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Learning by Teaching
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เข้าร่วมเมื่อ 3 ส.ค. 2020
Mechanical Engineer student Learning By Teaching.
Mathematics and Engineering
Mathematics and Engineering
Statics 1-8| Represent each of the following combinations of units in the correct SI form
Question: Represent each of the following combinations of units in the correct SI form using an appropriate prefix: (a) Mg/mm, (b) mN/us, (c) um*Mg
Engineering Mechanics: Statics, 14th edition
Russell C. Hibbeler
Thank you guys for watching. If you would like to donate use the link below to my Patreon:
patreon.com/LearningByTeaching
Please let me know if you have any comments or suggestions and also if you have any other problem you would like to go over with.
Engineering Mechanics: Statics, 14th edition
Russell C. Hibbeler
Thank you guys for watching. If you would like to donate use the link below to my Patreon:
patreon.com/LearningByTeaching
Please let me know if you have any comments or suggestions and also if you have any other problem you would like to go over with.
มุมมอง: 482
วีดีโอ
Statics 1-7| Represent each of the following quantities in the correct SI form
มุมมอง 108หลายเดือนก่อน
Question: Represent each of the following quantities in the correct SI form using an appropriate prefix: (1) 0.000431 kg, (b) 35.3(10^3) N, (c) 0.00532 km. Engineering Mechanics: Statics, 14th edition Russell C. Hibbeler Thank you guys for watching. If you would like to donate use the link below to my Patreon: patreon.com/LearningByTeaching Please let me know if you have any comments or suggest...
Statics 1-6| Round off the following numbers to three significant figures
มุมมอง 58หลายเดือนก่อน
Question: Round off the following numbers to three significant figures: (a) 58342 m, (b) 68.534 s, (c) 2553 N, and (d) 7555 kg. Problem 1-6 from: Engineering Mechanics: Statics, 14th edition Russell C. Hibbeler How to do significant figures. Thank you guys for watching. If you would like to donate use the link below to my Patreon: patreon.com/LearningByTeaching Please let me know if you have an...
Statics 1-5| Represent each of the following as a number between 0.1 and 1000 using prefix.
มุมมอง 1362 หลายเดือนก่อน
Question: Represent each of the following as a number between 0.1 and 1000 using an appropriate prefix: (a) 45320 kN, (b) 568(10^5) mm. and (c) 0.00563 mg. Problem 1-5 from: Engineering Mechanics: Statics, 14th edition Russell C. Hibbeler Thank you guys for watching. If you would like to donate use the link below to my Patreon: patreon.com/LearningByTeaching Please let me know if you have any c...
Statics 1-4 | How to convert units from English (FPS) to metric (SI).
มุมมอง 1292 หลายเดือนก่อน
Question: Convert: (a) 200 lb ft to N m,(b) 350 lb/ft^3 to kN/m^3, (c) 8 ft/h to mm/s. Express the result to three significant figures. Use an appropriate prefix. Problem 1-4 from: Engineering Mechanics: Statics, 14th edition Russell C. Hibbeler Thank you guys for watching. If you would like to donate use the link below to my Patreon: patreon.com/LearningByTeaching Please let me know if you hav...
Statics 1-3| Represent each of the following combinations of units in the correct SI form.
มุมมอง 1602 หลายเดือนก่อน
Question: Represent each of the following combinations of units in the correct SI form: (a) Mg/ms, (b) N/mm, (c) mN/(kg*us). Problem 1-3 from: Engineering Mechanics: Statics, 14th edition Russell C. Hibbeler Thank you guys for watching. If you would like to donate use the link below to my Patreon: patreon.com/LearningByTeaching Previous problem 1-2: th-cam.com/video/VL3HtuNrmxM/w-d-xo.html Plea...
Statics 1-2| Represent each of the following combinations of units in the correct SI form
มุมมอง 1762 หลายเดือนก่อน
Question: Represent each of the following combinations of units in the correct SI form: (a) kN/us, (b) Mg/mN, and (c) MN/(kg*ms). Problem 1-2 from: Engineering Mechanics: Statics, 14th edition Russell C. Hibbeler Thank you guys for watching. If you would like to donate use the link below to my Patreon: patreon.com/LearningByTeaching Please let me know if you have any comments or suggestions and...
