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Physix Daily
เข้าร่วมเมื่อ 3 มี.ค. 2021
I am Prottoy.
I am an undergrad at Bard College, NY.
My goal in this channel is to provide free education in simple and understandable language.
I love Physics.
I love teaching.
Enjoy :)
I am an undergrad at Bard College, NY.
My goal in this channel is to provide free education in simple and understandable language.
I love Physics.
I love teaching.
Enjoy :)
Problem 2.26 : Introduction to Electrodynamics _ Griffiths. V between two points of a cone
Problem 2.26 : Introduction to Electrodynamics _ Griffiths. V between two points of a cone
มุมมอง: 696
วีดีโอ
Problem 2.6 : Introduction to Electrodynamics_Griffiths - E field above the center of a flat disk
มุมมอง 5310 หลายเดือนก่อน
Problem 2.6 : Introduction to Electrodynamics_Griffiths - E field above the center of a flat disk
Problem 2.10: Intro to Quantum Mechanics_Griffiths. Simple Harmonic Oscillator & Ladder Operators
มุมมอง 275ปีที่แล้ว
Problem 2.10: Intro to Quantum Mechanics_Griffiths. Simple Harmonic Oscillator & Ladder Operators
Quantum Simple Harmonic Oscillator, Wave Functions, Intro to Ladder Operators, Hermite Polynomials
มุมมอง 621ปีที่แล้ว
Quantum Simple Harmonic Oscillator, Wave Functions, Intro to Ladder Operators, Hermite Polynomials
Problem 2.5: Introduction to Quantum Mechanics by David Griffiths
มุมมอง 691ปีที่แล้ว
Problem 2.4 : th-cam.com/video/GdTpK418Ppo/w-d-xo.html
What is the Hamiltonian? : Kinetic energy & momentum operators, and the updated Schrodinger Equation
มุมมอง 620ปีที่แล้ว
What is the Hamiltonian? : Kinetic energy & momentum operators, and the updated Schrodinger Equation
Using the Orthogonality of Stationary States to find c_n co-efficients in the Infinite Square Well
มุมมอง 178ปีที่แล้ว
Using the Orthogonality of Stationary States to find c_n co-efficients in the Infinite Square Well
Problem 2.4: Introduction to Quantum Mechanics - David Griffiths
มุมมอง 1.4Kปีที่แล้ว
Problem 2.4: Introduction to Quantum Mechanics - David Griffiths
Allowed Energy of particle trapped in the Infinite Square Well
มุมมอง 185ปีที่แล้ว
Here is the link to the Derivation of the Wave Function of particle in the Infinite Square Well: th-cam.com/video/Ho-iJ-iR6lE/w-d-xo.html
The Infinite Square Well: Deriving the Wave Function
มุมมอง 293ปีที่แล้ว
The Infinite Square Well: Deriving the Wave Function
The Photoelectric Effect - Introduction
มุมมอง 1752 ปีที่แล้ว
The Photoelectric Effect - Introduction
Derivation of the Mirror / Lens Equation
มุมมอง 1312 ปีที่แล้ว
Derivation of the Mirror / Lens Equation
How to derive displacement function of Simple Harmonic Motion
มุมมอง 1.7K2 ปีที่แล้ว
How to derive displacement function of Simple Harmonic Motion
Deducing Lorentz Transformation Equations
มุมมอง 4622 ปีที่แล้ว
Deducing Lorentz Transformation Equations
Classic Problem 6 - Calculating Amplitude and Time Period in SHM
มุมมอง 9782 ปีที่แล้ว
Classic Problem 6 - Calculating Amplitude and Time Period in SHM
Springs, Mechanisms, Time Period and Work
มุมมอง 1.9K3 ปีที่แล้ว
Springs, Mechanisms, Time Period and Work
Introduction to Simple Harmonic Motion (SHM) | General Equation and Derivation
มุมมอง 86K3 ปีที่แล้ว
Introduction to Simple Harmonic Motion (SHM) | General Equation and Derivation
Carnot's Engine | Mechanism and Work Done
มุมมอง 903 ปีที่แล้ว
Carnot's Engine | Mechanism and Work Done
The Second and Third Law of Thermodynamics Explained in 6 mins
มุมมอง 733 ปีที่แล้ว
The Second and Third Law of Thermodynamics Explained in 6 mins
Change in Entropy in Different Thermodynamics Processes
มุมมอง 6293 ปีที่แล้ว
Change in Entropy in Different Thermodynamics Processes
Classic Problem 5 | Calculating "g" from time of flight
มุมมอง 3683 ปีที่แล้ว
Classic Problem 5 | Calculating "g" from time of flight
Classic Problem 4 | Use of 1st Law of Thermodynamics
มุมมอง 1443 ปีที่แล้ว
Classic Problem 4 | Use of 1st Law of Thermodynamics
Why is Adiabatic Curve steeper than Isothermal Curve
มุมมอง 17K3 ปีที่แล้ว
Why is Adiabatic Curve steeper than Isothermal Curve
Work Done in a Thermodynamic Process Part 2 | Adiabatic Process
มุมมอง 3553 ปีที่แล้ว
Work Done in a Thermodynamic Process Part 2 | Adiabatic Process
Relationship between Thermodynamics Variables in Adiabatic Process
มุมมอง 1933 ปีที่แล้ว
Relationship between Thermodynamics Variables in Adiabatic Process
nice videooo !
super underrated channel thank u so much!!
