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Engr. Clidez
Philippines
เข้าร่วมเมื่อ 2 ก.พ. 2013
This is a channel dedicated to sharing my knowledge with students :) I livestream free tutorials once to twice a week. You may send me problems that you can't access on Chegg, Bartleby, or other platforms via the comments or my contact details, and I will make a video solution so that you can access answers for free.
Miscellaneous content includes Geometry Dash and Pokemon Unite videos :D
Miscellaneous content includes Geometry Dash and Pokemon Unite videos :D
Compound Curves - Sample Problems
@GillesaniaEngineeringVideos @cebox @EngrHLDC @SolUsmanJr @KippapEducation @engrjayc
The common tangent AB of a compound curve is 76.42m with an azimuth of 268º30', the vertex V being inaccessible. The azimuth of the tangents AV and VB was measured to be 247º50'; and 282º50' respectively. The stationing at A is 10+010.46 and the degree of the first curve is 4º based on the 20m chord. Use chord basis.
1. Compute the stationing of PCC
2. Compute the radius of the second curve
3. Compute the stationing of PT
4. What is the length of the common chord?
The common tangent AB of a compound curve is 76.42m with an azimuth of 268º30', the vertex V being inaccessible. The azimuth of the tangents AV and VB was measured to be 247º50'; and 282º50' respectively. The stationing at A is 10+010.46 and the degree of the first curve is 4º based on the 20m chord. Use chord basis.
1. Compute the stationing of PCC
2. Compute the radius of the second curve
3. Compute the stationing of PT
4. What is the length of the common chord?
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@structurefree @engrjayc @KippapEducation @GillesaniaEngineeringVideos This video discusses the major moment distribution method cases. Calculate the support reactions of the beam shown using the Modified Method and the Adjusted F.E.M. if the support at A sinks by 7mm and the support at B sinks by 12mm. E=12GPa and I=125x10^7mm^4
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A vertical force P=10kN is applied at the ends of cord AB of length 2m and spring AC. The spring...
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Join this channel to get access to perks: th-cam.com/channels/kMGyIHKTKI_K7Fzdcvm87Q.htmljoin This channel is an avenue to share my knowledge on various subjects such as mathematics, literature, and research, but I mainly focus on Civil Engineering Subjects. To send problem requests, follow our (FB Page): profile.php?id=61553684431570 Not all problems will be accommodated, but item...
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Join this channel to get access to perks: th-cam.com/channels/kMGyIHKTKI_K7Fzdcvm87Q.htmljoin This channel is an avenue to share my knowledge on various subjects such as mathematics, literature, and research, but I mainly focus on Civil Engineering Subjects. To send problem requests, follow our (FB Page): profile.php?id=61553684431570 Not all problems will be accommodated, but item...
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Napaka walang kwentang video
Which part did you not understand? The last part is the quickest approach to a quiz bowl question
Sheeesh bat parang ang conyo niyo po pakinggan
Pero galing pa din 😭
Noong full length english videos pa ginagawa ko sa statics nadadala accent eh hahah.. sa recent videos Filipino audience na talaga kinacater.. nakakaadjust na 😅
anong type po ng compound 'yan sir?
neer how do u solve this problem? my prof used this but didnt give an angle of intersection but instead degree of curvature which is 5 and that pc is 2+540.26
Using the degree of curvature, you can obtain the radius of the curve and start from there
ano po reference book niyo?
Pytel
Keep going ❤❤❤❤
Bakit po hindi na minultiply ang stifness ng span sa outermost hinge ng 3/4?
@@mjbautista1801 hindi po kasi modified method yan
Good day po sir, paano po kapag fixed po both supports? Isasama po ba yung moment sa cutted portion? Diba po malalaman pag tama yung equation kapag ni-substitute yung value ng length ng span sa x sa moment equation ay magiging zero? Applicable po ba yun kapag both fixed? Thank you po.