Statics 9-1| Locate the center of mass of the homogeneous rod bent into the shape of a circular arc.
มุมมอง 6943 หลายเดือนก่อน
Question: Locate the center of mass of the homogeneous rod bent into the shape of a circular arc. Problem 9-1 from: Engineering Mechanics: Dynamics, 14th edition Russell C. Hibbeler Thank you guys for watching. If you would like to donate use the link below to my Patreon: patreon.com/LearningByTeaching Please let me know if you have any comments or suggestions and also if you have any other pro...
Dynamics 17-96| The pool has a mass of 100 kg and a radius of gyration of kG=0.3 m.
มุมมอง 2.4K7 หลายเดือนก่อน
Question: The pool has a mass of 100 kg and a radius of gyration of kG= 0.3 m. If the coefficients of static and kinetic friction at A are us = 0.2 and uk = 0.15, respectively, determine the angular acceleration of the pool if P= 50N Problem 17-96 from: Engineering Mechanics: Dynamics, 14th edition Russell C. Hibbeler Thank you guys for watching. If you would like to donate use the link below t...
Dynamics 17-76| The 20-kg roll of paper has a radius of gyration = 120 mm about an axis passing ...
มุมมอง 1.7K10 หลายเดือนก่อน
Question: The 20-kg roll of paper has a radius of gyration = 120 mm about an axis passing through point A. It is pin supported at both ends by two brackets AB. The roll rests on the floor, for which the coefficient of kinetic friction is Me=0.2. If a horizontal force F= 60 N is applied to the end of the paper, determine the initial angular acceleration of the roll as the paper unrolls. Problem ...
Dynamics 17-69| The 20-kg roll of paper has a radius of gyration kA = 90 mm about an axis...
มุมมอง 1.6K10 หลายเดือนก่อน
Question: The 20-kg roll of paper has a radius of gyration kA = 90 mm about an axis passing through point A. It is pin supported at both ends by two brackets AB. If the roll rests against a wall for which the coefficient of kinetic friction is muk = 0.2 and a vertical force F = 30 N is applied to the end of the paper, determine the angular acceleration of the roll as the paper unrolls. Problem ...
Dynamics 17-61| If a horizontal force of P= 100 N is applied to the 300-kg reel of cable ...
มุมมอง 1.4K11 หลายเดือนก่อน
Question: If a horizontal force of P= 100 N is applied to the 300-kg reel of cable, determine its initial angular acceleration. The reel rests on rollers at A and B and has a radius of gyration of ko = 0.6 m. Problem 17-61 from: Engineering Mechanics: Dynamics, 14th edition Russell C. Hibbeler Thank you guys for watching. If you would like to donate use the link below to my Patreon: patreon.com...
Dynamics 17-45| The drop gate at the end of the trailer has a mass of 1.25 Kg and mass center at G.
มุมมอง 92011 หลายเดือนก่อน
Question: The drop gate at the end of the trailer has a mass of 1.25 Kg and mass center at G. If it is supported by the cable AB and Hinge at C, determine the tension in the cable when the truck begins to accelerate at 5 m/s^2. Also, what are the horizontal and vertical components of reaction at the hinge C? Problem 17-45 from: Engineering Mechanics: Dynamics, 14th edition Russell C. Hibbeler T...
Dynamics 17-35| The desk has a weight of 75 lb and a center of gravity at G.
มุมมอง 1.3K11 หลายเดือนก่อน
Question: The desk has a weight of 75 lb and a center of gravity at G. Determine its initial acceleration if a man pushes on it with a force F = 60 lb. The coefficient of kinetic friction at A and B is mu k = 0.2. Problem 17-35 from: Engineering Mechanics: Dynamics, 14th edition Russell C. Hibbeler Thank you guys for watching. If you would like to donate use the link below to my Patreon: patreo...
Dynamics 17-24| The door has a weight of 200lb and a center of gravity at G. Determine how far...
มุมมอง 3.5Kปีที่แล้ว
Question: The door has a weight of 200lb and a center of gravity at G. Determine how far the door moves in 2 s, starting from rest, if a man pushes on it at C with a horizontal force F = 30lb. Also, find the vertical reactions at the rollers A and B. Problem 17-24 from: Engineering Mechanics: Dynamics, 14th edition Russell C. Hibbeler Thank you guys for watching. If you would like to donate use...
