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Engr. Harf Miranda (Sir Harf Engineering Tutorial)
เข้าร่วมเมื่อ 23 ต.ค. 2009
Welcome to Sir Harf Engineering Tutorial!
Engr. Harf J. Miranda, MPE
BS CE Mapua University (Gold Medalist and Cum Laude)
Top 9 Civil Engineering Board Exam May 2013 (Rating 92.05%)
Master in Professional Engineering (MPE) University of Tasmania, Australia
Engr. Harf J. Miranda, MPE
BS CE Mapua University (Gold Medalist and Cum Laude)
Top 9 Civil Engineering Board Exam May 2013 (Rating 92.05%)
Master in Professional Engineering (MPE) University of Tasmania, Australia
PSAD Refresher 34: Stresses in Reinforced Concrete Beam (Working Stress Design)
SITUATION: A rectangular reinforced concrete beam with width of 300 mm and effective depth of 600 mm is subjected to a service bending moment of 200 kN-m. The beam is reinforced with 4-φ32 mm bars. Use f’c = 28 MPa.
16. Using Working Stress Design method, which of the following gives the location of the neutral axis measured from the extreme concrete fiber in compression?
A. 221.2
C. 246.33
B. 235.7
D. 205.4
17. Which of the following gives the maximum compressive stress in concrete in MPa?
A. 10.45
C. 8.65
B. 9.63
D. 7.53
18. Which of the following most nearly gives the tensile stress in steel in MPa?
A. 100
C. 140
B. 160
D. 120
Thanks for watching!
Comment for questions and suggestions for future lecture in this series.
Subscribe and hit the bell button to be notified for future posts.
#civilengineering #boardexam #engineering #structuralanalysis #structuralengineering #CivilEngineeringLicensureExamination #PRC #PSAD #theoryofstructures #cele #strengthofmaterials #mechanicsofmaterials #staticsofrigidbodies #steeldesign #compressionmember #trusses #friction #refresher #PSADRefresher #SHET
16. Using Working Stress Design method, which of the following gives the location of the neutral axis measured from the extreme concrete fiber in compression?
A. 221.2
C. 246.33
B. 235.7
D. 205.4
17. Which of the following gives the maximum compressive stress in concrete in MPa?
A. 10.45
C. 8.65
B. 9.63
D. 7.53
18. Which of the following most nearly gives the tensile stress in steel in MPa?
A. 100
C. 140
B. 160
D. 120
Thanks for watching!
Comment for questions and suggestions for future lecture in this series.
Subscribe and hit the bell button to be notified for future posts.
#civilengineering #boardexam #engineering #structuralanalysis #structuralengineering #CivilEngineeringLicensureExamination #PRC #PSAD #theoryofstructures #cele #strengthofmaterials #mechanicsofmaterials #staticsofrigidbodies #steeldesign #compressionmember #trusses #friction #refresher #PSADRefresher #SHET
มุมมอง: 423
วีดีโอ
PSAD Refresher 33: Design of Column Transverse Reinforcement (Special Provision on Seismic Design)
มุมมอง 69714 วันที่ผ่านมา
SITUATION: A column section b = 400 mm, h = 600 mm is reinforced with longitudinal bars Ast = 8-φ25 mm equally distributed along all faces. Lateral ties are composed of 12 mm rectangular hoops with clear cover equal to 40 mm and 12 mm cross ties in both directions. Concrete yield strength f’c = 27 MPa with allowable concrete shear stress, fv = 0.866 MPa, and steel yield strength, fy = 415 MPa. ...
PSAD Refresher 32: Pipe Carrying Steam (Analysis of Thin-walled Vessel)
มุมมอง 35314 วันที่ผ่านมา
SITUATION: A pipe carrying steam at 3.5 MPa has an outside diameter of 450 mm and a wall thickness of 10 mm as shown in Figure UT09. A gasket is inserted between the flange at one end of the pipe and a flat plate used to cap the end. 10. Calculate the required force to hold the cap on. A. 508.270 kN C. 556.650 kN B. 532.185 kN D. 596.325 kN 11. How many 40 mm diameter bolts must be used to hold...
