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This is a great video! Really intuitive way to understand the method of images :)

Why don't you upload more?

thank you for this chsnnel

Your are spectacular in solving physics problems.You Majestic and Marvellous

This has more detailed explanation. th-cam.com/video/BBlZNcUt4Jk/w-d-xo.html

AMAZING!

what do you mean by the fact that the path is a decreasing potential path?? why can’t it extend to infinity is what im not understanding

This is very helpful, thank you! Couldn't find a shoutout to three blue one brown on your channel tho 🤔. I'm confused 🤓

wtching i 2024

This problem had been eating away at me for a long time. I was so happy to finally see a concise well explained. Great work!

This completes very nicely Purcell's mathematical approach to this problem. Yes, by the uniqueness theorem bla bla bla..., now I have a neat physical argument which is more intuitive!

In prob 10 can you please explain why arctanu≥alpha

Very nice video

u should give a comeback these days science and math related small started to due to rate of increase in audience related to this type of contents. u can get supports from viewers through patrion and merch whatever be it ,just give it a try.😊

3.54 ... Why field couldn't end on plate .u said potential is decreasing all along the path ..wht does that mean ..?

ill try the second and third, even though its after 3 years and the solutions probably exist 2. i initially thought the see saw would stay even but after reading one of your replies, and considering tension, it will tip right 3. if you look at the string connecting the balls, the mass of the string is 0 so the net force on the string is 0 by F=ma. the forces acting on the string are the same forces acting on each ping pong ball. since the net force on the string is 0, the net force on each ball is also 0 and it stays in equilibrium

What if instead of a light pulse telling the ships to accelerate, they had a synchronised clock onboard that told them when to accelerate?

Plz bring more on hydrostatic

For number 3, if the machine were to spin, the ping pong balls on the right would go up and the ones on the left would go down. However, all the balls are pulling upwards, so that will not work. Only if the ping pong balls were swapped with rocks on the left would the machine work, and that one would only work for a small amount of time

Excellent video!!

magnificent video!

hau to be saxi laik u saar

This is a *really* good video

The light pulse hits both spaceships at the same time if it starts from the center of the rope. Remember, the spaceships aren't moving if there's nothing to move relative to!

From where can I find the pdf of 2022B??

nicee i was able to solve the first ques by torque analysis about the Centre of the circle of radius r but the second problem i did one tiny mistake

Never ever stop making mechanincs problems vids man they are so damn good and mechanics is ofcourse one THE best things in physics

I actually watched this video before meeting you at ipho 2023, without knowing that you created it. Amazing video!

Thx for sharing. Dang does this mean I'll have to refund all my investors money on my perpetual ping-pong ball FREE energy generator. Hey, don't tell my investors at least until I amass enough money to buy a new life somewhere else and leave town. Hahaha. As W.C.Fields said in one of his movies, yes indeed there's a sucker born everyday yes indeed yes indeed. LOL. Again thx for sharing.

Bro you should make a series on jee advance questions. Your channel is very underrated

It's gold for jee aspirants

Place a container partly filled with water on a kitchen scale and push down an object in the water (as on the left of the scale) or hold a sinking object half-way in the water (as on the right of the scale). You'll see that the mass shown by the scale increases. And that increase is exactly equal to the mass of the water displaced by the immersed object (a 100 ml object will add about 100 grams on the scale). In your problem 2 there are two forces acting on either side of the scale: the weight (gravitational force) of the water and the buoyancy force. And both forces are equal on either side of the scale: there is the same amount of water on either side, and the buoyancy forces are equal because the two balls have the same volume. Conclusion: the scale does not tip on either side. You can easily to the experiment at home with a kitchen scale.

In problem 11 I can't imagine how the equilibrium go out so for improving it for me I must solve it by Newtown and torques equations, So can you solve it by these equations ?

Nice

smh, i can't believe these small angle approximations. For the second one, you should be able to do dy/ds = lambda*g*s/sqrt((lambda*g*s)^2+(T_x)^2) which is easily integrable via u-sub and then you still get a quadratic in l, right?

help me bro

Nice

Hi, for problem 3 I’m a bit unclear. Why is there a vertical component of the velocity of the intersection? And why is the overall velocity tangent to the circle? Also what do you mean by frame moving v/2 right?

Its wrong then its conected ...

Anyone trying to find "infinite" energy needs a better understanding of how reality works lol... according to Newton.. no energy is every "created" or "lost"... it was all created during the big bang.. energy is never lost it only converts from one form to another.. the onlything "infinite" is the universe itself (sorta).

Dear Kind Sir, I hope this message finds you at a good time. My AP Physics C work and energy test is coming up in two days, and I am seeking private counseling. Would you please be able to give me some? I can pay you. In addition, can you plz teach me how to animate like this bhai - for my history class, I have to make a 3 - 4:30 minute presentation, and I would love to animate much like you do. Thank you sir

In the second puzzle, the scale deviates to the right. Because the thread is connected to the bottom of the container on the left side, and the tension force of the thread is equal to the difference between the buoyancy force and the weight of the object, and this force enters the container upwards. On the other hand, the reaction of the buoyancy force on the object is added to the water and the whole set downwards. So, the added forces in the set on the right are added to the size of the weight of the light object. On the right side, however, the tension force of the thread does not enter the container because it is not connected to the container. The only force added to the set is the buoyant force that enters the object. Now, since the volume of the two objects is the same, then the buoyancy force vector is the same for both objects, and the weight of the light object on the left side is less than the buoyancy force, so by comparing, we can see that the force added to the container on the right side is more.

In the first puzzle. The reason that despite the different amounts of water in the containers, the force on the bottom of the container from the water is the same is the effect of the force of the walls of the container. In the figure on the left, where the amount of water in the container is more than the others, due to the walls facing outwards, part of the weight of the water is neutralized by the walls, and only part of the water weight, which is the same as the weight of the water in the middle container, is applied to the bottom of the container In the middle container, where the force of the wall has no effect and the weight of the water has entered the bottom of the container, and in the third container, because the walls are facing inward, the vertical reaction force of the wall adds to the weight of the water, and the force on the bottom of the container is greater than the weight of the water and It is equal to the weight of the water in the middle container, in this way, all three apply the same force to the bottom of the container

Sir, plz help me with JEE😭

I don't quite understand how is the angle q constant if the question says it changes effortlessly???

i wish i could slurp watermelon as well as you shlrup shlurp 🍉

daaaaaaang bru this damn baby won't shut up! KAPOW! 👊

dear sir i wish i was your smartness would bleed into me thanks for the help in my algebra class

4:30 IT WORKS!!!!! IT WORKS!!!!!! ...on your animation:D Nice Video!

I saw the same solution to the first problem in my physics teacher's book , kudos still !