วีดีโอ

❤❤

❤❤

❤❤❤

😢😢😢

😮😮😮

😂😂😂😂

❤❤

❤❤❤

❤❤❤

Euler's famous equation: e^{iπ}+1=0 or e^{iπ+2ijπ}=-1, i=√(-1) & j any integer. Thus x^4=-1=e^{iπ+2ijπ},j=0,1,2,3 & x_j=e^{iπ/4+ijπ/2}=cos(π/4+jπ/2)+i*sin(π/4+jπ/2),j=0,1,2,3 x_0=cos(π/4)+i*sin(π/4)=(√2/2)(1+i), x_1=(√2/2)(-1+i), x_2=(√2/2)(-1-i), and x_3=(√2/2)(1-i)

Very good

Good

5 x 5 baraz 45 plus 45 baraz 90

X barac me 2

Song name plz

❤❤❤❤

😢😢😢😢

১১১১

❤❤❤

😢😢😢

❤❤❤

❤❤❤❤

😂😂😂

৭৭৭

❤❤❤

❤❤❤

❤❤❤❤

❤❤❤

❤❤❤

❤❤❤

X=2 log 5/3 +1

log 5**× = log 45 ⁵ ⁵ X = log 45 ⁵ X = log (3² * 5) ⁵ Х= 1 + 2log 3 ⁵

±72i

I think you just have to multiply by sqrt(a) on first line and then solve the equation for sqrt(a) and finished

???

LoL😮

5×5=45×4=90

x=log45/log5≈(0,95+0,7)/0,7≈33/14≈2,357. Absolute error is about 0,008.

Very nice solution.

My way to solve 5X = 45 Using log , X = log 45 / log 5 = 2,36521 Bingo from brazil !!!!

Log 45 to base 5

Write with thick pen. No one can read your handwriting.

27+64+125=216*1000^1/2 =6*10*60.^1/2= 60*60,^1/2 Mukund

Golden Ratio problem: φ=(√5-1)/2; φ^6=5-8φ=9-4√5=0.055728090000841 First described by Fibonacci? Check: (√15-√3)/√12=0.618033988749895=φ; [(√15-√3)/√12]^6=φ^6

O K. Thanks.

Sqrt(4) = 2 2^x + 2^x = 2*2^x 2*2^x / 2^x = 2^x 2^x = ? // cant be solved idk what this guy is on about

nicee

The difference between the two is -2. (27^0) - (3^1) = 1 - 3 = -2.

27^0=1 and 3^1=3

One answer: exponent is zero. 1/1 = 1