วีดีโอ

Nine. 2 seconds. Utter nonsense.

What a terrible solution, quit teaching please.

I literally fucking solved it in my head, 2.56

99% students failed this? Any source? This sounds like clickbait again. I doubt this was the case frankly. Looks like a standard test following a first class on quadratic formula; typically more than half the students would get this. If the teacher was particularly bad, maybe 1/4 of students would get this. Most classes in western europe have 30 students in highschool +/- 10 students; so 99% is unlikely in any case. There is no national level test at age 16 (quadratic formula) so no test would have more than 30-40 students (therefore 1% getting it right is unlikely). Sorry clickbait doesn't do it for me. You could be a lot more helpful by indicating who you target (kids who just had their first class on the quadratic formula), and not be so clickbaity.

{56.+9}=57.0 28^28^1.9 1^2^3^1^2^3^1.3^2 ^1^1^1^1^1^2.3^1 2.3 (a ➖ 3x+2) 3^2/2^2 3^2/2^2 1^1/1^1 3^1/1^2 32(a ➖ 3a+2).

{56 1.9}=570 28^28^1 .9 1^2^3^1^2^3^1.3^2 1^1^1^1^1^2.3^1 2.3 (x ➖ 3x+2).

{56.1+9}= 28^28^1 .9 12^31^2^3^1.3^2;1^1^1^1^1^2.3^1;23 (x ➖ 3x+2).

aª=15 => aª≈2,7131633826

2^3 (m ➖ 3m+2).

On TH-cam there are a lot of videos dealing with this problem. kᵏ = 5, kᵏ = 7, ... Lets give a general solution for kᵏ = a. As you can see, k = e^(W(ln(a))) is at least one solution for any a.

I thought people in France were smarter than this. 99% failed?

1024^2*2-3 1024^2= 1048576*2= 2097152-3= 2097149

@4:50: What's with the fish?

4:27: You don't have to solve for b. b₁ = a₂ and b₂ = a₁, due to commutative properties of addition and multiplication.

a + b = 7 a · b = 7 b = 7 − a a · (7 − a) = 7 7a − a² = 7 a² − 7a + 7 = 0 a₁,₂ = 7/2 ± √(49/4 − 7) = 7/2 ± √(21/4) a₁ = (7 − √21)/2 ∨ a₂ = (7 + √21)/2 b₁ = a₂ = (7 + √21)/2 ∨ b₂ = a₁ = (7 − √21)/2 𝕃 = {((7 − √21)/2; (7 + √21)/2); ((7 + √21)/2, (7 − √21)/2)}

WTF? I was expecting to see values for a and b. Instead some stupid equation thing. So glad i skipped to the end and didnt watch it all! Just give us the 2 values FFS!

m=1/25

Thanks, I didn't know the Lambert function.

How to farm views on the easiest questions

k ----- = 3 √k Multiply both sides with (√k)², so we get (k)(√k) = 3k Divide both sides with k, so we get √k = 3 Therefore, k = 9

If kids fail this, we know datn well the educational system is teall, really bad.

(5^5/2^2)3^2/2^2 (2^3^2^3/1^1)^1^1/1^2 (1^1^1^3/)^/2 (3/)^2 (x ➖ 3x+2). (9/4)^9/4) (3^2/2^2)^3^2/2^2 (1^1/1^1)^3^1/1^2 ()3/2 (x ➖ 3x+2).

a/a^0.5 = 15 (square both sides. a^2/a = 225 a = 225.

Just... use a fucken calculator

2

K≈2.5556046121008206152514542654716688251666245546770082657444779051946940910556792380785350314695368216609159021419007426500725006951318435953778861562027337906283192469224453845755268500788814610028235206033952753464934087866937979751398326480126483126290434732511836785982138364510248624348133791557408872825738535219096791579463928733246834568802148124356569139974705827991829210538743464766764201962396717855559371355533933558003605524502957115817423970198943496751085332037520257785339164677138735549361492125934221613565214865943152954562863325227046024905618930505968699384045624690257870429737676060583769466263501776071716081224015316650729903835716640526076851853233485992551043342015216963363151479146551682662047827961542031399595591989819098830379464400829216248427602708133326826701422860690257258469555180607781844442119388203387331951850708319893670689686928530988000463903148069254464469166743336531863188410381561637206143396797649798333226544831154296745419959658149630539512285872413292224927964499308610121300380735325389468892149589654764097709243905993793128075266294281708459005995957942012099463566368843443466762443951099177525257846072094150091654401086950486195502303928358951641343828121885933560783252619894210564934964831997359780978420016160113078889

K^K=11 K=e^(W(Ln(11))) K=e^(W(Ln(11)+2πin)) n=z It’s in my head.

0:26 k^k=🦆

(2)•(2)•(2)+(2)=10 (1)•(1)•(1)+(2)(2)(a ➖ 2a+2).

a*a*a+a=10 a=2 a=-1±2i

Tbh just calculate 512*512 and then multiply by 8 and subtract 3... Much faster... Your solution is like using a sledge hammer to bang a nail into a wall

Not sure how "99% of Students Failed This Tricky Math Test." The only thing tricky here is the convoluted proofs.

Ah my favourite "pick a tedious but elementary math problem and slap a made up prestigious-sounding competition/entrance exam for clickbait" type video just dropped.

Your English need improvement. slow and easy. assume not that all can follow your "next statement" DVD

Dude a/sqrt(a)=sqrt(a) So sqrt(a)=15 a=225(15*15) I don't belive almost every one failed that was very very easy

You made this way more complicated than necessary. I literally solved this mentally. Also, your second method ends up cross-multiplying just like you started with your first method.

5^6 5^2^3 2^3^1^1 2^3(k ➖ 3k+2).

(3)+(4)=7 (b ➖ 4a+3). (ab ➖ 7ab+1).

Out of curiosity, what is the value of this spesific solution? Basically we used all this time to get that a = f(15). I could have used for Taylor series to get the same answer. Is there some insight to gained from expressing it in terms of Lambert function?

click bait

i just assumed a/sqrt(a) = (sqrt(a)*sqrt(a)/sqrt(a) = 15 and the sqrt(a) cancel out leaving sqrt(a) = 15 then square both sides, so a = 225

i just watched the video to see if my answer is correct or there's some hidden mathematical rule which you'll break, good work, keep uploading my bro. btw, for which standard this Olympiad was framed?

So many unnecessary steps.

a+b=7 ab=7 (a,b)=((7±Sqrt[21])/2,(7±Sqrt[21])/2)=((3.5±0.5Sqrt[21],3.5±0.5Sqrt[21]))

so 99% of French students have brain damage? lol

(K ➖ 3k+3).

2^(2k)+2^(2k) 2(2^2k) 2^(2k+1)=16 2k+1=4 2k=3 k=3/2

all these exercises using the Lambert function are quite irritating because it is a very special fucntion that 99.9 % of the students never heard or will never hear of in their life.

a = sqrt(a) * sqrt(a); sqrt(a) * sqrt(a) / sqrt(a) = 15 => sqrt(a) = 15 => a=225

(sqrt(k))/k = 3 (sqrt(k))/(3k) = 1 sqrt(k) = 3k k = 9k^2, so k = 9*k*k (9*k*k)/k = 1 9k = 1 k = 1/9