PSAD Refresher 31: Stresses on Prestressed Double-Tee Simply Supported Beam
มุมมอง 66614 วันที่ผ่านมา
SITUATION: The flooring of a warehouse is made up of double-tee joists (DT) as shown in Figure LPT-012. The joists are simply supported on a span of 7.5m and are pre tensioned with one tendon in each stem with an initial force of 745 kN each, located at 75 mm above the bottom fiber, loss of stress at service load is 18%. Load imposed on the joists are: Dead load = 2.3 kPa (does not include self...
PSAD Refresher 30: Spacing and Bearing Stress on Rivets
มุมมอง 36814 วันที่ผ่านมา
SITUATION: The beam in Figure RGM 4.31 is fabricated by attaching a C180x14.6 channel to a W250x17.9 shape with 15-mm-dia rivets. The maximum shear force in the beam is 65 kN. Given properties: C180x14.6: A = 1850 mm^2; d = 178 mm; xcg= 13.8 mm Iy = 0.405x10^6 mm^4; tw = 5.3 mm; tf = 9.3 mm W250x17.9: A = 2270 mm^2; d = 251 mm; Ix = 22.4x10^6 mm^4; tw = 4.8 mm; tf = 5.3 mm 4. Find the maximum a...
PSAD Refresher 29: Block Supporting a Pole to Maintain Equilibrium (Friction)
มุมมอง 52214 วันที่ผ่านมา
SITUATION: Block D supports the 200-lb uniform pole ABC in the position shown. Assume A is frictionless. 1. Find the minimum weight (lb) of block D to avoid slipping. A. 237.6 C. 210.1 B. 156.7 D. 255.3 2. Find the minimum weight (lb) of block D to avoid tipping. A. 237.6 C. 333.2 B. 352.8 D. 255.3 3. Find the minimum weight (lb) of block D to maintain equilibrium. A. 237.6 C. 333.2 B. 352.8 D....
PSAD Refresher 28: Tipping of Container (Friction)
มุมมอง 42714 วันที่ผ่านมา
SITUATION: The weight of the cylindrical tank is negligible in comparison to the weight of water it contains (water weighs 62.4 lb/ft3). The coefficient of static friction between the tank and the horizontal surface is μ. 1. Assuming a full tank, find the smallest force P (N) required to tip the tank. A. 442.36 C. 820.56 B. 163.24 D. 414.35 2. Assuming a full tank, find the smallest μ that woul...
PSAD Refresher 27: Minimum and Maximum Force to Maintain Equilibrium on Homogeneous Bar (Friction)
มุมมอง 65414 วันที่ผ่านมา
SITUATION 27: The homogeneous bars AB and BC are identical, each having a mass of 100 kg. The coefficient of static friction between the bar at C and the horizontal plane is 0.5. 1. Calculate the maximum value of P (N) to maintain equilibrium. A. 540 C. 880 B. 1630 D. 480 2. Calculate the minimum value of P (N) to maintain equilibrium. A. 540 C. 880 B. 1630 D. 480 3. If P = 1000 N, calculate th...
PSAD SITUATION 34: Analysis of Dam | CELE April 2024
มุมมอง 1.7K21 วันที่ผ่านมา
CELE Past Board Exam Problem SITUATION 34: The forces acting per meter length of the dam shown are as follows: F1 = 275 kN; F2 = 165 kN; W = 650 kN. Given: θ = 60⁰. The coefficient of friction at the base of the dame is 0.30. 1. Solve for the factor of safety against sliding. A. 1.35 C. 1.14 B. 1.66 D. 0.85 2. Determine the eccentricity (m) of the resultant force at the base of the dam. A. 0.67...
