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Thank you so much sir ❤

thanks for help us❤

Please make more and more videos on mechanical engineering. Love from DUET, Gazipur, Bangladesh

Tommorow is my exam

Dou changed to d how?...

Super explanation sir

Nice 👍

very good explanation

thank you so much sir

thankyou sir

Thanku so much sir I understand everything about torsion..😊

Nice explanation sir❤

The composite bar consisting of steel and aluminum components, as shown in Figure 2, is connected to two grips at a temperature of 60°C. Find the stresses in the two rods when the temperature falls to 20°C. If the ends do not yield, the area of steel and aluminum bars are 250 mm2 and 375 mm2, respectively. Take E steel is equal to 2 into 10 raised to power 5 N per mm2 and E aluminum is equal to 0.7 into 10 raised to power 5 N per mm2. Alpha steel is equal to 1.17 into 10 raised to power minus 5 per degree Celsius and alpha aluminum is equal to 2.34 into 10 raised to power minus 5 per degree Celsius.

Thank you sir, this will help me a lot in my upcoming exam.

❤

Thank you sir 💯

Great Explanation

very nice explaination ... thank you sir <3

English sir!!!!!!! I can't hear you clearly

Sir kya app 2024 k liye upload kar sakte ho? Ya yehi padhe toh bhi chalega.

Thank you

A simply supported beam of 9m span, the vertical load increases linearly at a value of 10kn/m at the left end of the beam to a value of 30kn/m at the right end. (a) Draw the SF and BM diagrams, (b) calculate the maximum bending moment and locate where it lies. I have been watching your videos and they are helping a lot. please help me do that number

Oh my, victory at last... thank you so much for this sir🌝🌝

thank you ❤

how he is measure the length from q to r in velocity diagram

It would have been superb had it been it was translated into English for those who don't understand your language

200 -10 ? Why ?????? (200/2) -(10/2) =100-5 = 95

My professor recommended your videos by providing your video links🎉

Thank you sir so much.

View what is the method to describe eqution

Please go through derivation on velocity of sound at NASA website, that depicts the true physics Even though answer is matching, doesn't mean it can be reached in a wrong way

❤❤❤❤ Thanks

Is n't cos theta=Base/hypotenuse?????plzz reply fast buddy 8:36

Is t cos theta=Base/hypotenuse?????plzz reply fast buddy 8:36

Thanks you sir 🙏

Thank you sir 🙂

A night Before Exam ❤

Thank you very much!

Very simple and amazing lecture ❤

Sir explained very well even through parallelogram law of vectors .

5:07, 0.706×2.5=1.765

Smith Brian Anderson Angela Johnson Jason

Thank you a lot 👍

Thank you ❤

One hour before exam 😂😢😢😂😅❤

Sir your explanation is very nice.. But please show a full pic of derivation at end.. As we could directly refer it 😃

Great!!

can we choose dynamic viscosity instead of denity

Thank you sir you're first person i understand

Thank you 🙏