Dynamics 17-21| The pendulum consists of the 3-kg slender rod and the 5-kg thin plate.
มุมมอง 6Kปีที่แล้ว
Dynamics 17-21| The pendulum consists of the 3-kg slender rod and the 5-kg thin plate.
Dynamics 17-15| Determine the moment of inertia about an axis
มุมมอง 4.7Kปีที่แล้ว
Dynamics 17-15| Determine the moment of inertia about an axis
Dynamics 17-11| The assembly is made of the slender rods
มุมมอง 3.8Kปีที่แล้ว
Dynamics 17-11| The assembly is made of the slender rods
Dynamics 17-1| Determine the moment of inertia Iy for the slender rod.
มุมมอง 3.6Kปีที่แล้ว
Dynamics 17-1| Determine the moment of inertia Iy for the slender rod.
Dynamics 16-145| A ride in an amusement park consists of a rotating arm AB having a constant...
มุมมอง 3.7K2 ปีที่แล้ว
Dynamics 16-145| A ride in an amusement park consists of a rotating arm AB having a constant...
Dynamics 16-134| Block A which is attached to a cord moves along the slot of a horizontal forked rod
มุมมอง 2.3K2 ปีที่แล้ว
Dynamics 16-134| Block A which is attached to a cord moves along the slot of a horizontal forked rod
Dynamics 16-124| The disk rolls without slipping such that it has an angular acceleration of ...
มุมมอง 10K2 ปีที่แล้ว
Dynamics 16-124| The disk rolls without slipping such that it has an angular acceleration of ...
Dynamics 15-75| The 0.5-kg ball is fired from the tube at A with a velocity of v = 6 m/s.
มุมมอง 3K2 ปีที่แล้ว
Dynamics 15-75| The 0.5-kg ball is fired from the tube at A with a velocity of v = 6 m/s.
Dynamics 15-25| The balloon has a total mass of 400 kg including the passengers and ballast.
มุมมอง 2.9K2 ปีที่แล้ว
Dynamics 15-25| The balloon has a total mass of 400 kg including the passengers and ballast.
Dynamics 16-116| The disk has an angular acceleration α = 8 rad/s² and angular velocity ω = 3 rad/s
มุมมอง 11K2 ปีที่แล้ว
Dynamics 16-116| The disk has an angular acceleration α = 8 rad/s² and angular velocity ω = 3 rad/s
Dynamics 16-104| At a given instant the bottom A of the ladder has an acceleration of a = 4 ft/s²
มุมมอง 6K2 ปีที่แล้ว
Dynamics 16-104| At a given instant the bottom A of the ladder has an acceleration of a = 4 ft/s²
Dynamics 16-77| The planetary gear system is used in an automatic transmission for an automobile.
มุมมอง 6K2 ปีที่แล้ว
Dynamics 16-77| The planetary gear system is used in an automatic transmission for an automobile.
Dynamics 16-76| If link CD is rotating at wCD = 5 rad/s, determine the angular velocity of link AB
มุมมอง 16K2 ปีที่แล้ว
Dynamics 16-76| If link CD is rotating at wCD = 5 rad/s, determine the angular velocity of link AB
Dynamics 15-115| The chute is used to divert the flow of water, Q = 0.6 m3/s.
มุมมอง 1.7K2 ปีที่แล้ว
Dynamics 15-115| The chute is used to divert the flow of water, Q = 0.6 m3/s.
Dynamics 16-64| The pinion gear A rolls on the fixed gear rack B with an angular velocity
มุมมอง 8K2 ปีที่แล้ว
Dynamics 16-64| The pinion gear A rolls on the fixed gear rack B with an angular velocity
When I solved for the moment of inertia about the y axis, i didnt do (200-y) because i thought that wouldve been the area _under_ the parabolic shape. am i wrong for doing this or is it valid? my answer was 80(10^6) mm^4.
You are the reason I understand this, my exam is tomorrow
thank you daddy
For my major, I was told to take a trig based physics class, which meant I was done with Calculus at Cal 1. So I never learned much about Integrals. Can you do some of the problems using the Trig-based approach?