PSAD SITUATION 33: Friction on Crate | CELE April 2024
มุมมอง 69121 วันที่ผ่านมา
CELE Past Board Exam Problem SITUATION 33: A force P is applied to move the crate weighing 30 kg. Given: Width of crate w = 1.2 m; H = 0.50 m; Coefficient of friction = 0.25 1. Solve for the maximum value of P (N) which can be applied to maintain equilibrium given the following: θ = 30⁰ A. 135 C. 99 B. 168 D. 85 2. Solve for the maximum value of P (N) which will cause tipping to occur given the...
PSAD SITUATION 32: Sliding of a Plank (Friction) | CELE November 2023
มุมมอง 71521 วันที่ผ่านมา
CELE Past Board Exam Problem SITUATION 32: A 120 kg man walks on a 4 m plank resting on rough surfaces at A and B. Given: Coefficient of friction at A = 0.40 and coefficient of friction at B = 0.20. 1. At what distance x will the plank start to slide? A. 1.35 m C. 2.65 m B. 1.68 m D. 2.32 m 2. What is the friction force (N) at A? A. 256.7 C. 641.9 B. 98.6 D. 492.9 3. What is the vertical force ...
MSTC Refresher 121: Calculation of Peak Hour Factor (PHF)
มุมมอง 67321 วันที่ผ่านมา
A highway used for evening commuters’ experiences peak hour traffic of 3500 passenger equivalent vehicles per bour between 5:00 pm and 6:00 pm The traffic during the 15-minute segments is: 5:00 pm - 5:15 pm - 650 veh 5:15 pm - 5:30 pm - 920 veh 5:30 pm - 5:45 pm - 1140 veh 5:45 pm - 6:00 pm - 790 veh Most nearly, what is the peak hour factor? A. 0.30 B. 0.77 C. 1.3 D. 1.7 Thanks for watching! C...
MSTC Refresher 120: Design of Pavements Thickness Based on Strength Coefficient
มุมมอง 49321 วันที่ผ่านมา
The worn surface course of a high-volume pavement is being replaced with a design requiring a total structural number of 6.6. The engineer has decided to replace 6 in of the surface with recycled-in-place asphalt concrete having a surface course strength coefficient of 0.42, leaving in place 3 in of sound original pavement having a strength coefficient of 0.3. Under the original pavement are a ...
MSTC Refresher 119: Calculation of Superelevation (No Side Friction)
มุมมอง 44121 วันที่ผ่านมา
A one-lane rural road has a 10° curve extending for 230 m along its centerline. The road is 5 m wide with 3 m wide shoulders. The design speed for this road is 75 km/h. The superelevation needed so that side friction is not needed is most nearly: A. 0.0005 B. 0.034 C. 1.1 D. 1.9 Thanks for watching! Comment for questions and suggestions for future lecture in this series. Subscribe and hit the b...
MSTC Refresher 118: Correction on of Rod Reading due to Non-Verticality
มุมมอง 40221 วันที่ผ่านมา
A reading of 3.50 m is taken on a 4 m leveling rod that is 0.50 m out of plumb at the top of the rod. The correct reading (in m), when the rod is truly vertical, is most nearly: A. 3.06 B. 3.47 C. 3.53 D. 3.94 Thanks for watching! Comment for questions and suggestions for future lecture in this series. Subscribe and hit the bell button to be notified for future posts. #civilengineering #boardex...
