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Aap Puri video dekhiye

@basicsofmaths8740 sorry ma'am maine pura video nhi dekha tha 🙏

It works for finite number

ab+bc+ac=a²+b²+c² when a=b=c

Yes

Thanks

7^(2^n-1)/2^n

@@basicsofmaths8740 this is applicable to any no?

@@basicsofmaths8740 n stand for what

@@btechwaalahn= no of times number appear in the expression like 7 in this expression

Topic????

Sirf yehi video hai

@@basicsofmaths8740 formula kese apply hote hain ya fir kyu hote hain iske upar video milega to thik rehte basic ki video main

Aap isi formule ki baat kar rahe ho ya maths ke general formulae ki

@@basicsofmaths8740 nhi baki formula v chahiye tha.sab formula leke ek ya do video de sakte hain. Mujhe formula ko leke confusion hain ki kese apply hote hain

@@funuploader9247 maths mein bahut sare topics hote hain aur bahut sare topics ke bahut sare formule honge yah kisi bhi mathematician ke liye possible nahin hoga Aapka question tha formula apply kyon hote Hain Ans: formula apply karke ham kisi bhi problem ko kuchh minutes mein hi solve kar sakte hain example :;area of polygons Agar aap area find karne ke liye formula use nahin karoge to aap kaise find karoge

Thanks

Thanks

How? Could you explain

Competitions mein formula use karna hota hain aapke pass itna time nahin hota ki aap pura solve karo . Competitions mein aapko sirf 30 ya 40 seconds milte Hain ek question ko karne ke liye isiliye yah shortcuts and tricks use kiye jaate Hain but sorry agar aapka time Waste hua Ho

X²+1/x² is different from x⁵+1/x⁵

Thanks

radicals are taught in 7th class

I used binomial theorem

6/25

Use (a+b)², (a+b)³....and transpose some terms to get these formulae

It's better not to commit these formulae into memory. Problems such as these can easily be solved as follows: x+1/x=5 -- (i) Squaring both sides, we get: x²+2.x.(1/x)+1/x²=5² [using (a+b)²=a²+2ab+b²] i.e., x²+2+1/x²=25 or x²+1/x²=25-2=23 -- (ii) Now, multiplyng (i) by (ii), we get: (x+1/x)(x²+1/x²)=5*23=115 i.e., x³+1/x+x+1/x³=115 But x+1/x=5, and so we get: x³+1/x³=115-5=110 -- (iii) You can continue in the same fashion to get x⁴+1/x⁴ or you can use (iii). Squaring both sides of (iii), we get: x⁴+1/x⁴+2.x⁴.1/⁴=23²=529 i.e., x⁴+1/x⁴+2=529 => x⁴+1/x⁴=529-2=527 -- (iv) Multiplying (i) by (iv) -- or -- multiplying both sides of (ii) and (iii), we can find the value of x⁵+1/x⁵. Let's use (ii) and (iii). we get: (x²+1/x²)(x³+1/x³)=23*110 i.e., x⁵+1/x+x+1/x⁵=2530 But x+1/x=5. Thus, x⁵+1/x⁵=2530-5=2525 and so on

I can

√70.71.72.73+1 √(71-1)(71+1)(72-1)(72+1)+1 √(71²-1)(72²-1)+1 √71².72²-71²-72²+1+1 ....... Now use a²+b²=(a-b)²+2ab

Should I make a video on its proof?