Question will evaluating the point at point be different? I got F-EF =12
I honestly really look forward to these videos. The only TH-camr that explains it so well, so thank you
Ur explanations are spot-on, crisp clean, and right to the point.
how the f can you assume B is in the midpoint if there is nothing mentioned in the problem?
great job tmr is finally and i can say that u really helped me thanks bro
It is almost a mistake on his part in the calculations because he is supposed to add the moment approximately to both sides. This means that the sum of the moments about o for the resultant = 51x + 500, and the moment of the two forces before unification = 500 + 5.5 * 36 + 12 * 15 = 878 ....... And now. When we equal the two equations, 500 will subtract 500. When it goes against the sign, then 378 will be added. Dividing the result by 51 will end up being 7.411.
This was a big help, thanks!
Hi i would like to ask u another question can i?
I can actually pass my class now, thank you.
muchas gracias
Thank you my friend
How did you come up with integral y^2 * dA ?
this was very helpful, thank you
i love that you explain everything, even if it might be obvious. thanks to you, i finally know where to cut regarding method of sections. you're the best!
Why are you neglecting to include the vertical component forces at C and D in the free body diagrams? Why are you zeroing the component forces at these points. Despite it not asking for them they still exist and can't exactly be ignored.
Thanks, man. You're my saviour
i think for AC moment it should be (2.25)(0.5)?? pls tell me if i`m wrong😬
Thank you. The teaching was very concise and helpful.
Shouldnt r dot = 0.4*theta*theta dot not just 0.4*theta dot?
hi, do you have a lecture video regarding to this topic??
Can i assume they are symmetrical?? I hope i can get a reply What should i do if I were task to find every truss using the method of.Section in This problem for example?. Is it safe to assume the value i get for CE Is equal to BF???
a_A,t=0 due to no slip, a_A,n = w^2*r j =a_a. a_c = a_A + alpha x r_C/A + w x (w x r_C/A). Thus a_c = -10.01i -0.3656j. Not sure about a_b but the approach appears to be incorrect when applying to a_c
Why r we ignoring reaction forces
Damn bro, you explain so well. Thanks a lot 🙌
Sir, which book is this ?
wouldn't the moment about B also be an unknown? Why isn't it considered an unknown?
it's a smooth pin, it doesn't have a moment reaction force as by definition it is free to rotate.
Bro, I really miss you. If you still here in this channel, leave a comment here Love your videos and appreciate your enthusiasm
Hi from 4 years later❤ hope you have a nice and wonderful day, man🎉❤❤ Thanks for your help❤
shouldn't f and p have opposite sign because they are opposite direction
I wanaa your username instagram plz to communicate with you 🙏
How could the distance be 17.9 m if the maximum distance it could be is 7.5 m + 4.5 m = 12 m. it being 17.9 m from O would mean that it is not located on the beam.
It is almost a mistake on his part in the calculations because he is supposed to add the moment approximately to both sides. This means that the sum of the moments about o for the resultant = 51x + 500, and the moment of the two forces before unification = 500 + 5.5 * 36 + 12 * 15 = 878 ....... And now. When we equal the two equations, 500 will subtract 500. When it goes against the sign, then 378 will be added. Dividing the result by 51 will end up being 7.411.
Moment about point H is easier.
Thank you buddy. It is really helpful
❤❤❤
This is very important vidio. your channel be blessed my Lecturer.
I need a man like him during my engineering exams🥺🩷
why is rp = ra? Why can we neglect the other support for the first part?
muchas gracias saludos desde peru
Saludos amigo!
Just wanna ask how did you get 39.96 using scical? I hope you’ll reply ASAP huhunesss
Hi, in the video around 5:50 I show how I used the calculator to get that number. Hope that helps.
thank you for making this simple
Thank you very much. I was able to understand thanks to you. ❤ I watched you from Turkey. Greetings.
Awesome video helped with my homework.
Thnxxx
is dy for lower"1" shape similar to upper"1" shape sir
Great video man
Hii, from Philippines, why in respect to y-axis, you did not subtract the y from 1 to get the dA of the formula?
Hello, because when we were doing 10-5 with respect to the x-axis the area was on the right side of the curve, if the area was on the left side of the curve it would be just "x*dy" for the dA. In 10-6 when we are doing with respect to y-axis you can visualize it as under the curve area, so dA = y*dx only. IF the area was above the curve then it would be dA = (1-y)dx... I hope that helps. The key is to see the height of the "square"/section we are integrating. Is the height of that square equal to the height of the curve? or what else?