MSTC Refresher 117: Stopping Sight Distance on a Summit Vertical Curve
มุมมอง 46821 วันที่ผ่านมา
MSTC Refresher 117: Stopping Sight Distance on a Summit Vertical Curve
MSTC Refresher 116: Pavement Thickness based on Structural Number and Layer Experience Coefficient
มุมมอง 33821 วันที่ผ่านมา
MSTC Refresher 116: Pavement Thickness based on Structural Number and Layer Experience Coefficient
MSTC Refresher 115: Effect of Inflation to the Cost of Constructing a Bridge
มุมมอง 29121 วันที่ผ่านมา
MSTC Refresher 115: Effect of Inflation to the Cost of Constructing a Bridge
MSTC Refresher 114: Cumulative Earthwork Volume (Waste or Borrow)
มุมมอง 35521 วันที่ผ่านมา
MSTC Refresher 114: Cumulative Earthwork Volume (Waste or Borrow)
MSTC Refresher 113: Thermal Stress on Steel Rail
มุมมอง 30921 วันที่ผ่านมา
MSTC Refresher 113: Thermal Stress on Steel Rail
MSTC Refresher 112: Number of Links and Arcs in a Traffic Network | CELE April 2024
มุมมอง 63621 วันที่ผ่านมา
MSTC Refresher 112: Number of Links and Arcs in a Traffic Network | CELE April 2024
MSTC Refresher 111: Length and Grade of Vertical Profile for Transport Airport Runway
มุมมอง 30421 วันที่ผ่านมา
MSTC Refresher 111: Length and Grade of Vertical Profile for Transport Airport Runway
MSTC Refresher 110: Maximum Capacity of Traffic given Mean Velocity as a Function of Density
มุมมอง 34421 วันที่ผ่านมา
MSTC Refresher 110: Maximum Capacity of Traffic given Mean Velocity as a Function of Density
MSTC Refresher 109: Missing Northings and Eastings of a Point in a Triangular Traverse
มุมมอง 48521 วันที่ผ่านมา
MSTC Refresher 109: Missing Northings and Eastings of a Point in a Triangular Traverse
MSTC Refresher 108: Volume of Fill in Earthworks
มุมมอง 37421 วันที่ผ่านมา
MSTC Refresher 108: Volume of Fill in Earthworks
PSAD SITUATION 31: Pile Cap Subject to Combined Axial and Bending | CELE November 2023
มุมมอง 1.3K21 วันที่ผ่านมา
PSAD SITUATION 31: Pile Cap Subject to Combined Axial and Bending | CELE November 2023
MSTC Refresher 107: Application of First Derivative Test (Revenue)
มุมมอง 1.3K21 วันที่ผ่านมา
MSTC Refresher 107: Application of First Derivative Test (Revenue)
MSTC Refresher 106: Creating a Matrix from Work Flow
มุมมอง 56321 วันที่ผ่านมา
MSTC Refresher 106: Creating a Matrix from Work Flow
MSTC Refresher 105: Converting a Table to Matrix Form
มุมมอง 39321 วันที่ผ่านมา
MSTC Refresher 105: Converting a Table to Matrix Form
MSTC Refresher 104: Finding the Range of a Function from Lower Bound of Domain
มุมมอง 5021 วันที่ผ่านมา
MSTC Refresher 104: Finding the Range of a Function from Lower Bound of Domain
Matutulog na may natutunan.thank you Sir🫡
Good night! Bukas ulit 😂
Goodmorning sir, What book po galing ang problem?
Similar to past board question
@@harfmiranda any reference po? pra may mga masagotan problems lang the more probs the better
Not sure kasi sa review centers halo2 na ang references. Pero good references ang mga ito: Hibbeler Pytel Kiusalaas Singer Beer Meriam
Good day, Neer! Solid ka talaga. Sana po makagawa po kayo lec about double tee joists! Thank u and Godspeed po!
Meron po tayo niyan 😃 PSAD Refresher 31: Stresses on Prestressed Double-Tee Simply Supported Beam th-cam.com/video/QuKHkzc5fXc/w-d-xo.html
Bakit pag ikaw boss na gegets ko. pero siya hindi ko siya maintindihan kung bakit pa rin ako iniwan. huhuhu 😂😂😂
Baka pag naging engineer kana lods bumalik na siya haha
Sir, safe po ba sabihin na: Links = no. of nonzeroes/2 and Arcs = no. of -1?
Tama po!
@harfmiranda Thank you po engr.
Sir, san po galing ang "-2" sa "-2×8×14"?? Bakit po -2?
