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Anoop H A
เข้าร่วมเมื่อ 6 มิ.ย. 2013
วีดีโอ
Module 5 Z Transforms & IZT
มุมมอง 1502 ปีที่แล้ว
#signals #systems #convolutionsum #vtu #eee #18EE54 #z transforms #transforms
Module 2_18EE54_Numerical Problem on Convolution Integral
มุมมอง 472 ปีที่แล้ว
#signals #systems #convolutionsum #vtu #eee #18EE54 #Convolution Integral
Module 2_18EE54_Numerical Problems on Convolution Sum
มุมมอง 432 ปีที่แล้ว
#signals #systems #convolutionsum #vtu #eee #18EE54
Module 2_18EE54_Solution of Differential Equations
มุมมอง 383 ปีที่แล้ว
#signals #systems #differential equations #vtu #eee #18EE54
Module 1 _ 18EE54_Signals and Systems Properties of Systems 2
มุมมอง 413 ปีที่แล้ว
Module 1 _ 18EE54_Signals and Systems Properties of Systems 2
Module 1 _18EE54_Signals and Systems_ Properties of Systems-3
มุมมอง 303 ปีที่แล้ว
#signals #systems #Properties of Systems #vtu #eee
Module 1 18EE54 Properties of Systems
มุมมอง 2053 ปีที่แล้ว
Module 1 18EE54 Properties of Systems #signals #systems #Properties of Systems #vtu #eee
Safety Measures in Domestic Installations Part 1
มุมมอง 993 ปีที่แล้ว
Safety Measures in Domestic Installations Part 1
Safety Measures in Domestic Installations Part 2
มุมมอง 273 ปีที่แล้ว
Safety Measures in Domestic Installations Part 2
Module 2 Transposition of Transmission Line Conductors
มุมมอง 313 ปีที่แล้ว
Module 2 Transposition of Transmission Line Conductors
Module 2 Flux Linkage & Inductance of Composite Conductors
มุมมอง 593 ปีที่แล้ว
Module 2 Flux Linkage & Inductance of Composite Conductors
Numerical Problems on Inductance of a Single Phase Two Wire line
มุมมอง 2363 ปีที่แล้ว
Numerical Problems on Inductance of a Single Phase Two Wire line
Module 2 Inductance of a Single Phase Two Wire Line
มุมมอง 653 ปีที่แล้ว
Module 2 Inductance of a Single Phase Two Wire Line
Module 2 Line Parameters Introduction Inductance due to Internal Flux alone
มุมมอง 233 ปีที่แล้ว
Module 2 Line Parameters Introduction Inductance due to Internal Flux alone
Module 5 AC Distribution Calculations -2
มุมมอง 243 ปีที่แล้ว
Module 5 AC Distribution Calculations -2
Module1 Lecture 7 Line Supports and Conductors
มุมมอง 273 ปีที่แล้ว
Module1 Lecture 7 Line Supports and Conductors
Module 1 Lecture 6 Numerical Problems on Sag
มุมมอง 353 ปีที่แล้ว
Module 1 Lecture 6 Numerical Problems on Sag
Module 1_ Lecture 4_Sag at Unequal Levels
มุมมอง 243 ปีที่แล้ว
Module 1_ Lecture 4_Sag at Unequal Levels
Module1 Lecture-3 Advantages of HV Transmission
มุมมอง 373 ปีที่แล้ว
Module1 Lecture-3 Advantages of HV Transmission
Module-1 Lecture-2 Structure of Electric Power System
มุมมอง 533 ปีที่แล้ว
Module-1 Lecture-2 Structure of Electric Power System
Voltage and Current Relations of a DC series and Shunt Motors (Numerical Problems Included)
มุมมอง 493 ปีที่แล้ว
Voltage and Current Relations of a DC series and Shunt Motors (Numerical Problems Included)
Module 3 CTFT Introduction and Properties of CTFT
มุมมอง 1033 ปีที่แล้ว
Module 3 CTFT Introduction and Properties of CTFT
Textbook name and author?
Simply a show. It is rare to see resolution using this method on the web. Congratulations my friend
Thank you so much🥺
Thank you Sir
Thanks for the video, sir. Could you please share the pdf file also?
Bad explanation
This is beautiful, quite excellent.. Thank you so much sir
You are most welcome
0.178
Thank you so much sir🙏
Most welcome
thanks
Wrong formula 2*10^-7lnd/r'
same question why he took 4^-7?
it's not wrong.. Or which question do you mean?
Sir please send the notes
mistake in 2nd que ...you considerd VL is 400 ..so answer of current circuit is wrong
IL = 10.13
Sir 2nd question m hmne pole ku ni likha sirf slot or conductor hi ku liya Z k equal...jbki 1st m hmne Z k equal pole bhi likha h slot or conductor k sath?
Voice atche se nhi ataa hein....make it clear please.
You skipped to upload one vedio about convolution integral. This vedio is subsequent part of it .
In 3 rd problem kd is already given in question kd=0.97 then why you find kd again using formula kw/kp and find it as 0.93 Actually what is the value of kd? Kindly please reply
Same doubt
sir please upload complete module 3 CTFT vedios
Thanku sir❤
Thank your sir
So nice of you
Hello sir! Can you please tell which book you're referring to for these questions?
Sir very nice explination
Thanks and welcome
Good video
Glad you enjoyed
Thank u so much sir
Most welcome
Good
Thanks
Sir can you mail your notes you have explained problems very accurately so
in 2nd q 440V hai ya 400 V h
yeah the correct answer is 10.137 A
The structure of the forced response is always a constant regardless of the problems?
the structure will change on the basis of Input/excitation signal.
hello sir, is it not 2.22 instead of 4.44 in the phase voltage formula?
carry on🥰
Excellent sir
Many many thanks
WHY DIVIDED BY 2
hi! i already asked this question again what if this problem have uniform loading?
Good! what if distributor is loaded uniformly and concentrated at the same time can u make video or u can simply answer by writing some equations this is my gmail muhammad.adil6923@gmail.com
sir pls provide your material sir
Tnx sir
Welcome
@@AnoopHALearn why by 2 sir