Aastha Chemistry Classes
Aastha Chemistry Classes
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Ion electron Method || Cl2 + IO3^- + OH^- = IO4^- + Cl^- + H2O ||
Content in the video lecture -
Balance the given Redox Reaction by Ion Electron Method
Cl2 + IO3^- + OH^- = IO4^- + Cl^- + H2O
In this video lecture, we will explore the step-by-step process of balancing redox reactions using the ion-electron method. This method, also known as the half-reaction method, is widely used to balance complex chemical reactions involving oxidation and reduction. The lecture will cover key concepts such as identifying oxidation and reduction half-reactions, balancing atoms and charges, and combining the half-reactions to obtain the balanced overall equation. By the end of this session, you will gain a clear understanding of the principles and techniques required to accurately balance redox equations using this systematic approach.
Welcome to Aastha Chemistry Classes! Our channel is dedicated to helping students excel in chemistry, whether you’re preparing for UP, CBSE, or other state board exams, or aiming for competitive exams like IIT JEE, NEET, MHCET, KVPY, and more.
We provide high-quality content to strengthen your understanding and boost your confidence for both board and competitive exams. Our videos cover a wide range of topics, from foundational concepts to advanced problem-solving techniques, presented in a clear and easy-to-understand format.
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มุมมอง: 14

วีดีโอ

Ion electron Method || I2 + OH^- = IO3^- + I^- + H2O ||
มุมมอง 1819 ชั่วโมงที่ผ่านมา
Content in the video lecture - Balance the given Redox Reaction by Ion Electron Method I2 OH^- = IO3^- I^- H2O In this video lecture, we will explore the step-by-step process of balancing redox reactions using the ion-electron method. This method, also known as the half-reaction method, is widely used to balance complex chemical reactions involving oxidation and reduction. The lecture will cove...
Ion electron Method || Cr2O7^(-2) + I^- + H^+ = Cr+3 + I2 + H2O ||
มุมมอง 519 ชั่วโมงที่ผ่านมา
Content in the video lecture - Balance the given Redox Reaction by Ion Electron Method Cr2O7^(-2) I^- H^ = Cr 3 I2 H2O In this video lecture, we will explore the step-by-step process of balancing redox reactions using the ion-electron method. This method, also known as the half-reaction method, is widely used to balance complex chemical reactions involving oxidation and reduction. The lecture w...
Ion electron Method ||MnO4^- + C2O4^(-2) + H^+ = Mn+2 + CO2 + H2O||
มุมมอง 1019 ชั่วโมงที่ผ่านมา
Content in the video lecture - Balance the given Redox Reaction by Ion Electron Method MnO4^- C2O4^(-2) H^ = Mn 2 CO2 H2O In this video lecture, we will explore the step-by-step process of balancing redox reactions using the ion-electron method. This method, also known as the half-reaction method, is widely used to balance complex chemical reactions involving oxidation and reduction. The lectur...
Ion electron Method || 𝟐𝑰𝑶𝟑^− + 𝒙𝑰^− + 𝟏𝟐𝑯^+ = 6I2 + 6H2O. What is the value of x? ||
มุมมอง 1514 วันที่ผ่านมา
Content in the video lecture - 𝟐𝑰𝑶𝟑^− 𝒙𝑰^− 𝟏𝟐𝑯^ = 6I2 6H2O. What is the value of x? In this video lecture, we will explore the step-by-step process of balancing redox reactions using the ion-electron method. This method, also known as the half-reaction method, is widely used to balance complex chemical reactions involving oxidation and reduction. The lecture will cover key concepts such as iden...
𝑴𝒏𝑶𝟒^(− ) + Fe+2 + H+ = Mn+2 + Fe+3 + H2O || Ion Electron Method ||
มุมมอง 2114 วันที่ผ่านมา
Content in the video lecture - Balance the given Redox Reaction by Ion Electron Method 𝑴𝒏𝑶𝟒^(− ) Fe 2 H = Mn 2 Fe 3 H2O In this video lecture, we will explore the step-by-step process of balancing redox reactions using the ion-electron method. This method, also known as the half-reaction method, is widely used to balance complex chemical reactions involving oxidation and reduction. The lecture ...