Cosine law lang po yun
@@harfmiranda ayy oo nga pala sir. Thanks po!
sir may combined footing po ba kayo nung may 2019 po
Wala pa sa ngayon. Try ko gumawa kapag nabakante ulit engr! Hehe
Sainyo ko lang po na gets to sir. Sobrang linaw nang explaination.🎉
Salamat sa panonood!
@@harfmiranda thanks din po sir. Sana may gusset plate din po yung apatan lang sir. Medjo confuse ako dun baka din po may caltech nun just like bolts🤧
Ganito ba? PSAD SITUATION 7: Eccentrically Loaded Bolt in Spliced Beam th-cam.com/video/EzJUnSLW-mU/w-d-xo.html
sana araw araw kang mag upload neer HAAHAHHA. Salamat po nang marami!<3
Salamat po.
di kita calcu mo neeer hahahaaha
Hindi nga nashare screen ang calcu sa video na to. Hahaha Anyways, sa ibang videos ay nakashare na!
engr. hindi ba sin60 pag Ry ? at cos60 pag Rx?
Yung 60 degrees para sa F2 ay with respect to vertical kaya baliktad.
@@harfmiranda nagets ko na po yon nakalimutan ko sa 60 degrees pala nakadepende tsaka tanong ko lang po sa last prob po behind the dam is yong sa down stream po, tsaka ang upstream naman is ang face ng dam po, pano po naging behind the dam ang ang nasa upstream? or mali lng sguro pagkaintindi ko hehe
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I remember asking Jerome to request for this topic 🙏🙏 Thank you sa videos sir, best bingewatch pampagising at bago matulog
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Galing sir! thank you po . sir request lang sir Sets naman po sa theory of struct sir.
Salamat sa suggestion!
Malapit na sir 🥲
Magpapaskong engr!
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Salamat po Engr. 😇
Sir kakatapos ko lang lahat ng mstc refresher videos mo maraming salamat. Sir suggest lang po ako ng topic yong "Newtons Law of Cooling" po paturo? 😅
Salamat po sa suggestion! 😁
Thank you po sir maliwaag Ang pag explain .
Sa last part sir parang pwedi ata Yung e relate Yung force na nakuha sa first solution which is (442.36)/(pi(1.4)^2*4)=(200)/(pi(1.4)^2(x) Ans. 1.8 din pero not sure Kung Tama sir Yung way ng solution.
Yes pwede for this problem. 😃
Nice one sir. More videos to come. @@harfmiranda
Sir meron ka po sa bolted and welded connections?
PSAD SITUATION 7: Eccentrically Loaded Bolt in Spliced Beam th-cam.com/video/EzJUnSLW-mU/w-d-xo.html Check mo din Situation 2 sa playlist na yan. Wala pang welded na nagagawa
@harfmiranda wala po kayong full discussion?
Wala pa sa ngayon. Gagawa soon
Yung nasa right po ang upstream side dyan sir. Kasi doon po mas mataas ang water level. Bali sa right side rin po ang behind ng dam. 😊
Ahh gets ko po point niyo. Salamat po! 👌
Tnx ner dto ako nalito kung san consider ang behind
Good day po, sir, ganoon po ba lagi na kapag maximum ang hinahanap ay pa-right po ang direction ng horizontal? Thank you po.
Hindi po. Depende po sa magiging direction ng impending motion. Dito kaya pa-right kasi kapag sinobrahan ang P, babaluktot to the right ang structure. Kaya i-limit lang sa Pmax ang P sa condition na to the right. Depende padin po sa context ng problem ang direction ng friction. Basta lagi dapat na opposite sa direction ng impending motion ang direction ng friction.
Noted po, thank you
Sir hindi na po ba icoconsider yung weight ng water sa downstream side for the resisting force?
Yung given na F2 ay resultant na ng horizontal hydrostatic force and downward na weight ng water sa downstream side. 😃
@@harfmiranda may nakita po kasi akong kinuha muna yung y component ng F2 tapos dinagdag sa total weight ng dam
Sa pagcompute ng Ry? Yup ginawa ko din yun, dineretso ko nalang sa sum forces along y.