Like it
It's a pretty good video, but using the same symbol for 2 different quantities (k for kinetic energy, and for the force constant) is a bit confusing.
I came here for the integration part in the last..but he directly gave the results! 🥲
This tutorial need another tutorial
😮Thank you so much
Thanks a lot sir.. explained clearly...
You used wrong formula in part 1 But the answer will came Sin^2x = 1- cos2x/2 Cos term will give zero
Why in the beginning x =ct ! Why there is c isn't x =vt , why every explanation someone had to do something looks wrong ?
Why don't you make your own videos that will be error free.
W
In the letter a of the question, you use the propriety of kronecker delta to solve those integrals, and i got that. But explain to me why, on letter c you can't use the same propriety as doing the integrals by parts. For example, can't you use x=u implies du=dx, and dv= |psi1|^2dx implies v=1? I did by this and had the expect value equal 0. I know that is wrong because it doesn't make any sense physically, but i don't got why i can't use integration by parts :( Nice video, by the way! Very very good (sorry for my poor English).
How c= 1/2 A^2w^2
If you choose the moment where the velocity is 0, you can find the exact value of c by eliminating the v variable
nice video
Correct me if im wrong but in part d for <p> isnt the answer (8/3)*(h bar/a)*sin(3ωt) ? also at 20:40 and 12:10 its stated that the ω=n^2*π^2*hbar^2/2ma^2 but h bar constant is h bar not h bar squared in ω equals
Thank you for your feedback. You're exactly right. What I missed in the very last line was the omega factor which I forgot to add. If you add in omega in the last line, you should be able to simplify to whatever you have.
omg this was so helpful thank you.
What’s c mean
That's an integration constant
Nice explanation bro
0:40 Isnt x away from the equilibrium position
Isn't it cos
you can use cos or use sine. Both works.
But isn't it cos??
B cos(wt + C), still can do
I saw other videos but this one mad most sense to me
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Thank you for this Protty. It was really helpful.
You're welcome Fatuma. I'm glad my videos reached you
Sir can you please make a video on derivation of wave motion. Plzz sir
Cool thank you!
Thanks dude <3
4:11 Isn't there a +C when you are integrating the velocity and if there is, why is there a +C on the other side of the equation? Don't the +C's cancel each other out?
No, there are different constants on each side, they don’t cancel each other out, you can call them for example c1 and c2, you subtract c1 on both sides and ur left with c2-c1 in the right hand side, and a constant minus another constant is a new constant, which you denote just c
At 03:20, he mentioned about the chain rule. Which part is it? Why dv/dt = dv/dx*dx/dt? Can someone explain?
Part of chain rule the dx and dx cancel out and we get dv/dt
Thanks.
Thanks brother
Thanks a lot 😃
Amazing video!!!😍 I had a question in pendulum which I couldn't figure out🥺. How can I send it to you?😇
Hi! Email me at prottoymahdisamir@gmail.com
@@physixdaily6223 Thanks a lot for the assistance!!!! Just mailed u😁.
At last, somone who explains it... Thank u!!!
it's an ok explanation. He doesn't explain where the "second derivative" comes from.
@@DdoubleB03 I am explaining u.In case of 1st derivative of acceleration,we get dv/dt.After then, when we differenciate the velocity again we gets lastly d^2x/dt^2. this is how the "second derivative" comes from.
A song like this will definitely have international appeal. Just look at the comments.
This video is helpful 😀 thank sir
Thanks you sir in this concept is completed 😀 simple harmonic motion
A=amplitude X=Amplitude X=A Sqrt(A^2 - X^2) Sqrt(0)?????
X is a variable which we are analysing its behaviour as the time goes. So it is not always the same thing as the Amplitude. If they're same at a point, it means that the object moved as far as possible from the starting point which have now became as big as the position vector of the amplitude. So yeah it would be 0 in this case but you're forgetting that this term is inside of the cos function, so cos(0) would be 1 and x = A (Amplitude) as intented to be.
Please to solve the problems 2.11,2.12
Thank you. I'll post the solutions of those then!
2.12 and 2.13 Ka solution
I'll post them too!
Thanks
Unbelievable.! You taught the topic very easily within a few minutes.
Well done sir. Thank you
Best video so far
Im amazed by this form, thanks a lot bro !
Please sir which software did you used to record your videos🙏
How ω² = k/m , can anyone explain
the w itself is root of k/m then k/m equals to the ω²
@@eymendediler5357but how do you derive w = k/m? is this purely definitional?
@@mailingbox F = mw^2x = kx
@@mailingboxIt is purely definitional.
To find acceleration of a particle at maximum position from its equilibrium state from Newtown law we use a=F÷m F=-kx we take k÷m as beta during derivation we get root beta and we denote it as omega . So omega square is k÷m
It is best on you tube 🎉
I WANT TO KNOW THE LOGIC OF ? IS THIS A CONVENTION ? OR WE CAN PROVE IT BY TAKING INTO 2D
THNX FOR RESOLVING MY DOUBT