Acid - Base Titration- IIT JEE Problem 2019 || Stoichiometry & Volumetric Analysis ||
มุมมอง 15หลายเดือนก่อน
The content in the video lecture- 25 ml of the given HCl solution requires 30 mL of 0.1 M sodium carbonate solution. What is the volume of this HCl solution required to titrate 30 mL of 0.2 M aqueous NaOH solution? Welcome to Aastha Chemistry Classes! Our channel is dedicated to helping students excel in chemistry, whether you’re preparing for UP, CBSE, or other state board exams, or aiming for...
Equivalent Mass of H3PO4 when neutralised to 𝑯𝑷𝑶𝟒^(−𝟐), HClO4, NaIO3, AI(OH)3, SO2 ||ACC||
มุมมอง 20หลายเดือนก่อน
Content in this Video Lecture- Question - What is the equivalent mass of : 1). H3PO4 when neutralised to 𝑯𝑷𝑶_𝟒^(−𝟐) 2). HClO4 3). NaIO3 when reduced to 𝑰^− 4) NaIO3 when reduced to I2 5). AI(OH)3 6). SO2 to 𝑺𝑶_𝟒^(−𝟐) Welcome to Aastha Chemistry Classes! Our channel is dedicated to helping students excel in chemistry, whether you’re preparing for UP, CBSE, or other state board exams, or aiming f...
Normality, Relation between Normality & Molarity & Equivalent Weight ||ACC||
มุมมอง 26หลายเดือนก่อน
Content in this Video Lecture- Normality, Relation between Normality & Molarity & Equivalent Weight Welcome to Aastha Chemistry Classes! Our channel is dedicated to helping students excel in chemistry, whether you’re preparing for UP, CBSE, or other state board exams, or aiming for competitive exams like IIT JEE, NEET, MHCET, KVPY, and more. We provide high-quality content to strengthen your un...
n - factor or Valence factor || Stoichiometry & Volumetric Analysis ||
มุมมอง 35หลายเดือนก่อน
The content in the video lecture on “n-factor or Valence factor” in acids and bases likely covers the following: Understanding the Valence Factor (n-factor): Definition of the n-factor, a measure of the change in oxidation state or the number of ions produced in acid-base reactions. Its relevance in chemical reactions, particularly in acid-base titrations and redox reactions. n-factor in Acids:...
Volumetric Analysis IIT JEE Problem || Redox Reaction ||
มุมมอง 39หลายเดือนก่อน
Content in this Video Lecture- 50 mL of 0.5 M oxalic acid is needed to neutralize 25 mL of sodium hydroxide solution. The amount (in g) of NaOH in 50 mL of the given sodium hydroxide solution is : (1) 10g (2) 4 g (3) 20g (4) 80g Welcome to Aastha Chemistry Classes! Our channel is dedicated to helping students excel in chemistry, whether you’re preparing for UP, CBSE, or other state board exams,...
JEE Advanced 2023 || Chemical Bonding ||
มุมมอง 283 หลายเดือนก่อน
Content in this Video Lecture- Among [I3] , [SiO4]-4, SO2Cl2, XeF2, SF4, ClF3, Ni(CO)4, XeO2F2, [PtCl4]-2, XeF4 & SOCl2, the total number of species having sp3 hybridised central atom is . Welcome to Aastha Chemistry Classes! Our channel is dedicated to helping students excel in chemistry, whether you’re preparing for UP, CBSE, or other state board exams, or aiming for competitive exams like II...
JEE Advanced 2024 || Chemical Bonding ||
มุมมอง 343 หลายเดือนก่อน
Content in this Video Lecture- Based on VSEPR model, match the xenon compounds given in List-I with the corresponding geometries and the number of lone pairs on xenon given in List-II and choose the correct option. List -I (P) XeF2 (Q) XeF4 (R) XeO3 (S) XeO3F2 List - II (1) Trigonal bipyramidal and two lone pair of electrons (2) Tetrahedral and one lone pair of electrons (3) Octahedral and two ...