Sir bakit hindi na po kinonsider yung uplift force?
Nagkaka uplift force lang kung may seepage under the dam. Wala din naman binanggit sa problem kaya di na cinonsider. 🙂
Power🔥
mali po garod yung nasa ce ref neer? dun sa question 3 po
Yung height behind the dam is upstream side. So sa likod (nasa left side) kaya yun yung ginawa ko. Yung sagot ni ce ref ay sa front (downstream side), which is ginawa ko din sa dulo ng video. 🙂
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Salamat sa patuloy na pagtangkilik!
@@harfmiranda Salamat din Engr sa mga videos mo, baunin ko ito sa papalapit na CELE. 🙏
@@harfmiranda Engr, may fb page ka po?
Pa support nalang din ng Review center namin. 🙂 facebook.com/profile.php?id=61558154752906&mibextid=LQQJ4d
Hello Engr. Harf, for #46, clarify ko lang po, hindi po ba consider na D is inside diameter? stress=p(500-2*t)/4t. Thanks and more power to you!
Yes technically inside diameter ang D dun sa pD/2t or /4t. However, di naman specified kung outside or inside diameter ba yung given na 500. Kaya inassume nalang na inside nadin yun. If you recalculate considering outside diameter yung 500, same lang din ang sagot and may konting discrepancy lang. 😃
Sir baka nag round off si examiner ng 1.97. 1.97-1.8= 0.17m tama po ba sir?
Actually ako lang ang naglagay ng ibang choices jan. 161 yung answer sa ce ref which I think is typo error. Pero kung ganyan, pwede nga na sagot yung 170 if rounded off to 2 decimals yung y. 😊
@@harfmirandaOk po sir. 😅
soliiiiiiiidddddd nonsense na pala yungbsteel ration and Rn
Oo. Humahaba lang yung kakabisaduhin. Hehe
solid ka boss wala ng steel ratio, ayoss
Sir don sa block shear failure, yong naggovern po ba don sa tingin mo yon ang always maggogovern na path of failure para matandaan na lang or need talaga icheck yong tatlong path? Hehe.
Hindi ko masasabi na yun lagi ang magovern. Depende padin sa dimensions. Pero ang technique jan sa board exam, pag may natry kang isang block shear path tapos sa choices yun na yung pinakamaliit. Yun na yung sagot. 😃
@harfmiranda Ok sir thanks.
Sir pwede po panotice sa facebook?
Sir magkaiba po yong length of transition curve (V^3/CR) at length of spiral curve?
Ang spiral curve po ay transition curve. Same lang bossing
@harfmiranda Thank you sir.
Thank you master...😊
Thank you Sir!
Thank you very much, Engr/Sir Harf! Very helpful to self-reviewees like me.. Please find time to create a video about Absolut Volume method of calculating materials in concrete. More power, Sir! 😊
Salamat po sa suggestion!
30:40 sana all kaya na niyang ayusin yung sarili niya, yung iba kasi hindi. harhar.😅😅😅
21:45 my favorite whole number. HAHA. But kidding aside boss, naiintindihan ko talaga siya comprehensively. salamat po
Ayos! Hehe
Sir idol, ibig sabihin po kapag naging negative yong F na sinolve sa assummtion ay baliktad po dapat?
Yes bossing! Ibig sabihin din mali ang assumption na yung plane na yung ang major principal plane.
@harfmiranda Ok sir.
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Boss bakit sa ibang review center 3/7 ang numeral fraction part sa formula na rhomax?
3/7 accdg to NSCP, considering minimum steel strain of 0.004. Pero note that transition zone lang to and ang reduction factor ay 0.65<phi<0.90 3/8 considering steel strain of 0.005 and at the same time tension controlled phi = 0.90. Check out my other videos minention ko ito. Thank you sa panonood!
@harfmiranda Noted po sir, salamat.
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Sir sana maturo mo din yung eccentric welded connection ng steel. Thanks
Will upload soon boss!