Pag fixed both po yung value kapag nisubstitute yung x would be same sa reaction sa right fixed support but opposite sign hehe
New subs here sir, may I ask what if the given force at the joint is inclined, then the it is necessariy follows 1 kN unit is projected inclined sir? Thank you.
for vertical or horizontal movement, the unit load of 1kN always acts to the left/right or upward/downward only... the inclined force at the joint will only affect the REAL system, not the VIRTUAL system
@engrclidez thank you sir
hello sir, maapply ba sa tanan ang equation of moment for deviation? ang akoang deviation man gd gamit ang equation of moment by parts ka lahi compare sainyoha. Scical akong gigamit tong integral. Salamat daan sa tubag
2160 ang akoang Ta/b po
@@hamzamaruhom7644 dapat same ra sa integral japun.. try to double check the moment equation and the degree
@@engrclidez bali ing ani ang porma saakong equation gamit ang integral para sa ta/b = integral from 0 to 6 (135x-50x^2/2)(6-x) ang mugawas saakong scical kay 2160 po. Unsaun diay pagplastar sa equation po. Sa previous man nimo nga deviation, makuha man naku gamit saakong pag plastar ana pero kana kay lahi ang mugawas? huhu
@@engrclidez murag ang 2160 na answer po sir kay for t b/a siya kay gitan-aw nako ang imong sunod nga video, 2160 ang t b/a nimo. Naglibog nuun ko sir kong unsaon pagporma sa equation ;(
Yes sa tb/a na sya imomg equation gicompute
Holyyy Mas na intindihan kita kayaa Sa Professor ko No shocks Thanks Man
I failed to clarify it here but there are actually two possible values for the unknown angle. There is an obtuse angle value and an acute angle value. However, in the reference I used, the choices could only be obtained by using the obtuse angle. I found another reference, though, that used the acute angle.
pwede po ba kayo gumawa ng triangle sa beam na VWM method hehe ty
Thanks for the suggestion.. baka po soon magagawan ko
Detalyadong detalyado po sir. Maraming Salamat po Engineer!
sobrang angass🥹🥹🥹🥹
maraming salamat sir! napakalinaw!!!
sir if active paka, mag ask unta ko ba. what if missing ang mga P tas ang mga reaction. butang nako inani na problem: In the overhang beam shown, determine the load "P" so that the shear in each support and at the midspan is equal to zero. nya ang given kay P1 = 1m to left roller, roller to hinge = 6m, P2 = 1m to right hinge, dayon ang UDL is equal to = 20Kn/m
form ka three equations since duna kay three unknowns.. two vertical reactions sa support then ang value sa load P.. first equation moment ka sa any support.. second equation kay based on shear at the supports.. then third equation irelate sya sa shear at the midspan
@engrclidez nakuha nako ang P when gi equal nako ang shear A to 0 pero negative si letter P, okay rni? like -P = 20 sya
@engrclidez patudlo ko sir unsa nga equation gamiton, taod taod nako ani nga pangutana pero wkoy makita sa yt hahahahaa
@@sumiya3218 mao na sya ang exact question? Message lang nko sa fb hehe..
@@sumiya3218 pasend pd ko sa figure
Nag momodified lang po ba ng Stiffness when pin/roller nasa both ends
@@JuswaCadiz yepp
Good day po sir, paano po gagawin kapag may uniformly distributed load tapos may point load din po sa overhang part? Same lang po ba sa ginawa sa 20kN? Thank you po.
@@TAGSIMRHEAMAED kukunin pa rin po yung moment ng dalawang loads then total load to transfer at B would be the concentrated load + the resultant load of the uniform load
@@engrclidez thank you so much po!
Hello po, di ko gets yung mag input ng 3 sa calculator for finding the location of the maximum deflection. like dapat ba talaga 3? or pwede ibang values? pero if ibang values iinput ko iiba kasi yung result. Correct me if I'm wrong pero is it 3 because half siya sa distance ng beam AB? which is doon pinakamalapit yung possible value ng x na zero shear siya? Thank you!
@@RHODECHRISTIANBACUD yep tama.. 3 since usually half ng span safest guess nyo po.. magbabago yung guess value depending on the dimensions lang po
@@engrclidez Hala thank you po for clarifying and answering my question! Timing nasagutan nyo agad before sa exam ko bukas hehe
bisaya
Mas maka gets ko ani
pano ma-determine if concave upward or downward ang moment sa spandrel sa MDBP?