JEE Advanced 2022 || Coordination Compound ||
มุมมอง 433 หลายเดือนก่อน
Content in this Video Lecture- LIST-I contains metal species and LIST-II contains their properties List -I [Cr(CN)6]4- (P) t2g orbitals contain 4 electrons (II) [RuCl6]2- (Q) μ (spin - only) = 4.9 BM (III) [Cr(H2O6)]2 (R) Low spin complex ion (IV) [Fe(H2O)6]2 (S) Metal ion in 4 oxidation state (T) d4 species [Given: Atomic number of Cr = 24, Ru = 44, Fe = 26] Match each metal species in LIST-I ...
JEE Advanced 2023 || Coordination Compound ||
มุมมอง 843 หลายเดือนก่อน
Match the electronic configurations in List-I with appropriate metal complex ions in List-II and choose the correct option. [Atomic Number: Fe =26; Co = 27; Mn = 25 ] Our video is useful for Up /CBSE/ICSE Board students as well as students who are preparing for IIT JEE/ KVPY and other useful exams. On this TH-cam channel we will give you better content which will help you in your board exams as...
JEE Advanced 2024 || Coordination Compound ||
มุมมอง 434 หลายเดือนก่อน
JEE Advanced 2024 || Coordination Compound ||
IIT JEE Main 2024; 6th April || Chemistry, Solution Chapter ||
มุมมอง 2077 หลายเดือนก่อน
IIT JEE Main 2024; 6th April || Chemistry, Solution Chapter ||
IIT JEE Main 2024; 8th April || Chemistry, Solution Chapter ||
มุมมอง 367 หลายเดือนก่อน
IIT JEE Main 2024; 8th April || Chemistry, Solution Chapter ||
Solution Chapter IIT JEE MAIN 2024 ||Aastha Chemistry Classes||
มุมมอง 617 หลายเดือนก่อน
Solution Chapter IIT JEE MAIN 2024 ||Aastha Chemistry Classes||
Diamond and Graphite ||NEET 2022||
มุมมอง 362 ปีที่แล้ว
Diamond and Graphite ||NEET 2022||
Amongst the following which one will have maximum 'lone pair - lone pair' electron repulsions? NEET
มุมมอง 632 ปีที่แล้ว
Amongst the following which one will have maximum 'lone pair - lone pair' electron repulsions? NEET
The correct IUPAC name of the following compound is || NEET 2022 ||
มุมมอง 1882 ปีที่แล้ว
The correct IUPAC name of the following compound is || NEET 2022 ||
जीवों में अलैंगिक जनन (Asexual Reproduction in Animals) ||ASC||
มุมมอง 252 ปีที่แล้ว
जीवों में अलैंगिक जनन (Asexual Reproduction in Animals) ||ASC||
Packing Fraction of hcp & JEE Advanced Problem (2008) ||ASC||
มุมมอง 662 ปีที่แล้ว
Packing Fraction of hcp & JEE Advanced Problem (2008) ||ASC||
Volume of hcp (Hexagonal Closed Packing) ||ASC||
มุมมอง 1352 ปีที่แล้ว
Volume of hcp (Hexagonal Closed Packing) ||ASC||
∫{x*tan(x)/(sec(x) + tan(x))}dx from 0 to π ||NCERT||
มุมมอง 2092 ปีที่แล้ว
∫{x*tan(x)/(sec(x) tan(x))}dx from 0 to π ||NCERT||
∫{1/(1 + cot(x))}dx from 0 to π/2 ||NCERT||
มุมมอง 282 ปีที่แล้ว
∫{1/(1 cot(x))}dx from 0 to π/2 ||NCERT||
∫{(x sinx)/(1 + cos^2 (x))}dx from 0 to π ||NCERT||
มุมมอง 532 ปีที่แล้ว
∫{(x sinx)/(1 cos^2 (x))}dx from 0 to π ||NCERT||
Fajan's Rule - Covalent Nature of Ionic Compounds ||ASC||
มุมมอง 832 ปีที่แล้ว
Fajan's Rule - Covalent Nature of Ionic Compounds ||ASC||
Matrix- NCERT Exercise 3.1 ||ASC||
มุมมอง 293 ปีที่แล้ว
Matrix- NCERT Exercise 3.1 ||ASC||

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