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yes it can be applied. However, phases depend on the nature of substances and their weight losses. In your case may be more or less but remember each phase has the same way of calculation.

you can watch my other videos, pl

"Yes sir, but please provide the video link related to my doubt on how to read the adsorption model."

when you plot a graph on MS excel with straight line equation, you will directly get the values from equation y = mx + c

Please help us on how to find the slope of intercept

​@MuhammadAkhyarFarrukh but it's kinda confusing

@@jesugbogoenis it is explained. It can be directly get from straight line equation and with m and c. Like y = mx+c

Iv to do this in exam .. pen paper no excel and all pls help

I am sure you are using SPR-surface plasma resonance spectroscopy. If possible, dilute your sample to reduce the absorbance. Try to take absorbance of films with small concentration to avoid reflection of light. Apply baseline correction to your UV-Vis data to reduce noise.

I have already explained in video. This is just because 0.0001 is taken as common on y-axis (to smooth the y-axis) and when you multiply with 0.0398 it will become 0.00000398, because you have to multiply to get original value. If you do not take it as common, then it will directly give you the value of intercept of 0.00000398.

Due to the calculation of crystallite size. No conversion is required for d spacing, which distance between the two layers

The slope will be best if R*2 value is 1 (taken from straight line equation). I use the equation as discussed in video or please watch other videos doe detail.

his are wrong

it is in %, the same as data is received from TGA

ok thank you very much , if i understand with 1/T we have directly the value in j/mol right ? @@MuhammadAkhyarFarrukh

is it to find direty the ativation energy in j.mol^-1

Just to convert fraction into whole number but you need to multiply 1000 with slope again to get original value. If you plot without multiply 1000 with 1/T then no need to multiply slope again with 1000. Both ways will give same values.

Im phd student in china and I realy wont to know more is it possible to contact you @@MuhammadAkhyarFarrukh

​so with 1/T we have directly the value in j/mol also?@@MuhammadAkhyarFarrukh

Just divide the mass of adsorbent with Vm, you have taken for the study. If it is 1g then the value will remain the same.

understood one last thing that i had confussion! to find Vm we use 1/ slope + intercept then the unit if vm is not in cm^ -3

@@physicswithsirmuneer8975 dividing by 1, negative becomes positive

Thank you finally i got it actually slope has unit cm^-3 or /cm^3 so that when we divide by 1 we get unit cm^3 thank you very much nice and motivated video

Hello. I have basically the same question. If the Stot is in cm^3/g then if i divide it further by the mass of adsorbent (cm^3/g) / g will give me cm^3/g^2 Also it doesnt make sense that i take the sample of 0.1g and Stot will give ...lets say 10 cm^3/g Dividing Stot by 0.1 will grant 10 times higher value so 10cm^3/g will become 100 cm^3 / g^2 The only resonable calculation would be if Vm was given in cm^3 and not cm^3/g Then Stot would be the surface of the measured sample and further calculation would grant the result per gram - by incorporation of the sample mass So Stot = 10 cm^3 Stot/mass = 10cm^3/0.1g = 100cm^3/g ==> BET surf.

Usually, nanoparticles are stable and insoluble in water. There is possibility of scattering of light. You have to prepare low concentration by taken solid NPs in solvent and then sonicate and/or stir for few minutes unless find some clear solution. If problem continues then you can centrifuge and take spectra of filtrate because you do not need exact concentration for spectra. OR you can run Solid Phase, if having facility of SPR.

It is 20K/min. However if it is 20C/min then also no change as we are taking only difference of temperature after one minutes and that would be same in both cases. A is s-1. You can refer to publications. I am in China and might not discuss more.

To convert kilo joule into joule because activation energy will be calculate by multiplying slope with R gas constant that is equal to 8.314 J-K/ mole

yes same

@@MuhammadAkhyarFarrukh thank you sir

This is the last value of weight loss, I have explained in video.