@@1295key height of the spandrel is always at the moment center.. depende na po yan sa rotation na macaucause ng load about the moment center yung concavity nya.. upward rotation generally means upward concavity, downward otherwise
What is the name of the textbook?
@@doqe_study I'll try to look for it later.. you may message our fb page
Sir morning thank uu poo ...dahil sa ved NYU na absorb ko Ang reason kung bakit ganto ganyan nag influence diagram if kung saan² I position Ang unit load🥹
glad to help po!
Correction po sa formula sa fixed end moment with applied moment: the right end moment must be Ma/L^2(2b-a)... not (b-2a)
sorry mga kapitbhay 😅
Salamat bisdak neer
thanks for the video really useful
engineer, can i request po a video about this method for non prismatic beams? im still mastering this method po for all types of beams eh for quiz bee po. thank you, sir
hello po, this method is generally not advised for nonprismatic beams.. fastest way para sakin for non prismatic is the Virtual work method po.. but baka pwede ko po gawan yan
meron po kayo tagalog discussion nito po? huuhu
Plano kong gawan this week po..
حمار
pwede po gawa kayo tagalog discussion sir.Thank youu
@@arrowlandstonedelfino-guia6816 yepp, every after ng semester po ginagawan ko po yung videos ko
Life Savior ka LODS ❤❤❤
Wag nyo na lang pansinin pangalan ng account sa kapatid ko kasi toh HAHAHA
Glad to help lodi
Soo incredible demonstration of concept and principle
saan po nanggaling yung pi/180
@@CristineJenibelleLoyola conversion from degree to radians.. 2pi/360 (whole revolution) simplifies into pi/180
Sobrang tamag mo magsalita putangina ka
nagalit si box roblox HAHAHAHA. huwag ka na mag aral, mag roblox ka nalang bonjing
Anong book reference po ninyo dito? Thank you for your videos po it help us a lot po.
Hibbeler po hehe
Pwede po malaman kung anong specific book and edition po engr? 🙏 thank you in advance po.
@@syfroc5744 13th edition
goodevening sir, gemuya diay ni sir, mag meet ta ugma sir?
yepp magmeet
pag double overhang beam po ba magiging fixed yung dalwang free end at dalawa na yung internal hinge sa pag convert sa conjugate beam?
@@rickyjamoner1057 tama :D
@@engrclidez thank you po engr!
thank you hehe, galing nyo po sir
Pwede mag request sir, steel naman po. Salamat po!
@@Jaira1109 hello, anong topics poo?
@engrclidez tensile strength po tsaka slenderness ratio. Salamat po
Solid sir. Alternate shortcut solution.
Wala bang slow motion sa discussion parang Ang bilis
@@RegieMaloloy-on playback speed + pause button.. tagal na kasi ng video na yan.. nung bago palang ako.. ineedit out ko lahat ng dead air tas gumagamit ako ng silence detection.. reinforcement lang kasi yan para sa students ko (since nadiscuss na sa class beforehand).. pasensya po
what is the name of the application?
Deflection Lite available on app store
what app is this
@@shyuk-x3m Deflection Lite
tanong lang lods, paano mo to nagamit sa pc?
@@Pecksman01 via emulator po.. LD Player or pwede rin Bluestacks
anong book ref nyo po dyan sa problem na yan?
@@concepcionaarond.7979 hello, quiz bowl elimination round item po yan
The top left slab is actually a two-way slab with triangular and trapezoidal loadings.. whereas panel CDGH is a two way slab consisting of 4 triangles
Some of the slabs here are actuallt two-way slabs but were analyzed accordingly since most items sa CC2 subject assume one-way slab.. If you want to learn more about tributary areas, there is a chapter within this discussion covering one-way and two-way slabs th-cam.com/video/g_MRV5XEHQ4/w-d-xo.htmlsi=0-vGFqB8wuv_Q4Eo