วีดีโอ

You can email me at suraj1993864@gmail.com But I am working professional so I will not be available always

30x2-163.33-24(x-1) 2 = 30x2-163.33-24(x2+1-2x) = 30x2-163.33-24x2-24+48x = (30-24) x2-(163.33+24) +48x = 6x2-187.33+48x

@mechpm thanks Sir I get it🙏

@adityakumarsahu140 welcome 😊

I have considered it already

Welcome😊

Samjhnae k liye to playlist h, aap first video se dekho

Thanks

Thank you so much

I can't understand?

Sorry to know that, maybe there is some glitch. Check later.

Thank you so much for your kind words

There are already more than 300 videos but I still upload if I am free from my job. Thanks brother.

Welcome😊

@@AzmeeraPavankalyan-u9l I just solved previous line -24(x-1) 2 =-24 x2+48x-24 Then you can simplify

@@vimalkumarnimmala5450 Thanks but I can't understand what are you referring to

I am using different textbooks for different topics

@@shivasangaran4993 Please watch carefully, I said negative both times. Bending moment in case of hogging will be negative always.

Noted. Tq Sir ​@@mechpm

Welcome 😊

What do you mean?

I don't know speak other languages 🤣 you better aware yourself before you did try to pinpoint someone 😂

Mai hindi me bhi video banauga But abhi appko kya nahi samajh aaya puch sakte h

I can upload after few days because I am busy with my job. But you can have a look here eng.libretexts.org/Bookshelves/Mechanical_Engineering/Introduction_to_Aerospace_Structures_and_Materials_(Alderliesten)/02%3A_Analysis_of_Statically_Determinate_Structures/07%3A_Deflection_of_Beams-_Geometric_Methods/7.02%3A_Derivation_of_the_Equation_of_the_Elastic_Curve_of_a_Beam

You can watch from first video in playlist to understand better. But here is the rule. A shear force that tends to move the left of the section upward or the right side of the section downward will be regarded as positive. Similarly, a shear force that has the tendency to move the left side of the section downward or the right side upward will be considered a negative shear force

@mechpm thank you ✨ sir

Welcome

@@Happy-hg6sm Unit of E is N/mm2 Unit of I is mm4 Unit of theta is radians but we don't write it Unit of Yc is mm So unit of EI ×theta is N/m2× mm4 = N-mm2 Unit of EIYc is N/mm2 × mm4 × mm = Nmm3

Welcome

Ok, I will enable download by evening

See b^3 = (x^3)/4 hence b= (x) ^3/3 /(4^1/3) b = x/4^(1/3) hence b= (1/4) ^(1/3) x b= . 63x I hope you could understand Here. 63 just comes from (1/4)^ 1/3 or . 25^.33

@mechpm thank you much sir.

Welcome

Thank you. They are scheduled and will be enabled automatically in few days

Thank you very much sir. Completed all 14n Nos Bending Stress videos. It makes sense. Kindly do number of portal frame analysis video sir.

I have already made videos on truss, frames, stress in beams etc, just watch on my channel

@@paryaas2222 Because in question the radius of gear wheel is asked. Usually driving gear is called pinion (we don't have to calculate radius of pinion) and driven gear is called gear. So we have calculated the radius of driven gear not of pinion

We are using Macaulay's method in this question where a fix procedure and rules are defined that's why we have to cut section in the last portion only. Otherwise you can use double integration method and you can calculate from any direction. Please watch first video in playlist for rules of Macaulay's method

Ok done friend

Banaya hua h 15-20 din me aa jayega

You are right but I have corrected same in next step.

@@aakashdhakar02468 because both shafts are replacement of each other so we are assuming that they will be used at same place for same power transmission or same torque transfer

Thanks for correction

There is 1 mistake in units Thanks for correction

@@mechpm but for the udl the units are correct I agree with it because Udl= wl²/8 The l² is where one should me careful

6.816 N/mm and 6816 N/m are same.

@@mechpm ✅️ noted sir

Mail me @ suraj1993864@gmail.com

You have to design it so you can assume anything but important thing is that your speed ratio should be 10 and you can consider 2.5 and 4 also or 3.33 and 3 or 1 and 10. If you have to design then you can get multiple designs for the same situation but only important thing is your design should meet all the requirements in the question.

Sir but 1 and 10 se ans toh nhi a rha kuch kuch teeths number less than 20 sa ja rha

To hamre pas 2 conditions h 1) speed ratio =10 2) teeth not less than 20 To jo answer dono ko satisfy karege wahi correct hoge. Isliye aap 2:5 or 2.5:4 or 3:3.33 or 4:2.5 similar aise conditions le sakte h aur for agar teeth less than 20 aaye to use reject karke baki ke sare answer correct hoge

@@mechpm yes 2.5:4 se a rha h

Yes, watch from first video in playlist so that you can understand better.

Welcome😊

@@DanishMansoori-en2pm MOI bd3/12 hota h but yaha me section modulus calculate hua hai jo ki MOI/Max distance of fiber from NA or Z= I/Y

I= bd3/12 and Y= d/2 So Z= I/Y = bd3/12/d/2 = bd2/6

Thank you 👍

I can't understand your language

@mechpm explain how the every answer is came it is confusing to understand

@@manorenjitham2771 all the distances are calculated from bottommost of I section so it's correct, if you want to calculate from other side then it would be 169.34-20/2 which will be same value.

@@mechpm Ok sir thank u❤

You can already see in the playlist of my channel