วีดีโอ

Too Op

dayuum so good..

You mixed up the positive and negative charges. I noticed an error in the explanation regarding how the laser interacts with the OPC drum in a laser printer. The video states that the laser "applies a negative charge on areas to be printed," but this is incorrect. In reality, the process works as follows: The OPC drum is initially charged with a high negative charge by a primary corona wire or charge roller. The laser selectively scans the drum surface and reduces the negative charge in the areas where it hits, effectively neutralizing those areas. Negatively charged toner particles are then applied to the drum and adhere to the less negatively charged or neutral areas where the laser has hit, forming the latent image. The paper is given a positive charge, attracting the negatively charged toner from the drum to the paper. The toner is then fused to the paper with heat and pressure to create the final print. The laser does not add a negative charge; it reduces the existing negative charge to create the latent image. Hope this helps clarify the process!

bs aapki jarurat h

Thank u so much sir it helped us a lot..

Amazing 😂

But how is tan theta positive? Isnt it -V1/V2?

Amazing explanation, sir. Thanks a lot!

I wish I could like this more than once

Now if someone's gonna teach like this then physics could be fun in real 🙏

wonderful explanation and solution

Nice 🎉🎉🎉

Rey evarra meerantha!!!

Thank you so much for saving my project

It's amazing

sir how you took acceleration =0?

Loved the way you have explained ❤️❤️

Thanks sir , target jee adv 2024

But Sir please help me in finding the force which is responsible for moving it away from centre from the ground frame. Because I can't find any force due to which it is shifting it sideways as N2 is only causing rotation

Interesting

Too good explanation ❤

really great animation video I clearly understand it. Thanks a lot :)

Sir why you stop uploading

Superb

Sir your Videos are awesome Please continue teaching on TH-cam..... Your videos are more useful for students...

How to solve this in ground frame

Great effort. Even the color of KMnO4 solution (purple) is correct :)

Better than other videos I understood very well from this video thanks!

Wrong answer

Sir nice explanation by visualisation thank u

Thank you sir🫡

sup, im from Brazil, you r so good, keep on

Isnt the length L/2.. as the Torque is about the centre

Good work.... very helpful... Upload more concepts....

At 14:53 why is the scale in translational equilibrium in the horizontal direction as you wrote fk1=fs2

Exist New force problem ( Cavendish not told about in his work ) Study my GREEN force idea that you for like and share th-cam.com/video/CdZv6nMqE-w/w-d-xo.htmlsi=x148CZ16Ev1D3Lbh

Thank you

Sir Please continue this type formulae vedios for remaining chapters jee...

Gazab 🔥🔥🔥

thank u sir i was ur student in 9th online

Sir I am having doubt in question that on which physical quantities will the time taken to leave the ceiling of the left by the bolt is depends on as well as what will be the effects of pseudo force on the bolt?

Thankyou sir

Sir we can also do this in single step.... Let's see the concept....take the radius to be R and length of the thread be L...also lamda be the mass/length (linear mass density) The acceleration DEVELOPS due to the driving force downwards.......which is G....as just after the cut....the tension at both the free ends will be zero....and their effective vertical length will only be responsible for DRIVING THE THREAD...... THEREFORE WE CAN WRITE DRIVING FORCE=(LAMBDA)(H)(G)..... Therefore ACCELERATION will be...F/M (H)(G)/L....(h is the hanging length....).. Now using this result we can directly write a=(1.5-πR/2+ R)/1.5 Which gives the same answer.... Therefore we wrote the answer directly....

amazing video, thants alot sir , sir we want more such lectures pleeeeeeeeeeeeeeasssssssssssseee sir

100 cm kese aayaa hai explain kar do sir ji please 🙏

Underrated channel

Thank you sir! One doubt tho Then does that mean any metal(even non magnetic) would move along with magnets when it's rotated like in question!?

thanks sir

Please start again this series