in voltage slowly as it absorbs the charge. A bad battery gets up to voltage too quickly with a low current. I am surprised how high the resistance is for all of your good batteries, did you say about 2.5 ohms(?) I guess you are using them at very light load as with an internal resistance of about 2.5 ohms you be loosing 6v in the battery for a load of only 2.4 amps.
Do you need to put a resistor on the battery to calculate the internal resistance. Can't you just put the meter in Ohms scale and find the internal resistance of the battery ?
Simply NO! Your meter can blow up! (Measuring resistance on a live circuit is prohibited)... And internal resistance cannot be measured in this way...It looks like the ESR of capacitors...
Eu kero conpra um ledio desdi
Essi ledi em contra nu mercadolivre
newbie here, great vid, not familiar with all of this but i have 12V 7ah batteries I'd like to test however I only found those little wired resistors 1K and 5.5K (used on home alarm systems), can I use these to test the batteries - I quickly tried it but the Voltage did NOT drop at all with these resistors
Needs to be lower resistance, ideally a few hundred milliamps to an amp for batteries of this size to get any useful resolution. Try a 22 ohm 10 watt resistor or maybe a 12 ohm 15 watt, cheap ones from ebay are fine. What do you intend on using the battery for? A worn out battery may still be perfectly fine in low power applications or bench use but unsuitable for others.
please will you make me a power pack like this?
You could also measure the current with the resistor in place. (R1 + R2) = V/I. You measure I, you measure V, R1 is the resistor value, and R2 is the unknown internal resistance. Solve for R2.
Yes, probably more accurate? but you need to do two measurements at the same time.... so need two meters.
Very good effort for your first TH-cam video. Never be scared to shorten parts that are running a bit long. I'm advising as a film editor Cheers David
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Great video and simple equations I guess this is best for a constantly measuring of a batteries life or as you have done a number of the same batteries I tried it with a 10w 63ohm resistor on some car batteries, they where all new and measure milli-ohms
Is this possible to do with a car battery as well? What power resistor to use then? And where did that 120ohm number come from?
For car batteries you'd need a much lower resistance probably less than 8 ohms and rated for tens of watts (resistor will get very hot if left connected for long). But cars are outside and experience wider temperature swings than indoors, cold in particular will reduce the cold cranking amps so a cold night may be required to get a better picture (let the battery sit out there all night in the freezing cold first).
Very nice clean installation. I really liked the battery back-up system.
Wow great..
Very educational and informative, thanks.
You do know that the manufacturer's specified internal resistance is 0.17 Ohms? Quite the difference from 2.91 Ohms. A dead short on a fully charged battery should yield a 73AH drain.
Should if been in milliohms..
If the internal resistance was actually 3 Ohms all the time then it would be pulling 4A internally and be flat within 30 minutes when on the bench. The internal resistance is more likely to be <100mOhms. You did identify the dud batteries doing a 100mA load test and your two red dot batteries pulled down to 5v and 11.2v so that shows that open circuit voltage tells you nothing and a load test of some kind gives a better indication of State of health.
Internal resistance appears in series with the cells, not parallel.
Fantastic job brother. You even took the time to show the huge difference in brightness. You've convinced me to at least upgrade to a 180 Lumen for now until I can afford the 2000 Lumen upgrade!
link?
dude this is the best multimeter measuring internal resistance video ever! thanks so much with every tiny details great master respect from Turkey
A BIG thank you for this video! It was exactly what I searched for and your video fitted ALL the slots. Thanks for the Vaseline tip also! Perfect.
Nice vid but very sloppy with terminology and fine detail. This could be extremely confusing to "new to electronics" people and sight impaired people, otherwise well presented.
He did the math super fast in the vid. It was 0.1 amps then multiplied by 12v to get the wattage of 1.2. He uses that formula shown in the vid to get his readings. From what I've seen mostly used, Ohms(R) =(v1-v2) / (v1/ohms used for test) using the same drain method to get V2. The results should be in the milliohms for what I have read. The result should match closely to the battery specs, when new of course.
Grab bag 3 Vissit my home
1.2 amps = 1.2 watts ?
He did the math super fast in the vid. It was 0.1 amps then multiplied by 12v to get the wattage of 1.2. He uses that formula shown in the vid to get his readings. From what I've seen mostly used, Ohms(R) =(v1-v2) / (v1/ohms used for test) using the same drain method to get V2. The results should be in the milliohms for what I have read. The result should match closely to the battery specs, when new of course.
12V/7.2AH lead acid battery with 12.9V open circuit voltage that I suspect to be gone bad, when connected to a 10W 1R resistor showed 4.3V till I can see on multi meter, the connecting wire to resistor and resistor were very hot, I had to remove the wire. So it was passing 8.9A. It shouldn't be right. Too much of current passing through it.
A 1Ohm resistor connected across a 12V battery draws 12A from the battery, or consumes 144W of power. In order for it to withstand such power, it should be made of at least three times that power, that is, nearly a 450W one, instead of the 10W you used. The feeding cables should have been accordingly calculated for proper diameter or (better) cross section, securing low voltage drop for that current magnitude instead of their inadequacy causing overheating. Apart of all these above, there is nothing wrong with your test. In fact, using high current, makes it much more reliable as regards the health of the battery under test... The point is to do it correctly and safely...
@@ΠάριςΑζής Wrong, the terminal voltage dropped from 12.9v to 4.3v the moment he connected the load. The high internal series resistance of the battery meant the actual combined load resistance was higher than 1 ohm. Also you don't need such a high wattage resistor for tests like this, three times higher is for product design where the resistor will be dissipating such power reliably for long periods of time, the 10w resistor getting overwatted for a few seconds during tests isn't the end of the world as long as it's resistance doesn't change too much, if in doubt put it in distilled water for cooling. Although I'd probably have used a 10 ohm 15w instead.
@@CamelCasee Where exactly am I wrong? My comment is based on the hypothesis that the battery under test is healthy and the calculations are accordingly done. Apart from that, it is obvious that the result is due to high internal resistance. What do you think that would happen during testing a healthy battery under the conditions you suggest? Have you ever seen the load resistors used inside the test instruments of the market which use the same method of dynamic testing of batteries? Do you know their wattage? They also are used for a few seconds per test as you say...but take a look at one of them before putting such comments...
@@ΠάριςΑζής He used a 120 ohm resistor.
good job ... interested ...come back to my channel like
Great informative video! Thanks. There is a lot of potential for these handheld radios and there is a Facebook group to promote their use. facebook.com/groups/626284211601283/ 73 2AT111
Cheers for the video content! Excuse me for the intrusion, I would love your opinion. Have you researched - Rozardner Powerful Battery Reality (Sure I saw it on Google)? It is a smashing one off product for learning how to recondition an old battery without the normal expense. Ive heard some super things about it and my cousin after many years got amazing results with it.
Linear amplificator?
Good video, interesting information.
Thank you, a very informative and well laid out video, regards Doc Cox.
use over charge to de-sulfate them use current limiting resistor or light bulb 12 volt on one leg of input voltage from charger then 5 times run to 11 volts recharging as normal every time ,,its a way work best on flooded as one just add water but if they do not dry out being sealed one can crack sulfation away and reform themn
@Dodai Dibri just charge battery then run it dead but only to 10.5 --10 volts recharge it should get better capacity on say 5th time then charge it 24 hour to 2 weeks yep a bout it
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